Solutions

experiment, we set out to determine the osmolarity of a potato. In order to do this, we placed potato pieces in seven different solutions of varying sucrose molarity. First, we weighed each potato piece to obtain the initial weight, shown in Figure 1. Then, we split the pieces vertically before placing them in the cubs containing the sucrose solutions. In each cup was a solution of sucrose with a molarity ranging from 0.0M to 0.6M. After placing the potatoes in the cups, we allowed them to…

If the solution is in an open container, Ψp is 0, so the water potential of the solution equals its solute potential. This equation will be used in the results section where we calculate the water potential of 3 plant species using the above methods. Variables The independent variables were the type of plant used (apple, potato, or yam) and the concentration of the sucrose solution. The overarching independent variable was the type of plant.…

solute B was about 278.4g/mol, which is close to given molar mass of octadecanol. Conclusion- This lab allowed us to determine the molar mass of the unknown solute B by finding the difference in freezing point temperature of the cyclohexanol and the solution with the unknown solute B. My experimental value for the molar mass was 278.4g/mol which means that solute B is octadecanol because its molar mass is 270g/mol. This means that my experimental…

they remained as solids. The test tube was then placed into a centrifuge and ran for thirty seconds. By doing so, the unsettled solid were forced to accumulate at the bottom of the test tube. This allowed for a more effective decantation of aqueous solution that contained component X onto the watch glass. Repetition of this extraction processes ensured that most of component X was separated from the sample. Once three washes were done, the aqueous…

Introduction: All living organisms require the process of osmosis in order to live. When there is a semi-permeable membrane separating differing parts of an aqueous solution, the fluid will flow from the section with the higher osmotic pressure to the section with the lower osmotic pressure (HammelSchlege2005). This happens because the solute molecules diffuse toward the fluid with a lower concentration and the solute molecules drag the water through which they diffuse (HammelSchlege2005). This…

region of water that has a lower potential through semipermeable membranes. There are three types of solutions, hypertonic, hypotonic, and isotonic. Hypertonic solutions have a higher concentration of solute while hypotonic solutions have a lower concentration of solute. Isotonic solutions have an equal concentration of solute. There is no net movement going in or going out of the isotonic solution or solute. The purpose of this experiment is demonstrate osmosis by weighing the dialysis bag to…

translocation of solutes. A solution that is hypertonic contains a higher concentration of solutes than water. Conversely, a solution that is hypotonic contains a higher concentration of water than solutes. An isotonic solution is one which has a relatively equal amount of water and solute. This is important in osmosis because the state of the solutions outside and inside the cell determine the movement of the water. For example, if the cell is placed in a hypertonic solution, the water will…

body, thus, it is using osmosis to get into our body. Putting rice in water and boiling is pretty much the same, the water will move into the rice, causing it become cooked or swell. Relating to this, tonicity is the ability to of an extracellular solution to make water move either inside…

0.20 g of adsorbent was added to 20 mL of 50 mg/L dye solution and Vortex at 150 rpm for various time intervals at 5, 10, 15, 30, 60, minutes. The above steps were repeated using dye concentrations of 100, 150 and 200 mg/L dye solutions. Adsorbent dosage is an important parameter because it determines the capacity of adsorbent for a given initial concentration of dye molecules. Then their % absorbance’s were calculated by spectrophotometer (λmax=410) and thus amount adsorbed were calculated.…

variable was the zebrafish embryos after they were exposed to the C4. In addition, 2 controls were set up, containing a ocean/embryo solution, and the control was used to compare the effects between the solutions containing C4 and the solutions containing no C4. Furthermore, 2 controls were used because 2 experiments were conducted one containing a larger solution of C4 and the other containing a trace amount of C4. The hypothesis stated that if the zebrafish embryos were exposed to…