Future of Hydrogen Fuel Cells Essay

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The Future of Hydrogen Fuel Cells

The present global economy is nearly entirely dependent on petroleum and crude oil imports from the Middle East. Where the current situation stands now, oil prices will continue to skyrocket and the environmental impact will continue becoming greater if no form of alternative energy is implemented to a greater extent within the coming years. However, to this effect, the industrial cost of producing such forms of alternative energy is in itself primarily composed of coal and petroleum. In this light, I will investigate the practicality of hydrogen fuel cells based upon hydrogen consumption and exploitation. Hydrogen holds enormous promise for the future regarding alternative energy sources. To this
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The negatively charged anode splits hydrogen atoms into separate ions. The electrons flow to complete a circuit and once utilized, continue on to return to the fuel cell and recombine with hydrogen to allow the latter to bond with oxygen molecules to form water as the single waste element (http://www.fctec.com/fctec_types_pem.asp) (the basic diagram is found at the aforementioned site). However, what elements are required to make this system equally or more efficient than gasoline engines?

The energy produced by a hydrogen fuel cell is produced by the combination of atoms and the decrease in volume of gases. In this, it is crucial to understand the entropy of one mole of hydrogen, oxygen, and water, in this example, at 298 Kelvins and one atm, which are 130.68 J/K, 205.14 J/K, and 69.91 J/K respectively. Entropy here is important to measure because it represents the energy which may be lost due to a quantity of disorder, in this case measured by the amount of heat added per unit of temperature. Because the chemical equation for water may be rearranged as H2+.5O2=H20, the entropy value of one mole for water must be halved: 205.14/2=102.57 J/K. following this, the work performed by the system to combine these two elements is given by W=P(change in)V. Using 1 atm=101.3x10^3 Pascals, the change in V given by: (total number of moles in reactants)(m^3 occupied by one mole)(final temperature/273
Kelvins). Thus the equation: W=(101.3x10^3 Pa)(1.5 mols

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