To investigate which food dye color were present in the low-calorie Gatorade, a small sample of the Gatorade was inserted into a UV-Vis spectrometer to examine which color was being absorbed and reflected. There were two peaks, where the two colors were being the most absorbed. Once the absorbance was figured out, the food dyes that is needed in the Gatorade was present by using the color spectrum and the wavelength. These colors were green (514 nm) and orange (629.6 nm). Then the emitting colors can be solved. The colors that were emitted were red and blue. So, the food color dyes that was needed was FD&C Blue #1 and FD&C Red #40.
To determine the concentration of the red and blue dye, a concentration curve for each dye was created by using …show more content…
It was changed into a linear line graph. From the graph an equation was created, y = mx + b. The equation, y = mx + b was the same thing as A=Ɛℓc. The equation for the blue dye is .187 abs. = 102739x + 0 and the equations for the red dye is .244 abs. = 30260x + 0. These values were inputted into the beer’s law, A=Ɛℓc (A = y, Ɛℓ= M, c= x). To find concentration, beer’s law was rearranged to AƐℓ=c. The final concentration of the red dye was 1.82x10-6 and the blue dye was 8.06x10-6.
Let alone, the final concentration was found, then the final volume can be found. The equation M1V1=M2V2 must be change into (M_1 V_1)/M_2 =V_2. The final volume needed for the red dye was 5.00 mL, the blue dye 3.60 mL, and the rest was filled up with deionized water up to 25 mL in a volumetric flask. Only one trial was done. To measure the accuracy of the created solution, the solution was put in a UV-Vis spectrometer. Then the absorbance curve of the created solution was compared to the absorbance curve of the Gatorade.
Discussion/Results
Food dyes that was presented in the low-calorie Gatorade was FD&C Blue #1 and FD&C Red #40. The UV-Vis spectrometer showed that wavelengths 514 nm and 629.6 nm had absorbance peak. Using a color spectrum, the wavelengths corresponds to green and orange. The colors that were emitted were red and blue. Figure 1: The absorbance curve of the low-calorie
To determine the concentration of the red and blue dye, a concentration curve for each dye was created by using …show more content…
It was changed into a linear line graph. From the graph an equation was created, y = mx + b. The equation, y = mx + b was the same thing as A=Ɛℓc. The equation for the blue dye is .187 abs. = 102739x + 0 and the equations for the red dye is .244 abs. = 30260x + 0. These values were inputted into the beer’s law, A=Ɛℓc (A = y, Ɛℓ= M, c= x). To find concentration, beer’s law was rearranged to AƐℓ=c. The final concentration of the red dye was 1.82x10-6 and the blue dye was 8.06x10-6.
Let alone, the final concentration was found, then the final volume can be found. The equation M1V1=M2V2 must be change into (M_1 V_1)/M_2 =V_2. The final volume needed for the red dye was 5.00 mL, the blue dye 3.60 mL, and the rest was filled up with deionized water up to 25 mL in a volumetric flask. Only one trial was done. To measure the accuracy of the created solution, the solution was put in a UV-Vis spectrometer. Then the absorbance curve of the created solution was compared to the absorbance curve of the Gatorade.
Discussion/Results
Food dyes that was presented in the low-calorie Gatorade was FD&C Blue #1 and FD&C Red #40. The UV-Vis spectrometer showed that wavelengths 514 nm and 629.6 nm had absorbance peak. Using a color spectrum, the wavelengths corresponds to green and orange. The colors that were emitted were red and blue. Figure 1: The absorbance curve of the low-calorie