A Experiment On Solubility Test Essay

1305 Words Oct 15th, 2015 6 Pages
Discussion For the first part of the experiment, a solubility test was conducted on all compounds. Because they were all ionic, every known compound naturally dissolved in water, and conducted electricity. As the next determining factor in the process to identify the unknown substance, the compounds were tested in acetone. As seen in table 2, only one compound, Ca(NO3)2 was found to be soluble in this solvent. Because the unknown solid was insoluble in acetone, Ca(NO3)2 was then eliminated as a possible inorganic compound. The flame test did not help to eliminate any possibilities for the unknown, because each flame turned orange after being dipped in the different solutions. However, as a final qualitative test, the pH test further narrowed down the identity of the unknown because almost half of the given substances in table 2 (NaOH, Na2CO3, NaCH3CO2, CaCl2, and NaCl) were either too basic or slightly too acidic as compared to the remaining compounds. From the few remaining, observed qualities and physical properties of the compounds were compared from the observations section, and the results for the unknown compound implied that the identity was either NaNO3 or MgSO4. The gravimetric analysis further suggested that the unknown compound was MgSO4. BaNO3 was chosen as the solvent because it is known to form a precipitate with Sulfate (BaSO4), but not with NaNO3. The written equation for this reaction is BaNO3 (aq) + MgSO4 (s)  BaSO4 (s) + MgNO3 (aq). The results of the…

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