Chemical Formula Lab Report

1304 Words 6 Pages
The purpose of this lab is to calculate the chemical formula of a hydrate compound made up of copper, chlorine, and water molecules by using the law of definite proportions. The water of hydration of the copper chloride hydrate sample will be determined as well as the mass of copper and chlorine through a chemical reaction. The results will be used to calculate the moles of copper and chlorine and then the empirical formula of the compound.

Techniques used:

In this experiment, different techniques will be used to collect the required data, such as taking the mass of the hydrate sample on a digital balance, assembling a ring stand, properly setting up a Bunsen burner and safely using it to heat the hydrate sample, properly setting up a
…show more content…
The atomic weight of an element is found on the periodic table. The atomic weight of an element is determined by taking the masses of the isotopes and the natural abundance of the isotope and multiplying. One mole of a compound equals the molecular weight. The molecular weight of is 18.02 amu or g/mol. Hydrogen has an atomic mass of 1.01 amu or g/mol and since there are two atoms of hydrogen in water, the atomic mass is 2.02 amu or g/mol. Oxygen had an atomic mass of 16.00 amu or g/mol, and there is only one oxygen atom in water, so its atomic mass is 16.00 amu or g/mol. The molecular weight of water is (2.02 amu or g/mol + 16.00 amu or g/mol) = 18.02 amu or g/mol. The molecular weight of is 233.39 amu or g/mol. Barium has an atomic mass of 137.33 amu or g/mol and there is only one atom of barium, so the atomic mass of barium in barium sulfate is 137.33 amu or g/mol. Sulfur has an atomic mass of 32.06 amu or g/mol and there is only one atom of sulfur so the atomic mass of sulfur in barium sulfate is 32.06 amu or g/mol. Oxygen has an atomic mass of 16.00 amu or g/mol and there are four atoms of oxygen in barium sulfate, so the atomic mass of oxygen in barium sulfate is 64.00 amu or g/mol. The molecular weight of is (137.33 amu or g/mol + 32.06 amu or g/mol + 64.00 amu or g/mol) = 233.39 amu or

Related Documents