Use LEFT and RIGHT arrow keys to navigate between flashcards;
Use UP and DOWN arrow keys to flip the card;
H to show hint;
A reads text to speech;
14 Cards in this Set
- Front
- Back
- 3rd side (hint)
|
Prime factors |
Factors related to x-ray emission that are under the direct control of the radiographer; milliamperage (mAs), kilovoltage (kVp), and distance (SID) |
|
|
|
X-ray quantity |
A measure of the number of X-ray photons in the useful beam Is directly affected by mAs, kvp, distance, filtration |
|
|
|
X-ray quality |
A measurement of the penetrating ability of the X-ray beam Is directly affected by kilovoltage and filtration |
|
|
|
Half value layer |
X-ray quality is numerically represented by the __ (HVL)X-ray quality is numerically represented by the __This layer of an x-ray beam is that thickness of absorbing material needed to reduce the X-ray intensity (quantity) to half its original value This layer of an x-ray beam is that thickness of absorbing material needed to reduce the X-ray intensity (quantity) to half its original value |
|
|
|
Exposure index (IE) |
With a digital imaging system, exposure to the IR must be assessed by reviewing a Numerical exposure value known as the ____ |
|
|
|
Increase |
As mAs increase, x-ray exposure will ____ proportionally |
|
|
|
Kilovoltage (kVp) |
Controls both the quantity and quality of the X-ray beam.
Increasing this on an X-ray control panel will cause an increase in speed and energy of the electrons applied across the x-ray tube. |
|
|
|
Penetrability |
The ability of the X-ray to pass through structures and tissues |
|
|
|
4 |
If kvp is doubled, the amount of X-ray photons increases approximately ___ times |
|
|
|
The square of the ratio of the change in kvp |
What is the X-ray quantity approximately proportional to |
|
|
|
Contrast |
Kvp is the primary controller of the differences in density / IR exposure. This is known as ___ |
|
|
|
15% rule |
An increase in kvp by 15% that causes a doubling and exposure, and vice versa |
|
|
|
Exposure maintenance formula |
A direct square law; mAs must increase when distance increases, and vice-versa, in order to maintain image receptor exposure |
|
|
|
Direct square law |
A direct relationship is necessary to compensate for the changes in intensity and IR exposure |
|
