Precipitation Reactions Lab Report

Improved Essays
Conclusion: The the precipitation reactions lab eight out of the fourteen occurring reactions were precipitates. A precipitate means that a solid substance was formed or a substance that is not aqueous was formed. The reactions that did not form a precipitate were DNR, which means that they did not react. At station one barium chloride and potassium nitrate did not react but barium chloride and silver nitrate reacted to form barium nitrate and silver chloride. The precipitate at station one was silver chloride. Both reactions at station two did not react. Station three had a reaction occur between sodium carbonate and calcium sulfate forming sodium sulfate and calcium carbonate. The precipitate was calcium carbonate. Station four formed a …show more content…
The solubility rules were used to determine which reactant was aqueous and which one was a solid. The solid is the precipitate formed in the reaction. The formation of the precipitate indicates that a chemical reaction occurred. If no precipitate formed the reaction would be labeled with DNR, which stands for does not react. The solubility rules states which elements are soluble or insoluble, including the exceptions for each rule. For example at station one, barium chloride reacted with silver nitrate yielding to barium nitrate and silver chloride. Barium nitrate is aqueous because all nitrates are soluble. Silver chloride is the precipitate because all chlorides expect silver and a few others are soluble, since silver is an exception silver chloride is insoluble. To determine which reactant out of the chemical reactions the solubility rules provided the guideline necessary to figure out which reactant is the precipitate. The reactions in this equation were all of the same type of chemical reaction. They were double replacement reactions which is the two products are interchanged to formed two new compounds on the reactant side. Intermolecular forces have heavy influence over solubility. Intermolecular forces are between molecules and are weak forces of attraction. There are four intermolecular forces including hydrogen bonding, dipole-dipole forces, dipole-induced dipole forces, and london dispersion forces. Hydrogen bonding is the strongest and occurs when one hydrogen molecule is attracted to another molecule. Next is dipole- dipole forces which occurs between polar molecules. After that is dipole- induced dipole, it is weaker than dipole-dipole because its occurs between a polar and a nonpolar molecule. The weakest intermolecular force is london dispersion forces because it is only temporary

Related Documents

  • Improved Essays

    6.03 Calorimetry Lab

    • 1044 Words
    • 5 Pages

    To test the solution for Pb2+ and Ag+ ions, add 8 drops of 6 M HCl solution to Test Tube 1 and stir the mixture. If a white precipitate forms, then Ag+ and/or Pb2+. Centrifuge the test tube and add one more drop of 6 M HCl. If more precipitate does form, continue adding HCl one drop at a time until the supernatant (the liquid) remains…

    • 1044 Words
    • 5 Pages
    Improved Essays
  • Improved Essays

    The purpose of this lab was to determine the formula of copper chloride hydrate by dehydration through heating, rehydration through adding water back in, the reaction of aluminum with the copper chloride hydrate to produce solid copper, and the weight of this copper. To accomplish this, a petri dish was weighed and 1.01 g of copper chloride hydrate was added to the dish. The solid salt crystals were broken up to make sure that all of the hydrate would be heated the same. Next, the petri dish and hydrate were heated upon a hot plate for roughly 15 minutes, until all the salt crystals were brown instead of blue. This indicated that all of the water had been burned out of the hydrate, leaving dehydrated copper chloride.…

    • 494 Words
    • 2 Pages
    Improved Essays
  • Improved Essays

    There is a solubility table that is able to help determine the solutions solubility. When there is a mixture with two solutions the result solution of that mixture would either be a soluble reaction or an insoluble reaction. The solubility or the insolubility of the reaction can be determined by the precipitate. In lecture ionic equation examples were shown which helped to do the Pre-Lab questions and the Pre-Lab questions were helpful in seeing which out of the 36 mixtures or equations are soluble and which ones are insoluble. With the help of the Pre-Lab question that were done with full understanding it was simple and very easy to determine the results of the nine unknown solutions added together.…

    • 791 Words
    • 4 Pages
    Improved Essays
  • Improved Essays

    Unknown Lab Report

    • 750 Words
    • 3 Pages

    Materials. Numerous substances in the experiment were used. The most frequently used was the unknown due to the need to test its physical and chemical qualities. When a solution of the unknown was made, 1.000 g of the unknown and 1.0 mL of water was used to make it. To test for the possible ions, 1.0 mL of silver nitrate and 1.0 mL of nitric acid were used for the ion test.…

    • 750 Words
    • 3 Pages
    Improved Essays
  • Improved Essays

    Unknown Compounds

    • 695 Words
    • 3 Pages

    When hydrochloric acid was added to the unknown and known solutions, both resulted in no reaction. This also occurred when potassium hydroxide was added to both of the solutions. Barium chloride was then added to the two solutions, which resulted in a cloudy white precipitate from both of the solutions. A cloudy white precipitate also formed when calcium nitrate and ammonium nitrate were added to both the unknown and known solutions. These reactivity tests were conducted in order to establish how the unknown compound would react with acids, bases, and salts.…

    • 695 Words
    • 3 Pages
    Improved Essays
  • Great Essays

    Also on the Data Sheet it states that NaCl is dissolvable in water. The Data sheet supports our results. Both unknown and known compounds had similar amounts of AgCl on the filtration paper. From the results I can conclude that the unknown NaCl and the known NaCl produces the same product, AgCl, when reacting with AgNO3. The AgCl forms because Cl reacts with Ag.…

    • 931 Words
    • 4 Pages
    Great Essays
  • Improved Essays

    Unknown Compounds

    • 816 Words
    • 4 Pages

    For the reaction that formed the precipitate, using stoichiometry, the masses were equal between the unknown beginning, the hypothesized beginning, the unknown ending, and the hypothesized ending, once again confirming our…

    • 816 Words
    • 4 Pages
    Improved Essays
  • Decent Essays

    Following the Ways of the Scientific Method The scientists solved the Elkhorn Coral mystery using the scientific method by following each step of the method to come to a conclusion as to what is killing the coral. The followed the steps precisely so that would not make any errors during their trials. They started with the first step of the scientific method, making an observation.…

    • 417 Words
    • 2 Pages
    Decent Essays
  • Improved Essays

    Unknown Salt Investigation

    • 1329 Words
    • 6 Pages

    Theory: In this experiment the unknown salt was precipitated as silver chloride through the addition of silver nitrate. This was done so that the chlorine ions could be separated from the salt to determine the overall percent content. Silver nitrate is used as the precipitating agent because it is highly…

    • 1329 Words
    • 6 Pages
    Improved Essays
  • Decent Essays

    The purpose of this lab was to determine if a change in mass occurs during a chemical reaction in a closed system. To conduct this experiment, the mass of the test tube, rubber cover, and other materials must be measured. To prevent the test tube from rolling off of the balance, a plastic cup was used to hold it in place, but the group had to remember to zero out the cup on the balance so the cup’s mass will not affect the masses of the objects the group was trying to measure. During this investigation, it was determined that there is a 0% change in mass after a chemical change in a closed system, because the mass of the copper and sulfur before heating did not change after being heated. Although the substances had changed in appearance and could no longer be considered…

    • 478 Words
    • 2 Pages
    Decent Essays
  • Improved Essays

    The intermolecular forces present in the molecules in Step (1a) include only dispersion forces, because each of the compounds are non-polar. In Step (1b), there are dispersion forces, hydrogen bonding, and dipole-dipole forces. Dispersion forces occur in all compounds, hydrogen bonding occurs between the oxygen and hydrogen atoms within each of the compounds, and there is also a dipole movement between the oxygen and hydrogen atoms. There is a correlation between IMFs and volatilities, as the stronger intermolecular forces tend to evaporate the slowest, resulting in a lower vapor pressure. 1c.…

    • 865 Words
    • 4 Pages
    Improved Essays
  • Decent Essays

    In this lab, we carried out a variety of reactions using different chemicals and metals. A chemical reaction is when the chemical state of the substance you are testing rearranges its ionic and molecular structure. One of the reactions we experienced was single replacement, this consists of one ion switching places with another ion to form a new compound. Another reaction we saw was double replacement. In this reaction, two compounds ions are switched to form two new compounds.…

    • 177 Words
    • 1 Pages
    Decent Essays
  • Improved Essays

    This is shown in the balanced chemical equation by the products of water and the solid copper chloride. The observation of the liquid turning clear represents the water and seeing the particles represents the precipitate. The yield of copper chloride is 1.49 grams. This demonstrates the transformation of the copper hydroxide being converted into regular copper oxide and with the rest of the mass becoming water. The limiting reactant was the copper oxide and the excess was hydrochloric acid.…

    • 1243 Words
    • 5 Pages
    Improved Essays
  • Improved Essays

    In this experiment, two cations in an unknown solution were found using qualitative analysis. For Part A, the solution was to contain either silver or lead, while in Part B, the solution that was set on the side form Part A was identified to contain either calcium or barium. Part C explored a different method through the use of cation flame tests to observe colored flames from six metal chloride solutions. In Part A, the initial step was to add HCl to the unknown sample.…

    • 885 Words
    • 4 Pages
    Improved Essays
  • Great Essays

    When calculating the quantitative solubility of the unknown compound in water, the amount of water that was measured in the hydrated cylinder and poured into the flask could have been greater than expected. This is more likely than less water being used because more solute was needed to saturate the solution than expected. Another error that could have occurred during this part of the experiment was that too much of the unknown compound was added accidently to the solution than could dissolve. Most of the error in this lab occurred during the quantitative analysis since all of the percent yields of the precipitate were over 100%. This miscalculation could have been caused by the beakers not being washed out thoroughly between each reaction or by the mass of KCl measured on the electronic scale being greater than exactly 0.5 grams.…

    • 1428 Words
    • 6 Pages
    Great Essays