This report will discuss multiple experiments regarding chemical equilibrium. Chemical
equilibrium is when both reactants and products are both equal to each other. If one is not equal
to each other, than the direction of shift will move to where equilibrium has been tampered with.
Throughout all the labs, we observed that with different chemicals we have different directions
of shift. From acids to bases, we see that direction of shift can vary which leads to different
conclusions. We also investigated the effect of adding or removing a stress and temperature. We
discovered that all weak acids partially ionize in a water solution.
The materials we gathered were used by all members of our group. We used two reagent
trays for …show more content…
A Bunsen burner was used to heat the beaker and we were able
to measure it by using a thermometer. We also used ice to lower the temperature of the water. In
some cases, we needed to measure the pH by using the strip and analyzing by comparing it to the
pH chart. The vinegar, bromothymol, sodium hydroxide and Lugol was shared throughout the
classroom by other classmates.
Before the labs began, we initiated by labeling the two trays. The four-well tray reagent
tray was labeled with tea, starch, MOM and 0.1 M Acetic Acid. The three-well reagent tray was
labeled in number from one to three. We then dedicated a pipet for each tray as well as
distributing other liquids to other trays. The first lab focused on changing the concentration of
Hydrogen ions in a tea solution. As this experiment stressed on chemical equilibrium, it also
emphasized on the direction of shift in equilibrium. We first added five drops of tea in all three
wells of the three-well reagent. No further instruction was given to us on well two because it
would serve as a control in this experiment so that way we could compare our results. We then
added two drops of 0.1 M NaOH into well one. After this, we recorded our shift in equilibrium …show more content…
Then, we had to convert the pH level into exponential notation. From this, we were able to
write the equation for the ionization of the 0.1 M acetic acid (CH3COOH). Then, we had to solve
the equation by inserting the exponential notations of the hydronium ions, the acetate ions and
the acetic acid into the equation.
Throughout our experiments, our data was either recorded in our tables or on the packet
given to us during these labs. In our first lab, our data was recorded on both our data table and
the packet. The data table shows the stress that we added to the solution. From the stress, we see
that this was able to produce a color change. Ultimately, this caused a direction of shift. By
adding the 0.1 M acetic acid, we changed the color from brown into tan. This stress also caused
the direction to shift to the right, which would balance out the reactants and products. The
addition of the 0.1 M NaOH, however, was the exact opposite. The stress caused the solution to
change yellow. It also caused the direction of shift to move to the left instead of the right.
According to the equation, we were able to conclude that “tea+H” has a brown color and “teaH”
has a tan
equilibrium is when both reactants and products are both equal to each other. If one is not equal
to each other, than the direction of shift will move to where equilibrium has been tampered with.
Throughout all the labs, we observed that with different chemicals we have different directions
of shift. From acids to bases, we see that direction of shift can vary which leads to different
conclusions. We also investigated the effect of adding or removing a stress and temperature. We
discovered that all weak acids partially ionize in a water solution.
The materials we gathered were used by all members of our group. We used two reagent
trays for …show more content…
A Bunsen burner was used to heat the beaker and we were able
to measure it by using a thermometer. We also used ice to lower the temperature of the water. In
some cases, we needed to measure the pH by using the strip and analyzing by comparing it to the
pH chart. The vinegar, bromothymol, sodium hydroxide and Lugol was shared throughout the
classroom by other classmates.
Before the labs began, we initiated by labeling the two trays. The four-well tray reagent
tray was labeled with tea, starch, MOM and 0.1 M Acetic Acid. The three-well reagent tray was
labeled in number from one to three. We then dedicated a pipet for each tray as well as
distributing other liquids to other trays. The first lab focused on changing the concentration of
Hydrogen ions in a tea solution. As this experiment stressed on chemical equilibrium, it also
emphasized on the direction of shift in equilibrium. We first added five drops of tea in all three
wells of the three-well reagent. No further instruction was given to us on well two because it
would serve as a control in this experiment so that way we could compare our results. We then
added two drops of 0.1 M NaOH into well one. After this, we recorded our shift in equilibrium …show more content…
Then, we had to convert the pH level into exponential notation. From this, we were able to
write the equation for the ionization of the 0.1 M acetic acid (CH3COOH). Then, we had to solve
the equation by inserting the exponential notations of the hydronium ions, the acetate ions and
the acetic acid into the equation.
Throughout our experiments, our data was either recorded in our tables or on the packet
given to us during these labs. In our first lab, our data was recorded on both our data table and
the packet. The data table shows the stress that we added to the solution. From the stress, we see
that this was able to produce a color change. Ultimately, this caused a direction of shift. By
adding the 0.1 M acetic acid, we changed the color from brown into tan. This stress also caused
the direction to shift to the right, which would balance out the reactants and products. The
addition of the 0.1 M NaOH, however, was the exact opposite. The stress caused the solution to
change yellow. It also caused the direction of shift to move to the left instead of the right.
According to the equation, we were able to conclude that “tea+H” has a brown color and “teaH”
has a tan