# Essay on identification of unknown organic compound

992 Words Oct 29th, 2013 4 Pages
Identification of Unknown Organic Compound by Melting Point (M.P), Boiling Point (B.P) and Infrared Spectroscopy

Methods and Background The main objective of this lab is to identify the given unknown organic compounds with various methods. Identification of an unknown compound is important to perform through the process of melting point (M.P), boiling point (B.P) and Infrared spectroscopy (I.R). Index of Hydrogen deficiency (IHD) and elemental analysis makes an experiment more efficient in determination of unknown compound. The color, odor, melting point and boiling point determines the physical state and properties of a compound. It also determines its volatility in respect to temperature. The functional group of a compound can
Student group
Unknown
Carbon (c)
Hydrogen (H)
Oxygen (O)
Nitrogen (N)
Molar Mass (g/mol)
1
A (solid)
68.85%
4.95%
26.20%
0%
122.037

B (liquid)
69.72%
11.70%
18.58%
0%
86.073
Calculation for empirical formula: For Solid For Liquid
Step 1. C=68.85/12 g/mol= 5.737 step 1 C= 69.72/12= 5.81
H=4.95/1 g/mol = 4.95 H= 11.70/1 = 11.70
O= 26.20/16g/mol = 1.637 O= 18.58/16 = 1.16
Step 2. Dividing by small value Step 2 C = 5.737/1.637 = 3.504 C=5.81/1.16 = 5.00 H = 4.95/ 1.637 = 3.023 H=11.70/1.16 = 10.08 O= 1.637/1.637 =1 O= 1.16/1.16 = 1
Step 3. Multiplying by integer Step 3 C= 3.5*2 = 7 C=5 H= 3.02* 2 = 6 H= 10 O= 1*2 = 2 O= 1 The empirical value for solid is C7H6O2 The empirical value for Liquid is C5H10O
Index of Hydrogen deficiency: It determines the saturation of a compound. (Possible combination of double bond, triple bonds and ring.) For solid IHD=5 For Liquid IHD = 1 Possible combination Possible combination 2 triple bond + 1 ring 1 ring or 1 double bond 2 triple bond +1 double bond 5 double bond 4 double bond +1 ring 3 double bond +2 ring 2 double bond +2 rings 1 double bond + 4 rings

Fourier Transform Infrared Spectroscopy The following were the three

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