Introduction
The goal of this experiment was to determine atomic weight of Kandimonium and the relative number of M&M’s in Kandimonium. Kandimonim is composed of three isotopes: Skittles, M&M’s, and Sweet Tarts, and the ratio of Sweet Tarts to Skittles is 27:18. The relative number of M&M’s and the atomic mass were determined by weighing each of the different Isotopes and calculating their average masses for further calculations.
Calculations
The following calculations were used to determine the atomic weight of Kandimonium:
Kandimonium Jar #10 Total Mass: 80.0916 g
Average Mass of Isotope T (Sweet Tarts): 1.156 g
Average Mass of Isotope S (Skittles): 1.042 g
Average Mass of Isotope M (M&M’s): 0.848 g
These average masses were calculated …show more content…
This was accomplished by precipitating three different solutions (Solution A, B, and C) with silver nitrate to create a compound of silver and the unknown element. Given that 0.01 moles of AgX were present, the grams of silver and the unknown element were calculated. Using the periodic table, the unknown elements were able to be determined.
Calculations
Given: 0.01 mol AgX
1 mol Ag = 107.868g
Solution A: (mol of Ag)(molar mass of Ag) + (mol of A)(unknown) = mass of salt
.01 mol Ag(107.868 g) + .01 mol(A) = 1.74g
A= 66.132 g
Solution B: (mol of Ag)(molar mass of Ag) + (mol of B)(unknown) = mass of salt
.01 mol Ag(107.868 g) + .01 mol(B) = 2.43g
B= 135.132 g
Solution C: (mol of Ag)(molar mass of Ag) + (mol of C)(unknown) = mass of
The goal of this experiment was to determine atomic weight of Kandimonium and the relative number of M&M’s in Kandimonium. Kandimonim is composed of three isotopes: Skittles, M&M’s, and Sweet Tarts, and the ratio of Sweet Tarts to Skittles is 27:18. The relative number of M&M’s and the atomic mass were determined by weighing each of the different Isotopes and calculating their average masses for further calculations.
Calculations
The following calculations were used to determine the atomic weight of Kandimonium:
Kandimonium Jar #10 Total Mass: 80.0916 g
Average Mass of Isotope T (Sweet Tarts): 1.156 g
Average Mass of Isotope S (Skittles): 1.042 g
Average Mass of Isotope M (M&M’s): 0.848 g
These average masses were calculated …show more content…
This was accomplished by precipitating three different solutions (Solution A, B, and C) with silver nitrate to create a compound of silver and the unknown element. Given that 0.01 moles of AgX were present, the grams of silver and the unknown element were calculated. Using the periodic table, the unknown elements were able to be determined.
Calculations
Given: 0.01 mol AgX
1 mol Ag = 107.868g
Solution A: (mol of Ag)(molar mass of Ag) + (mol of A)(unknown) = mass of salt
.01 mol Ag(107.868 g) + .01 mol(A) = 1.74g
A= 66.132 g
Solution B: (mol of Ag)(molar mass of Ag) + (mol of B)(unknown) = mass of salt
.01 mol Ag(107.868 g) + .01 mol(B) = 2.43g
B= 135.132 g
Solution C: (mol of Ag)(molar mass of Ag) + (mol of C)(unknown) = mass of