Equation of trendline 2 calculation: m= rise/run = 25/45 = 0.5 c= 17.6 y= 0.5x +17.6
Point of intersection:
Equate both trendlines to find point of intersection
0.8x + 5.9 = 0.5x + 17.6 x= 39
Since x=39, x2= 9 as x2 represents x in descending order.
R2 for trendline 1 = 0.98
Correlation coefficient for trendline 1= 0.96
R2 for trendline 2 = 0.98
Correlation coefficient for trendline 2= -0.99
Ratio calculation from graph:
39.0 mL (± 0.3 mL) / 9.0 mL (± 0.3 mL)
= 4.3 (± 4.1%)
= 4.3 (± 0.2)
Hence, the ratio is 39:9 or 4.3 (± 0.2)
Qualitative and processed data from graph:
The ratio calculated from the graph is the volume of bleach to the volume of unknown. There are two trend lines present due to the two quantities present and the varying amounts of each.
The point of intersection of the two trend lines determines the ratio of volumes (bleach to unknown).
From the graph, the ratio is 39:9 or 4.3 (± 0.2). This matches with the qualitative data, as the solution was warm when settled after two minutes, was bubbling, and released a strong odour after one minute.
The X (two X axes) and Y axis …show more content…
To identify the correct ratio of reaction, the unknown solution and bleach were mixed in varying amounts. Then, the temperatures were recorded for each trial done. Since the amount before the reaction (reactants) is more than the amount after the reaction, the reaction is exothermic as it releases heat. This explains the increase in temperature from 21.2 (°C ± 0.1 °C ) to other respective temperatures. The volume of the solutions are supposed to be constant for one to calculate molar ratios. Hence, a concentration of 0.50 M is kept the same for each reactant. The temperature change is therefore proportional to the amount of reactants that are