# Egg Drop Essay

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The Egg-Drop Device Process The process of dropping an egg is more complex than a normal person would believe. The egg-dropping process requires knowledge of history, engineering, and mathematics and physics. To fully understand how an egg drops, the knowledge of the history of physics, the engineering behind a device, and the mathematics and physics of free-fall is needed.
Physics originates in its classical form in Ancient Greece. Thales was the first physicist. The theories Thales made gave the discipline of physics its name. Thales believes that the world, although made of many materials, was really made of only one element: water. The interaction of water between the phases of solid, liquid, and gas gives materials different properties.
Copernicus discovers that the Sun was the center of the solar system, not the Earth. Kepler develops the three laws of planetary motion. Galileo discovers that the natural state of an object is either at rest or moving with a constant speed, for as long as no unbalanced forces are acting on the object. Galileo reasons that if friction and other forces were balanced, an object would continue along at constant speed. Galileo understands the concept of acceleration and motion of objects acted upon by …show more content…
The conceptual side of egg-dropping requires knowledge of free-fall physics. The most basic formula to know is v = d/t, or velocity is equal to the distance divided by the elapsed time. In the test simulation, the device is dropped at a distance of 75 feet or 22.86 meters, and the average elapsed time is 2.223 seconds. Using these two values, substituted into the formula, the velocity is determined to be 10.2834 meters per second. Velocity is a vector quantity with direction and magnitude. In the case of the device, the direction is directly down or 90 degrees below the horizontal and the magnitude is 10.2834. After solving for velocity, one can get the acceleration of the device as it drops from 75 feet. To calculate acceleration, the formula a = v / t, or in other words, acceleration is equal to velocity divided by the elapsed time. Substituting in the values, acceleration roughly equals 4.6259 m/s^2. With the acceleration, the force of the falling object is calculable using the formula f = ma, or force is equal to the mass times the acceleration. When the values are substituted in, the formula determines the force to be 5.3105

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