We find the magnetic fields B1, B2 and B3:

퐵1=퐵2= 푢0 푖 = 푢0 푖 = 4∗3.14×10−7 ∗(3.65) =ퟒퟐ.ퟔퟔퟎ풖푻 2휋푟 2휋( 2푎) 2 ∗ 3.14 ∗( 2(0.0121))

퐵3= 푢0 푖 = 푢0 푖 = 4∗3.14×10−7 ∗(3.65) =ퟐퟎ.ퟏퟏퟎ풖푻 2휋푟 2휋(3푎) 2 ∗ 3.14 ∗(3∗(0.0121))

The x components of the B1 and B2 cancel each other; therefore the net magnetic field will be downward and we have (the negative sign is because the direction is downward):

퐵=− 퐵1cos 45 + 퐵2cos 45 +퐵3 퐵=−42.660푐표푠45 +42.660푐표푠45 +20.110

푩 = −ퟖퟎ. ퟒ 흁푻

b) Determine the magnitude and direction of the magnetic field at point B.

According to the right-hand rule, the direction of the magnetic fields of the 3 wires are shown: B1 and B2 are equal in magnitude but in opposite direction, so they will cancel each other. Therefore the net magnetic field here is B3 (Its is negative because it is downward):

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According to the right-hand rule, the direction of the magnetic fields of the 3 wires are shown:

We find the magnetic fields B1, B2 and