• Shuffle
    Toggle On
    Toggle Off
  • Alphabetize
    Toggle On
    Toggle Off
  • Front First
    Toggle On
    Toggle Off
  • Both Sides
    Toggle On
    Toggle Off
  • Read
    Toggle On
    Toggle Off
Reading...
Front

Card Range To Study

through

image

Play button

image

Play button

image

Progress

1/43

Click to flip

Use LEFT and RIGHT arrow keys to navigate between flashcards;

Use UP and DOWN arrow keys to flip the card;

H to show hint;

A reads text to speech;

43 Cards in this Set

  • Front
  • Back
Light has characteristics of what?
an electromagnetic wave and a particle
How tall must a flat mirror hanging on the wall be in order for a person to see their feet and the top of their head at the same time?
Half the Height of the Person
What would you see if a small mirror were hung at your belt level?
Your knees
An observer facing a mirror observers a light source that is in front of the mirror. Where does the observer percieve the light source to originate from
The same place and distance behind the mirror as the real source is infront of the mirror. (it is therefore a virtual image)
What is a virtual image?
The light does not actually come from that point—it only looks like it does. You have to look into the mirror or lens to see it.
What does Snell's law describe?
Refraction
The speed of light in glass is _______the speed of light in air?
Less than
think of the relationship between speed of light and velocity and wavelength
C=LV (L is lambda)
Light passes through three materials N1=1, N2=1.3 and N3=1.5. Each change in N makes the light refract. Will the angle with the normal at N3 be different if light only goes from N1 to N3 than if it had gone from N1 to N2 to N3?
No. The angle to the normal will be the same regardless of N2 being present
An observer looks directly down on a fish swimming below the surface. How deep does the fish appear to be in relation to its actual depth?
It appears to be shallower
A fish swims below the surface of the water. An observer looking from a distance looks ________ to the fish.
Taller than he really is
A fish is 1.2 m beneath the surface of a still pond of water. At what maximum angle can the fish look toward the surface (measured with respect to the normal to the surface) in order to see a fisherman sitting on a distant bank? (for water, n = 1.333) A drawing might help. Take the fishes perspective.
48.6
n1*sinθ=n2*sinθ
1sin90=1.33sinθ
To be a real image the light has to _________?
If you put up a screen _______?
actually pass through the image point.
I can see an image on it.
to be a virtual image ___________?
Where do you have to look to see the image?
The light does not actually come from that point—it only looks like it does.
- into the mirror to see it.
When we look into the water at a fish is the fish virtual, real, upright, or inverted?
Virtual and upright
Light from an object reflected by a mirror in such a way that the rays diverge after reflection as if they were coming from a point behind the mirror produces what kind of image?
Virtual
Which of the following is not a principal ray of a concave mirror?
a. a ray that goes through the center of the curvature of the mirror
b. a ray that approaches the mirror along a line parallel to the axis
c. a ray that goes through the focal point on the way to the mirror
d. all three are used
D. All three are used
Which 2 of the following best describes the image of a concave mirror when the object is far away from the mirror (object distance is >C)? real, virtual, upright, inverted
Real and Inverted
Which of the following best describes the image of a concave mirror when the object is at a distance smaller than the focal point distance from the mirror? real, virtual, upright, inverted
Virtual and upright
Which of the following best describes the image of a concave mirror when the object is at a distance between the center of curvature and the focal point distance from the mirror? real, virtual, upright, inverted
Real and Inverted
Which of the following is not a principal ray of a converging lens?
A ray that goes through the center of the curvature of the lens
A ray that approaches the lens along a line parallel to the axis
A ray that goes through the focal point on the way to the lens
All three are used
A ray that goes through the center of curvature.

In a lens the third ray is drawn through the center of the lens
Which of the following describes the image for a thin converging lens that forms whenever the magnitude of the object distance is greater than that of the lens' focal length? Real, upright, inverted, virtual
Real and inverted
A lens is used to image an object onto a screen. If the right half of the lens is covered, what happens to the image?
the image becomes fainter. the right half of the lens is covered not the right half of the object, so half the light rays project on the screen making it dimmer
A lens is used to image an object onto a screen. If the right half of the object is covered, what happens to the image?
The left half of the image disappears
What happens to the image for a thin converging lens if the object is moved closer to the lens so that it is closer to the lens than the focal point?
Real, upright, inverted, virtual
Virtual and upright
Interference occurs with which of the following?
Light waves
Sound waves
Water waves
All of the above
All of the above
Phase differences between the portions of the wave are caused by?
Differences in the distance traveled, and phase changes occuring on reflection
For shorter steps (shorter wavelength) the minimums and maximums__________
Get closer together
When the slits get closer together the minimums and maximums . . .
get further apart
When light hits a mirror and bounces off there is a _________ phase shift
180 degree
When light reflects off a medium with a larger n there is a 180o phase shift.
When light reflects off a medium with a smaller n there is no phase shift
Yep thats true
An interference pattern is formed on a screen by shining a planar wave on a double-slit arrangement. If we cover one slit with a glass plate, the phases of the two emerging waves will be different because the wavelength is shorter in glass than in air. If the phase difference is 180°, how is the interference pattern altered?
the bright and dark spots are interchanged
Two identical slides in air are illuminated with monochromatic light. The slides are exactly parallel and the top slide is moving slowly upward. Assume that only the top surfaces are reflective. What do you see in top view?
Sequentially all black, then all bright
An oil film on water reflects different colors more or less brightly owing to interference, depending on the film thickness. In an outer region where the film is thinnest (thin compared to visible wavelengths), all colors reflect brightly. From this information, we can tell that the index of refraction of the oil is______than that of water
Less
What happens to the color seen as the soap film gets thicker?
the color changes from green to yellow
(goes to a longer wavelength)
ROYGBIV
What is the minimum thickness of a glycerin film (n=1.47) on which light of wavelength 600 nm shines that results in constructive interference of the reflected light? Assume the film is surrounded front and back by air.
102nm
2nt=ml (l=lamda) and
d=2t because we want constuctive interference
2(1.47)(2t)=600nm
600/4(1.47)=t
t=102nm
When a ray of light is incident on two polarizers with their polarization axes perpendicular, no light is transmitted. If a third polarizer is inserted between these two with its polarization axis at 45° to that of the other two, does any light get through to point P
yes.
Look at the equations for double slit and single slit
Double
dsinθ(bright)=ml
dsinθ(dark)=(m+1/2)l
Single
dsinθ(dark)=m(l/a)
If I am nearsighted what kind of lenses do I need?
Diverging

the image is formed infront of where it needs to be...diverging lenses move this image further back in the eye to the right spot
If I am farsighted whatkind of lenses do i need?
Converging...need to form the image closer than it is naturally
For a simple magnifying glass the image is???
Virtual
For a telescope we get a_________ image?
virtual de-magnified
A 1 cm tall object is placed 4 cm to the left of a converging lens of focal length 8 cm. A diverging lens of focal length -16 cm is 6 cm to the right of the converging lens. Find the position and height of the final image. The image is
Upright and Virtual
Can you get a real image from a divergin lens?
Yes, but only if you create a negative object, which would be the image of another lens.