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45 Cards in this Set

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Law of Sines

a/sinA = b/sinB = c/sinC or sinA/a = sinB/b = sinC/c

Law of Sines Ambiguous case - no triangle

a<h, side a is too short to meet side c

Law of Sines Ambiguous case - one right triangle

a=h, side a equals the altitude

Law of Sines Ambiguous case - one oblique triangle

a>b, one triangle is possible

Law of Sines Ambiguous case - two triangles one acute and one obtuse

h<a<b, side a intersects side c at an obtuse angle or acute angle

Area of a triangle given 2 sides and the angle between them

(1/2)bcsinA or (1/2)absinC or (1/2)acsinB

Law of cosines a

a squared = b squared + c squared -2bccosA or cosA = (b squared + c squared - a squared)/2bc

Law of cosines b

b squared = a squared + c squared - 2accosB or cosB = (a squared + c squared - b squared)/2ac

Law of cosines c

c squared = a squared + b squared - 2abcosC or cos C = (a squared + b squared - c squared)/2ab

Guidelines for solving an iblique triangle given SAS 1

Find the length of the side opposite the known angle by using law of cosines

Guidelines for solving an iblique triangle given SAS 2

Use the law of sines to find the measure of the angle opposite the shorter of the two given sides. This angle will always be acute. Alternatively, use the law of cosines (alternative form) to find either remaining angle

Guidelines for solving an iblique triangle given SAS 3

Find the measure of the third angle by subtracting the sum of the measures of the other two angles from 180

Guidelines for solving an oblique triangle given SSS 1

Use the alternative formulas for the law of cosines to find the largest angle of the triangle ( angle opposite the longest side)

Guidelines for solving an oblique triangle given SSS 2

Find either the remaining two angles using either the law of sines or the law of cosines. Since the largest angle was found in step 1, the two remaining angles are guaranteed to be acute.

Guidelines for solving an oblique triangle given SSS 3

Find the measure of the third angle by subtracting the sum of the measures of the other two angles from 180

Heron's formula for area of a triangle

Area = square root of (s(s-a)(s-b)(s-c) where s is the semi perimeter: s=1/2(a+b+c)

Polar coordinate system definition

Consists of a fixes point O called the pole (or origin), and a ray called the polar axis, with endpoint at the pole. Each point P in the plane is defined by an ordered pair of the form (r, theta) where r is the directed distance from the pole to P

Polar coordinate system 2

If r > 0, point P is located r units from the pole in the direction of theta


If r < 0, point P is located |r| units from the pole in the direction of theta + pi (the direction opposite theta)


If r = 0, point P is located at the pole

Polar coordinate system 3

Theta is a directed angle from the polar axis to line OP


Theta > 0 is measured counterclockwise from the polar axis


Theta < 0 is measured clockwise from the polar axis

Convert between rectangular and polar coordinates

To convert polar coordinates (r, theta) to rectangular coordinates (x,y), use x=rcos theta and y=rsin theta

Convert between rectangular and polar coordinates

To convert the rectangular coordinates (x,y) to polar coordinates (r,theta), use r squared = x squared + y squared and tan theta = y/x for x does not = 0

Scalars

Quantities that are described by a single value called the magnitude

Magnitude

Size or measure of the quantity

Vector quantities

Quantities that are described by both magnitude and direction

Speed

Scalar quantity that tells us how fast an object travels

Velocity

Vector quantity that tells us how fast the object travels and in which direction

Vector

In a plane it is a line segment with a specified direction

Component form of a vector

V={x2-x1,y2-y1}

Equality of vectors

If v=《a1,b1》and w=《a2,b2》, then v=w if and only if a1=a2 and b1=b2

Vector addition

Let v =《a1,b1》, w=《a2,b2》and c be a real number


V+w=《a1+a2,b1+b2》

Vector subtraction

Let v =《a1,b1》, w=《a2,b2》and c be a real number


V-w=《a1-a2,b1-b2》

Multiplication of a vector by a scalar

Let v =《a1,b1》, w=《a2,b2》and c be a real number


Cv=《ca1,cb1》

Unit vector

Vector that has a magnitude of 1

Find a unit vector in the direction of a given vector

If v = {a,b}, then a unit vector Uv in the direction of v is given by


Uv = (1/||v||)v=(1/||v||){a,b}={a/||v||,b/||v||}


If v = {a,b}, then a unit vector Uv in the direction of v is given byUv = (1/||v||)v=(1/||v||){a,b}={a/||v||,b/||v||}

Represent vectors in terms of I and J

The representation of v={a,b} in terms of i and j is v=ai+bj


The values of a and b are called scalar horizontal and vertical components of v, respectively

Magnitude direction and components of a vector 1

Let v={a,b} be a vector in standard position and let 0 be less than or equal to theta which is less thenan 360° be the direction of v measured counterclockwise from the positive x axis

Magnitude direction and components of a vector 2

||v||=square root of a squared + b squared and tan theta = b/a (where a is not = to 0) (magnitude and direction of v)

Magnitude direction and components of a vector 3

a=||v||cos theta and b=||v||sin theta


v={a,b}={||v||cos theta, ||v||sin theta} or v=ai+bj=||v|| (cos theta)i + ||v||(sin theta)j

Dot product

If v={a1,b1} and w={a2,b2}, the dot product v•w is defined as


v•w=a1a2+b1b2

Angle between 2 vectors

If theta is the angle between 2 nonzero vectors v and w, then


Cos theta = (v•w)/||v|| ||w|| and theta = cos-1(v•w/||v|| ||w||)

Orthogonal vectors

Two vectors v and w are orthogonal if and only if v•w=0

Decomposition of a vector into orthogonal vectors 1

If v and w are 2 nonzero vectors then1. The vector projections of v onto w is given by projwv=((v•w)/||w||squared)w


If v and w are 2 nonzero vectors then1. The vector projections of v onto w is given by projwv=((v•w)/||w||squared)w

Decomposition of a vector into orthogonal vectors 2

2. To decompose v into vectors v1 and v2 parallel to w and orthogonal to w, respectively, we have


v1=projwv=((v•w)/||w||squared)w and v2=v-v1

Definition of work 1

If D is the displacement vector of an object in moving the object in a straight line from points A to B under a constant force F, then the work W done is computed by


1. W=F•D

Definition of work 2

W=||projdF|| ||D|| or W=||F|| ||D||cos theta, where theta is the angle between F and D