A Thermometric Titration
Table: (Representing the results obtained from the experiment)
HCl 1 mol dm-3 (± 0.100)
HCl 0.76 mol dm-3 (± 0.100)
Highest Temperature (Time)
Lowest Temperature (Time)
Sample Calculation for the Unknown Concentration
C1V1 = C2V2
1 (190 - 505) = C2 (235 - 505)
1 28.0 = C2 37.0
C2 = 2837
C2 = 0.760 mol dm-3 (±0.0500)
Sample Calculation for the amount of mole in Unknown Acid
Mole = Concentration Volume
Mole = 0.760 (±0.0500) (235 - 505) (±0.0100)
Mole = 0.760 (±0.0500) 37.0 (±0.0100)
Mole = 28.0 mol (±6.73)
Sample Calculation for Uncertainty of Mole
±0.05000.76 100 = ±6.700% ±0.010037 100 = ±0.0300% …show more content…
First with Hydrochloric acid (HCl) of concentration 1.00 mol dm3 and Second with again Hydrochloric acid (HCl) of an unknown concentration. The main aim of this experiment was to find the concentration for the unknown Hydrochloric acid and to determine the quantity of energy released in the titration. With the help of the known Hydrochloric acid concentration the unknown was determined. Although there was no hypothesis made before the experiment as it was not required.
With the required equipment, Hydrochloric acid was poured into a burette upto 0mL. A pipette was used to gather 25.0 cm3 of Sodium Hydroxide and transfer it into a Beaker. However during the experiment, 25.0 cm3 was converted into dm3, which resulted as 0.0250 dm3. The Beaker was placed underneath the Burette during the titration process. During the setup, a temperature probe was placed in the beaker containing the NaOH, as the temperature was to be recorded. Once the temperature of the solution was stabilized after 50s, 1.0 dm3 of Hydrochloric Acid was titrated into the solution of NaOH. The mixture was stirred as the titration continued. Successive 1.0dm3 portions of HCl solution were added at every intervals of 5 second, stirring of the mixture continued as the process continued, as it helped the two solutions of NaOH and HCl to mix properly. The temperature of the NaOH solution was recorded, with the help of Logger Pro. This data is …show more content…
It might have affected the result obtained for the unknown concentration and hence also the quantity of energy released during the titration.
After the first titration, we should have used a different Burette or we could’ve washed the burette first with water and then with HCl of 0.76 mol dm-3 (the unknown concentration), so that all the HCl of 1.0 mol dm-3 emptied.
Heat Lost to the Surrounding
Steps : 5-7
It would affect the result of the quantity of energy released in the titration.
During the titration, a lid might be used to avoid the heat lost to the surrounding.
Although, There would still be heat lost to the surrounding, but the amount would be lesser.
Time lapse during the titration
Step : 5-7
It would affect the time data for the maximum and minimum temperature, and hence would affect the result of the unknown concentration and the energy