# Explanation Of Hooke's Law, Law Of Elasticity

2208 Words 9 Pages
Serial Number Topic Page Number 1 Introduction 3
2 Theory

2.1. Definition
2.2. Spring arrangement
2.3 Series arrangement of springs
2.4. Parallel arrangement of springs 3
3 Methodology

3.1. Apparatus
3.2. Procedure 8
4 Results

4.1. parallel and series combination

4.2. Compression springs

4.3. Tension springs

4.4. Graph of Tension Spring, Compression spring, Parallel spring and the Series Spring 9
5 Discussion 14
6 Conclusion 15
7 Bibliography 15 Introduction
The spring is a wonder of human manufacturing and originality. A reason being its kinds, that is, the compression, the extension, the torsion, the coil springs and all have different uses and functions.
The experiment was done to prove the results for Hook’s
Elastic behaviour of solids as per Hooke’s law can be understood by the minute displacements of their component molecules and atoms from usual positions are proportional to the force that leads to that displacement.

Theory
2.1) Definition: Hooke’s law states that, the force required to compress or expand a spring to some distance that is the comparatively minute deformation in spring to certain distance is directly proportional to the displacement or size of the deformation (Fig.1)
In simpler words, the law is a theory of physics that says that the force required to extend or compress a spring by a certain distance is directly proportional to that distance.
Also, when the force used to compress or extend the object attached to the spring is disconnected it would go back to its original shape.
Hooke’s law is the first classical example of an explanation of elasticity – which is the property of an object or material which causes it to be restored to its original shape after distortion. The phenomenon to recoil to normal shape after undergoing distortion can be called as “restoring force”. In the purview of the Hooke’s Law, this restoring force is proportional to the quantity of “stretch”
Different springs were taken that were Tension, Compressed, series combination and Parallel Combination and when their spring constant and the graph was plotted between force(N) and displacement(x), it showed all the springs followed the hooks law that is the graph was linear that is the force applied was directly proportional to the displacement. In case of tensed, compressed and series combination springs it was found that the points close to the origin were very close to each other. On calculating the spring constant for the parallel and series combination, the value of spring constant(K) in case of parallel combination was found to be more than in case of the series

• ## Kinematics Of Particles Summary

If the particle has initial position x1, initial velocity v1, final position x2 and final velocity v2, we have ∫_(x_1)^(x_2)▒〖F_t dx〗=∫_(v_1)^(v_2)▒mvdv ∫_(x_1)^(x_2)▒〖F_t dx〗=(mv_2^2)/2-(mv_1^2)/2 The first term in the above equation is the work done by a force and the second and the third terms are kinetic energies of a particle. Since the work due to a force is scalar quantity, kinetic energy of a particle is also a scalar quantity. We write above equation as U_(1→2)=T_2-T_1 T_1+U_(1→2)=T_2 Eq. 2.10 Eq. 2.10 is the mathematical representation of the principle of work and energy for a particle.…

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• ## The Two Properties Of The Mass Spring System

The to and fro vibration of a mass on a spring or air molecules is analogous to a point moving around the circumference of a circle at a constant rate. During the course of oscillation, the magnitude of restoring force changes over time because magnitude of displacement changes. As mass moves towards equilibrium Fr reduces, as mass moves away from equilibrium, maximum displacement, Fr…

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• ## Friction Experiment

In this experiment, we pulled a weighted block across the table and measured the amount of force it took for the block to begin to move. Theory states that static friction is a force that resists motion. When two surfaces are moving across each other, there is friction force that slows down an object by taking away some of the energy. Static friction (f_smax=μ_s f_N) resists motion. An example of static friction is when you are pushing a heavy object.…

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• ## Linear Differential Concentration And Damping Factors

9 Part two of the lab allowed us to find the spring coefficient and the damping coefficient. To find the spring coefficient we use the equation, k= ((2πf)^2 m)/2 Eq.10 Were f is the frequency and m is the mass. This is showing the spring coefficient which represents the relationship between how hard the spring is able to push the spring down . As the spring constant gets larger the more force needed to push the spring down. The last equation we used was to calculate the damping factor, which was, c=2√km ∙ ζ Eq.…

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• ## Essay On Kinetic Friction

Static friction is given by Fs< usn where N is the normal force between the object and its support surface and us is the coefficient of static friction. There-fore, the coefficient of static friction is given by Us= fs, max/ N Where F s, max is the maxixmum force of static friction. Once the external force overcomes static friction, the object moves. Its motion is opposed by kinetic friction. The force of kinetic friction is given by f k = ukN where u k is the coefficient of kinetic friction.…

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• ## Importance Of Conservation Of Mechanical Energy

The uncertainty of ∆E/∆y can be calculated in quadrature using the following equation: δ ∆E/∆y=√((δ_(∆E/(∆y, slope))^2+δ_(∆E/(∆y, m))^2)) (6) This value is 0.00208773 J/m, or 0.002 J/m, which is the same as the value calculated on Origin. So ∆E/∆y is -0.283±0.002J/m. Spring Potential Energy: Introduction and Theory: Spring potential energy (aka elastic potential energy) is the stored potential energy of a stretched spring. Hooke’s Law states that the displacement of the spring when a force is acting upon it is directly proportional to that force that makes it compressed or extended. The equation below is Hooke’s Law, F= -kx (7) where F is the force, k is the constant, x is the position.…

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• ## Proportionality And Newton's Second Law Of Motion Essay

Proportionality and Newton’s Second Law of Motion Abstract How does increasing the mass of an object affect its acceleration? Is acceleration dependent of the mass of an object? How do they relate? Defining and testing Newton’s second law of motion familiarizes us with this relationship. In this experiment, we use the mass of an object as an independent variable to come to a conclusion about force and acceleration.…

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• ## Relationship Between Static And Kinetic Friction

Based on the Force - Time graph generated by slowly pulling the cart with weights, we get measurement of static and kinetic friction to calculate the coefficients of frictions. From the graph, the maximum static force is peak force value before kinetic friction takes place.Then get µs according to equation fsmax = µs N. From the average kinetic friction from the Force -Time graph and equation fk = µk N, calculate its coefficient. This lab leads to a conclusion that the coefficient of static friction is usually larger than that of kinetic friction. Our experimental value of coefficient of static and kinetic friction for plastic cart is ( 0.183 ± 0.003 ) N and ( 0.098 ± 0.001 ) N. For the cork cart is ( 0.250 ± 0.003 ) N and ( 0.217 ± 0.002 ) N. For the felt cork cart is ( 0.203 ± 0.003 ) N and ( 0.165 ± 0.002 )…

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• ## Relationship Between Fluid And Newtonian Fluid

A fluid in which the viscous stresses taken place from its flow at all the point are linearly proportional to the rate of change in its deformation over time is called Newtonian fluid. Newtonian fluid explains the relationship between the shear rate and the shear stress is linear with the proportionality constant, which is to be referred as the coefficient of viscosity. Non-Newtonian fluid is a fluid where the properties of fluid flow are not similar with Newtonian fluid. In Newtonian fluids, the viscosity of fluid is dependent on the shear rate history. In the non-Newtonian fluid, the relationship between the shear stress and the shear rate is different and can even be time dependent.…

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• ## Porous Materials Essay

U=A_p/S_s v Where Ss is the cross sectional area of the sample, and v is the terminal velocity of the mass which is obtained by timing how long the mass takes to travel a defined length. The flow resistivity is thus: r=(CMgcos(ψ) S_s t)/(LA_p^2 ) A correction factor (C)  is used to account for leakage between the mass and the pipe wall, as well as the friction between the two surfaces. The angle at which the pipe is positioned from the vertical is ψ. 2.3.2 Microphone Method of Measuring Flow Resistance The alternative method of measuring flow resistance is using an impedance tube . The sound source used is a pure tone and is adjusted so the distance between each microphone is exactly an odd number of quarter wavelengths.…

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