Parana Pine:
For the Parana Pine I obtained the published value from a website since the values on the lab sheet didn’t have a values for Parana Pine. Firstly, I calculated my own Young’s Modulus Value with the result got from the tests using the equation for Young’s Modulus in Bending:
E= l³/(4bd^3 ) x ( Δw)/( Δx)
From using this equation, I achieved 14.44 E/GPa as a value, the published value, was: 11.37 E/GPa found on ‘The Wood Database’. The difference between my results and the Published values is: 3.07, and it was still within the range of the published value.
Regarding the accuracy of the test, since this was my first time conducting this type of test, there may have been some mistakes I made that could have affected the results …show more content…
However the geometry of how the given load is placed onto the material is important as well, based on the tension and bending properties of the given material. Material Stiffness is the Young’s Modulus of a material, therefore the how much loads the material would resist before elastic deformation. For example: For the component stiffness of Timber, the Timber generally has more stiffness when it is placed on the ‘edge on’, since the deflection is smaller, usually of: 3mm at 1KN of load, this may be because this side of the timber is thicker which can also contribute to the stiffness of the material. Whereas if the timber were placed on a ‘flat face’ then the deflection would be: 58mm at 1KN load. This is due to the geometry of how the Timber is positioned, because when a Timber beam is placed on ‘Flat face’ the distance between the top face and bottom face is smaller, therefore the Young’s Modulus in Bending is notably lower and is more prone to higher deflection. Compared to the ‘edge on’ side of the Timber, which is stiffer and the deflection is …show more content…
Explain why?
Based on my results I believe the Mild Steel is the most suitable component for structural application, because the 0.3% Mild Steel had the highest E/GPa value of 212.77 E/GPa compared with all the other materials used.
Steel is a metal, so it is made up of metallic bonds, which means that the element largely consists of positive ions (positive charge) and delocalized electrons (free electrons of negative charge), the repulsion is balanced within the atom, a main reason to why metals are non-reactive to other elements.
However one disadvantage of the using steel is because it consists of iron atoms. Iron is reactive to both water and oxygen, and when these elements react together it forms –iron oxide (rust). Rust can reduce the effectiveness and efficiency of the material. So you should be very careful whilst handling steel in construction.
Moreover, metallic bonds have a simple crystal lattice in solid state and are the weakest primary chemical bonds. Hence the reason to why pure metals are dissolved with other elements such as: carbon for mild steels. Metal alloys have increased strength and hardness. The structure of alloys reduces the space between each ion, so there is less space for delocalized electrons and it improves the chemical bond with each element within the
For the Parana Pine I obtained the published value from a website since the values on the lab sheet didn’t have a values for Parana Pine. Firstly, I calculated my own Young’s Modulus Value with the result got from the tests using the equation for Young’s Modulus in Bending:
E= l³/(4bd^3 ) x ( Δw)/( Δx)
From using this equation, I achieved 14.44 E/GPa as a value, the published value, was: 11.37 E/GPa found on ‘The Wood Database’. The difference between my results and the Published values is: 3.07, and it was still within the range of the published value.
Regarding the accuracy of the test, since this was my first time conducting this type of test, there may have been some mistakes I made that could have affected the results …show more content…
However the geometry of how the given load is placed onto the material is important as well, based on the tension and bending properties of the given material. Material Stiffness is the Young’s Modulus of a material, therefore the how much loads the material would resist before elastic deformation. For example: For the component stiffness of Timber, the Timber generally has more stiffness when it is placed on the ‘edge on’, since the deflection is smaller, usually of: 3mm at 1KN of load, this may be because this side of the timber is thicker which can also contribute to the stiffness of the material. Whereas if the timber were placed on a ‘flat face’ then the deflection would be: 58mm at 1KN load. This is due to the geometry of how the Timber is positioned, because when a Timber beam is placed on ‘Flat face’ the distance between the top face and bottom face is smaller, therefore the Young’s Modulus in Bending is notably lower and is more prone to higher deflection. Compared to the ‘edge on’ side of the Timber, which is stiffer and the deflection is …show more content…
Explain why?
Based on my results I believe the Mild Steel is the most suitable component for structural application, because the 0.3% Mild Steel had the highest E/GPa value of 212.77 E/GPa compared with all the other materials used.
Steel is a metal, so it is made up of metallic bonds, which means that the element largely consists of positive ions (positive charge) and delocalized electrons (free electrons of negative charge), the repulsion is balanced within the atom, a main reason to why metals are non-reactive to other elements.
However one disadvantage of the using steel is because it consists of iron atoms. Iron is reactive to both water and oxygen, and when these elements react together it forms –iron oxide (rust). Rust can reduce the effectiveness and efficiency of the material. So you should be very careful whilst handling steel in construction.
Moreover, metallic bonds have a simple crystal lattice in solid state and are the weakest primary chemical bonds. Hence the reason to why pure metals are dissolved with other elements such as: carbon for mild steels. Metal alloys have increased strength and hardness. The structure of alloys reduces the space between each ion, so there is less space for delocalized electrons and it improves the chemical bond with each element within the