Dssds Essay

1655 Words Apr 25th, 2014 7 Pages
PROBLEMS BASED ON ALPHABET. >> Page - 1 |
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PROBLEMS BASED ON ALPHABET |
Generally in Alphabetical questions a letter series is given in the English alphabets from A to Z. We have to find out the letters satisfying certain given conditions as regards their positions in the given sequence.
Some Models:
Directions : Following questions are based on the general English alphabet series.
AB C D E F G H I J K LM N O P Q R S T U VW X Y Z
¤ If the first five letters of English alphabet are reversed and then next six letters are reversed, again next five letters are reversed, again next six letters are reversed, again last four letters are reversed, then which letter will be 11th to the right
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PROBLEMS BASED ON ALPHABET. >> Page - 3 |
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Hint: 8R / 7R / 6R / 5R
(I) (II) (III) (IV)
25 - (7 + 6 + 5);
= 25 - 18;
= 7; G is the required letter.
¤ If the first seven letters of English alphabet are reversed, so are the next eight, so are the next six and so are the remaining five, then what will be the 11th letter to the left of 3rd letter from the right?
1) I 2) J 3) M 4) N 5) None of these
Ans: 2.
Hint: 7R / 8R / 6R / 5R
(I) (II) (III) (IV)
14th letter from the right comes in section B
(I) + 14 - { (III) + (IV)}
7 + 14 - 11 = 10th letter i.e J |
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PROBLEMS BASED ON ALPHABET. >> Page - 4 |
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¤ If the first three letters of English alphabet are reversed and so on ... and the last two letters are reversed, then which letter will be 19th letter to the right of 17th from the left of 5th letter from the right?
1) W 2) B 3) V 4) X 5) None of these
Ans: 3.
Hint: 3R / 3R / 3R / 3R / 3R / 3R / 3R / 3R / 2UC
(I) (II) (III) (IV) (V) (VI) (VII) (VIII) (IX)
17 + 5 - 19 = 3rd…

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