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15 Cards in this Set

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  • Back

Ohm's law described

I=g*E, where E = voltage


E=IR;


g=1/R = permeability


- circuit needs a resistor and battery





resistance (R)

resistance = volts/current


- how hard it is to get across

conductance (g)

conductance = permeability = 1/R


- how easy it is to get across

membrane capacitance

- good insulator = membrane


- good conductor = intracellular and extracellular fluid


- membrane capacitance passively stores electrical charge

charge equation (Q)

Q=C*E


charge = capacitance*voltage


- capacitance is proportional to the area of conductors


- charge increases as area is increased


- capacitance increases as diameter increases

relationship of capacitance to:


area


distance b/w plates


material b/w plates

1. area and capacitance = positively correlated


2. bistance b/w plates (e.g. myelin) and capacitance = negatively correlated


3. material b/w plates and capacitance = ??

Time constant

tau = the time it takes voltage to decay to 37% of its final voltage


- function of resistance and capacitance

Capacitor in a cell

- begins as a short circuit with zero impedance (so meter = 0)


- as charge accumulates, current begins to flow through resistor and meter reads a voltage (no longer a short circuit)


- once capacitor is fully charged, no additional current flows to the capacitor and all current goes through resistor

capacitor charging or discharging effects

- because the membrane is a capacitor, there is a delay as it charges or discharges


- delay increases as the area of membrane increases (although it can hold more charge overall)

equilibrium (membrane resting potential)

net charge = 0


no energy is needed to maintain the cell


Ek=(RT)/(zF)*ln(ko/ki) = Nernst

RC current

- current across the resistor = membrane potential


- you need voltage across the resistor to get a current:


Ir=g(Em-Ek)


current = conductance * driving force



what is the current once capacitor is charged?

- once capacitor is charged,


Ir=g*Em

what is current before capacitor is charged?

Ir=g(Em-Ek)current = conductance * driving force

IV-curve plot

Em (voltage) = x-axis


current = y-axis


g= slope of line and gives indication of how many channels are open


(1g = 1 channel, 3g = 3 channels, etc)

what happens when g (conductance) is not constant?

- conductance becomes a function of voltage and plot is not linear


- when g increases, current must increase to keep voltage the same


I=g*Em (membrane resting potential in volts)