• Shuffle
    Toggle On
    Toggle Off
  • Alphabetize
    Toggle On
    Toggle Off
  • Front First
    Toggle On
    Toggle Off
  • Both Sides
    Toggle On
    Toggle Off
  • Read
    Toggle On
    Toggle Off
Reading...
Front

Card Range To Study

through

image

Play button

image

Play button

image

Progress

1/27

Click to flip

Use LEFT and RIGHT arrow keys to navigate between flashcards;

Use UP and DOWN arrow keys to flip the card;

H to show hint;

A reads text to speech;

27 Cards in this Set

  • Front
  • Back

Avogadro constant

6.02 x 10²³

Molar mass

Moles = mass ÷ Mr

Number of particles

Moles = no. Of particles ÷ 6.02 x 10²³

Empirical formula

A. Find moles of individual element


Mass÷ Mr


B. Ratio (÷ by smallest)

Hydrated salts

A. Moles of compound and water separately (not individual elements)


B. Ratio (÷ by smallest)

% by mass

% by mass = (mass of element ÷ Mr of compound) × 100

Stoichiometry

The ratio of the amount, in moles, of each substance in a chemical reaction

Limiting reagents in reacting masses

A. Calculate moles of both reactants - use limiting reactant in further calculation


B. Use ratio from equation to work out unknown mol


C. Work out unknown info

% yield

% yield = (acttual mass ÷ theoretical mass) × 100

Atom economy

Atom economy (sum of molar masses of desired products ÷ sum of molar masses of all products) × 100

Concentration

Moles ÷ volume

Mol dm‐³

Mol dm -³ = g dm-³ ÷ Mr

Volume

Moles = vol ÷ 24

If not given Room temp and pressure you do

pV = nRT

Tonnes and kilograms

1kg = 1000g = 10³ g


1 ton = 1000kg = 1000000g = 10⁶ g

Temperature

°C --> K +273

Pressure

kPa --> Pa ×10³

Volume

1dm³ = 1000 cm³


Cm³ --> m³ ÷10⁶


Dm³ --> m³ ÷10³

Pressure

Pa

R

8.314

Temperature

K

Concentration

Mol dm-³

Volume

Dm³

Mass

Grams

Moles

Mol

Molar mass

Mr

Equilibrium

Kc = [C]c [D]d (products)


-------------


[A]a [B]b (reactants)