Use LEFT and RIGHT arrow keys to navigate between flashcards;
Use UP and DOWN arrow keys to flip the card;
H to show hint;
A reads text to speech;
27 Cards in this Set
- Front
- Back
Avogadro constant |
6.02 x 10²³ |
|
Molar mass |
Moles = mass ÷ Mr |
|
Number of particles |
Moles = no. Of particles ÷ 6.02 x 10²³ |
|
Empirical formula |
A. Find moles of individual element Mass÷ Mr B. Ratio (÷ by smallest) |
|
Hydrated salts |
A. Moles of compound and water separately (not individual elements) B. Ratio (÷ by smallest) |
|
% by mass |
% by mass = (mass of element ÷ Mr of compound) × 100 |
|
Stoichiometry |
The ratio of the amount, in moles, of each substance in a chemical reaction |
|
Limiting reagents in reacting masses |
A. Calculate moles of both reactants - use limiting reactant in further calculation B. Use ratio from equation to work out unknown mol C. Work out unknown info |
|
% yield |
% yield = (acttual mass ÷ theoretical mass) × 100 |
|
Atom economy |
Atom economy (sum of molar masses of desired products ÷ sum of molar masses of all products) × 100 |
|
Concentration |
Moles ÷ volume |
|
Mol dm‐³ |
Mol dm -³ = g dm-³ ÷ Mr |
|
Volume |
Moles = vol ÷ 24 |
|
If not given Room temp and pressure you do |
pV = nRT |
|
Tonnes and kilograms |
1kg = 1000g = 10³ g 1 ton = 1000kg = 1000000g = 10⁶ g |
|
Temperature |
°C --> K +273 |
|
Pressure |
kPa --> Pa ×10³ |
|
Volume |
1dm³ = 1000 cm³ Cm³ --> m³ ÷10⁶ Dm³ --> m³ ÷10³ |
|
Pressure |
Pa |
|
R |
8.314 |
|
Temperature |
K |
|
Concentration |
Mol dm-³ |
|
Volume |
Dm³ |
|
Mass |
Grams |
|
Moles |
Mol |
|
Molar mass |
Mr |
|
Equilibrium |
Kc = [C]c [D]d (products) ------------- [A]a [B]b (reactants) |