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14 Cards in this Set
- Front
- Back
- 3rd side (hint)
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During a particular thunderstorm, the electric potential difference between a cloud and the ground is Vcloud - Vground = 1.02 x 108 V, with the cloud being at the higher potential. What is the change in an electron's electric potential energy when the electron moves from the ground to the cloud?
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-1.63×10-11 J
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you use the equation PE=qV where q is the charge on the
electron that is moving from the ground to the cloud. V is given and q=-1.6E-19C |
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A particle has a charge of +1.46 mC and moves from point A to point B, a distance of 0.194 m. The particle experiences a constant electric force, and its motion is along the line of action of the force. The difference between the particle's electric potential energy at A and B is EPEA - EPEB = +9.22E-4 J. Calculate the magnitude of the electric force that acts on the particle.
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4.75×10-3 N
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started with PE/q = V
Than V/d = E and finally F= qE |
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Two charges A and B are fixed in place, at different distances from a certain spot. At this spot the potentials due to the two charges are equal. Charge A is 0.154 m from the spot, while charge B is 0.424 m from it. Calculate the ratio qB/qA of the charges.
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2.75
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divideq
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Location A is 3.11 m to the right of a point charge q. Location B lies on the same line and is 4.11 m to the right of the charge. The potential difference between the two locations is VB - VA = 44.0 V. What is the magnitude and sign of the charge?
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-6.26×10-8 C
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44 V=k*q*((1/ra)-(1/rb))
k=8.99E9 N*m^2/C^2 |
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Four identical charges (+2.03mC each) are brought from infinity and fixed to a straight line. The charges are located 0.412 m apart. Determine the electric potential energy of this group.
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not yet
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19.28
An equipotential surface that surrounds a point charge q has a potential of 469 V and an area of 1.12 m2. Determine q. |
1.56×10-8 C
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solved for "r" by taking the square root of A/4pi,
then multiplying by V and dividing by k. k=8.99E9 N*m^2/C^2 |
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The inner and outer surfaces of a cell membrane carry a negative and positive charge, respectively. Because of these charges, a potential difference of about 0.0660 V exists across the membrane. The thickness of the membrane is 7.88E-9 m. What is the magnitude of the electric field in the membrane?
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8.38×106 V/m
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just divide volts over distance
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19.38
What voltage is required to store 7.34E-5 C of charge on the plates of a 6.02 microF capacitor? |
1.22×101 V
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I used the equation C=Q/V
I had C= the number of Farats given in the problem and Q= the charge given in the problem and solved for V. |
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19.49
Two point charges, +3.52mC and -6.11mC, are separated by 1.10 m. What is the electric potential midway between them? |
-4.23×104 V
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V=k(q1/.5r+q2/.5r)
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1 farand=
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C/V
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get from Farand to charge to number of electrons
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1.F*V
2.[1]/[charge of electron] |
((C/V)(V))=C
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charge of an electron
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1.6E-19 C
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19.53
A capacitor has a capacitance of 2.70E-8 F. In the charging process, electrons are removed from one plate and placed on the other plate. When the potential difference between the plates is 520 V, how many electrons have been transferred? |
8.78E13
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1.C=Q/V, solve for Q...
2.[1]/(1.6E-19 C)=# electrons |
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Four identical charges (+2.03mC each) are brought from infinity and fixed to a straight line. The charges are located 0.412 m apart. Determine the electric potential energy of this group.
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3.90×10-1 J
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Look at this page (http://www.physicsforums.com/showthread.php?t=65102), also look in notebook on p13, and read explanation I typed on lon capa. Hard problem.
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