Genetics

Front 1

Discontinuous replication

Back 1

D. Both A and C

Front 2

In which form of bacterial recombination does the bacteria find and take up the DNA instead of having it injected into the cell?

Back 2

C. Transformation

Front 3

The Maximum recombination freuency between two genes is

Back 3

C. 50%

Front 4

Hershey and Chaes differentiated between DNA and protien by:

Back 4

A. labeling the DNA with 32Phosphorous, proteins with 35Sulfur

Front 5

E. COli is grown in 15N contating Media for several generations so taht all of the DNA is'heavy' and then grown for 2 generations in light (14N) media. What would be the proportion of heavy:hybrid:light DNA assuming dispersive replicatio?

Back 5

C: 0:1:0

Front 6

In what form of bacterial recombination is a double recombination event not required to integrate the DNA into the chromosome?

Back 6

D.Required in all forms

Front 7

A non-color blind father is married to a woman who is also not color blind. They have four sons, two of whom are color blind. They have a child with Klinefelter syndrome. This child suffers from color blindness. This occurred because of a normal gamete fusing with a gamete which is the result of nondisjunction in:

Back 7

E. Meiosis II in female

Front 8

What is the sex of the color blind child in the previous question

Back 8

A. male

Front 9

Which of the Following is true? (Inversions)

Back 9

D. Inversions interfere with recombination, reciprocal translocations with forming gametes with the correct chromosome balance

Front 10

Which of the following is the result of dosage compensation in human females

Back 10

C. Barr Body

Front 11

After several generations of labelling in 15N media, Meselson and Stahl switched to 14N media for one generation. The DNA extracted after one generation in 14N media was centrifuged in a cesium gradient. The DNA formed a single band with a density somewhere between DNA grown in 15N media and DNA grown in 14N media. This data is consistent with:

Back 11

E. semiconservative and dispersive replication

Front 12

XYY can only occur because of a normal gamete fusing with a gamete which is the result of nondisjunction in:

Back 12

A. Meiosis II in male

Front 13

The pyrimidine bases are

Back 13

Thymine and cytosine

Front 14

A colorblind mother and normal vision father have a child who is XXXXYY and colorblind. This is the result of:

Back 14

D. Nondisjunction in Meiosis II in the father and Meiosis I and II in the mother.

Front 15

In the Meselson Stahl experiment differentiating the modes of replication by labeling with different forms of nitrogen and spinning in a cesium gradient, how many rounds of replication were needed to determine if the following modes of replication were not used in E. coli?

Back 15

C. two rounds of replication for dispersive; one round of replication for conservative

Front 16

In human beings, which sequence will have the largest Cot 1/2?

Back 16

D. a gene involved in eye color

Front 17

Meselson and Stahl only had DNA in their isopycnic centrifugation experiments which corresponded in density to fully replicated or unreplicated DNA. How could this be since many of the bacteria in their flasks would have only partially replicated their DNA at their specific time points?

Back 17

C. The experimenters messed up and broke the chromosomes up into small pieces

Front 18

The form of DNA normally found in our cells is:

Back 18

B. B

Front 19

In mammalian cells, the only autosomal chromosome abnormality found at any frequency is

Back 19

B) trisom