Study your flashcards anywhere!

Download the official Cram app for free >

  • Shuffle
    Toggle On
    Toggle Off
  • Alphabetize
    Toggle On
    Toggle Off
  • Front First
    Toggle On
    Toggle Off
  • Both Sides
    Toggle On
    Toggle Off
  • Read
    Toggle On
    Toggle Off

How to study your flashcards.

Right/Left arrow keys: Navigate between flashcards.right arrow keyleft arrow key

Up/Down arrow keys: Flip the card between the front and back.down keyup key

H key: Show hint (3rd side).h key

A key: Read text to speech.a key


Play button


Play button




Click to flip

19 Cards in this Set

  • Front
  • Back
Discontinuous replication
D. Both A and C
In which form of bacterial recombination does the bacteria find and take up the DNA instead of having it injected into the cell?
C. Transformation
The Maximum recombination freuency between two genes is
C. 50%
Hershey and Chaes differentiated between DNA and protien by:
A. labeling the DNA with 32Phosphorous, proteins with 35Sulfur
E. COli is grown in 15N contating Media for several generations so taht all of the DNA is'heavy' and then grown for 2 generations in light (14N) media. What would be the proportion of heavy:hybrid:light DNA assuming dispersive replicatio?
C: 0:1:0
In what form of bacterial recombination is a double recombination event not required to integrate the DNA into the chromosome?
D.Required in all forms
A non-color blind father is married to a woman who is also not color blind. They have four sons, two of whom are color blind. They have a child with Klinefelter syndrome. This child suffers from color blindness. This occurred because of a normal gamete fusing with a gamete which is the result of nondisjunction in:
E. Meiosis II in female
What is the sex of the color blind child in the previous question
A. male
Which of the Following is true? (Inversions)
D. Inversions interfere with recombination, reciprocal translocations with forming gametes with the correct chromosome balance
Which of the following is the result of dosage compensation in human females
C. Barr Body
After several generations of labelling in 15N media, Meselson and Stahl switched to 14N media for one generation. The DNA extracted after one generation in 14N media was centrifuged in a cesium gradient. The DNA formed a single band with a density somewhere between DNA grown in 15N media and DNA grown in 14N media. This data is consistent with:
E. semiconservative and dispersive replication
XYY can only occur because of a normal gamete fusing with a gamete which is the result of nondisjunction in:
A. Meiosis II in male
The pyrimidine bases are
Thymine and cytosine
A colorblind mother and normal vision father have a child who is XXXXYY and colorblind. This is the result of:
D. Nondisjunction in Meiosis II in the father and Meiosis I and II in the mother.
In the Meselson Stahl experiment differentiating the modes of replication by labeling with different forms of nitrogen and spinning in a cesium gradient, how many rounds of replication were needed to determine if the following modes of replication were not used in E. coli?
C. two rounds of replication for dispersive; one round of replication for conservative
In human beings, which sequence will have the largest Cot 1/2?
D. a gene involved in eye color
Meselson and Stahl only had DNA in their isopycnic centrifugation experiments which corresponded in density to fully replicated or unreplicated DNA. How could this be since many of the bacteria in their flasks would have only partially replicated their DNA at their specific time points?
C. The experimenters messed up and broke the chromosomes up into small pieces
The form of DNA normally found in our cells is:
B. B
In mammalian cells, the only autosomal chromosome abnormality found at any frequency is
B) trisom