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110 Cards in this Set
- Front
- Back
[A] versus t |
Linear for a zero order reaction |
|
ln[A] versus t |
Linear for a second order reaction |
|
1 / [A] versus t |
Linear for a second order reaction |
|
M / s |
Zero order |
|
M * s^ -1 |
Zero order |
|
1 / s |
First order |
|
s^-1 |
First order |
|
1 / M * s |
Second order |
|
M^-1 * s^-1 |
Second order |
|
What happens to the reaction of the rate when the number of collisions increases? |
The rate increases |
|
Should the collision energy be greater than or less than the activation energy for the reaction? |
Greater |
|
What happens to the rate if the orientation is very precise? |
Proceeds at a slower rate |
|
If the temperature changes, the ________ will change too. |
Constant |
|
Higher temperatures result in changes in the ________ of collisions, and the ________ energy of these collisions. |
Frequency, average |
|
If the concentration increases, what happens to the rate of the reaction? |
The rate increases as well |
|
If the energy of reactants is SMALLER than the energy of products, the overall reaction is _________. |
Endothermic |
|
If the energy of reactants is GREATER than the energy of products, the reaction is _____________. |
Exothermic |
|
A —> products |
Unimolecular |
|
A + A —> products |
Bimolecular |
|
A + B —> products |
Bimolecular |
|
A + A + A —> products |
Termolecular |
|
A + A + B —> products |
Termolecular |
|
A + B + C —> products |
Termolecular |
|
What is the rate determining step in a reaction? |
The SLOWEST step |
|
__________ appear first as a reactant and then as a product |
Catalysts |
|
__________ appear first as a product and then as a reactant. |
Intermediates |
|
Rate laws are written using ________ only. |
Reactants |
|
0 Celsius |
273.15 K |
|
A catalyst does not affect the position of ___________ of a chemical reaction. |
Equilibrium |
|
A catalyst does not affect the position of ___________ of a chemical reaction. |
Equilibrium |
|
K stands for the… |
Equilibrium constant |
|
Keq >> 1 |
Favors products |
|
Keq <<< 1 |
Favors reactants |
|
K = 1 means… |
K is somewhere between reactants and products but we can’t tell |
|
The larger the k….the farther the reaction proceeds to the _______ before equilibrium is reached |
Right |
|
Q stands for |
Reaction quotient at ANY other point of time but NOT at equilibrium |
|
What do these stand for? - starting point - certain point - when equilibrium is reached |
Key words for Q |
|
Kp stands for….. |
Pressure |
|
Kc stands for….. |
Concentration |
|
If K is small and Q is big, the reaction goes to the ______ side |
Left |
|
If Q is small and K is big, the reaction goes to the _________ side. |
Right |
|
What is the formula used to cancel the x out? |
Ao / K > 400 |
|
If you increase the pressure, you __________ the volume. |
Decrease |
|
The reaction will shift to the _______ side if you increase the pressure and decrease the volume. |
Right |
|
In order to decrease the pressure, you must _______ the volume. |
Increase |
|
If you decease the pressure and increase the volume, the reaction shifts to the _______ side. |
Left |
|
Endothermic q = |
Reaction goes left |
|
Exothermic q = |
Reaction goes to the right |
|
Why doesn’t a catalyst affect the equilibrium of a reaction? |
The addition of a catalyst doesn’t affect the equilibrium of a reaction because a catalyst speeds up both forward and reverse rates. |
|
Why doesn’t a catalyst affect the equilibrium of a reaction? |
The addition of a catalyst doesn’t affect the equilibrium of a reaction because a catalyst speeds up both forward and reverse rates. |
|
HCl |
Strong acid - Hydrochloric acid |
|
Why doesn’t a catalyst affect the equilibrium of a reaction? |
The addition of a catalyst doesn’t affect the equilibrium of a reaction because a catalyst speeds up both forward and reverse rates. |
|
HCl |
Strong acid - Hydrochloric acid |
|
HBr |
Strong acid - hydrobromic acid |
|
HI |
Strong acid- hydroiodic acid |
|
H2SO4 |
Strong acid - sulfuric acid |
|
HNO3 |
Strong acid - nitric acid |
|
HClO4 |
Strong acid - perchloric acid |
|
HClO4 |
Strong acid - perchloric acid |
|
NaOH |
Strong base - sodium hydroxide |
|
LiOH |
Strong base - lithium hydroxide |
|
KOH |
Strong base - potassium hydroxide |
|
Ca(OH)2 |
Strong base - calcium hydroxide |
|
Sr(OH)2 |
Strong base - strontium hydroxide |
|
Ba(OH)2 |
Strong base - barium hydroxide |
|
________ ________ complete dissociate |
Strong acids |
|
________ ________ complete dissociate |
Strong acids |
|
________ ________ partially dissociate |
Strong bases |
|
Why does water dissociate slightly? |
One molecule in half a billion splits into an OH- ion by losing a proton to another water molecule. That other molecule becomes H3O+. |
|
pH = |
- log[H3O+] |
|
[H3O+] = |
10^-pH |
|
pH + pOH = |
14 |
|
pOH = |
-log[OH-] |
|
[OH-] = |
10^-pOH |
|
Kw = |
[H3O+][OH-] |
|
Kw = |
[H3O+][OH-] |
|
pH 0-6 = |
Acidic |
|
Kw = |
[H3O+][OH-] |
|
pH 0-6 = |
Acidic |
|
pH of 7 |
Neutral |
|
Kw = |
[H3O+][OH-] |
|
pH 0-6 = |
Acidic |
|
pH of 7 |
Neutral |
|
pH 8 - 14 |
Basic |
|
Kw = |
[H3O+][OH-] |
|
pH 0-6 = |
Acidic |
|
pH of 7 |
Neutral |
|
pH 8 - 14 |
Basic |
|
Brønsted-Lowry Acid |
Proton (H*) donor |
|
Kw = |
[H3O+][OH-] |
|
pH 0-6 = |
Acidic |
|
pH of 7 |
Neutral |
|
pH 8 - 14 |
Basic |
|
Brønsted-Lowry Acid |
Proton (H*) donor |
|
Brønsted-Lowry Base |
Proton (H+) acceptor |
|
Kw = |
[H3O+][OH-] |
|
pH 0-6 = |
Acidic |
|
pH of 7 |
Neutral |
|
pH 8 - 14 |
Basic |
|
Brønsted-Lowry Acid |
Proton (H*) donor |
|
Brønsted-Lowry Base |
Proton (H+) acceptor |
|
Conjugate base is formed when… |
Acid loses H+ |
|
Conjugate acid is formed when….. |
Base gains H+ |
|
What is an amphiprotic species? |
A species that can act as both an acid or base. |
|
What is an amphiprotic species? |
A species that can act as both an acid or base. |
|
What is the most common anohiprotic species? |
H2O |
|
What is an amphiprotic species? |
A species that can act as both an acid or base. |
|
What is the most common anohiprotic species? |
H2O |
|
K >1 Reaction goes to the ____ side |
Right |
|
K < 1… reaction goes to the _____ side. |
Left |