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51 Cards in this Set

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Evidence for Kekule’s model to be wrong:

 All C-C bond lengths are the same length, between C-C and C=C.
 Only reacts with Br2 with a halogen carrier
 Benzene is lower in energy than Kekule’s structure suggests its should be.
Discuss the structure and bonding in benzene / (comparing to kekule - structure):

Discuss the relative low reactivity of benzene / (problems with Kekule – reactivity):
Discuss the reactivity of benzene compared to alkenes
Discuss the reactivity of phenol compared to benzene
Benzene VS. Cyclohexene
Cyclohexene
 Electrophillic Addition
 Electrons are localised
 Between C-C 2e from  bond and 2e from localised bond = 4e
 Higher electron density, polarises electrophiles more
 Don’t need a halogen carrier
Benzene
 Electrophillic Substitution
 Electrons are delocalised
 Between C-C 2e from  bond and 1 e from the C-C from delocalised bond = 3e
 Lower electron density, polarises electrons less
 Need a halogen carrier
Benzene VS. Phenol
Phenol- Multiple Substitution
 Lone pair of electrons on O
 Delocalise with the  electrons in the Benzene ring
 Makes more electron rich
 Ring becomes activated, polarises electrophiles more
 Phenols do not need a halogen carrier
Benzene- Mono-substitution
 Electrophillic Substitution
 Electrons are delocalised
 Between C-C 2e from  bond and 1 e from pre C-C from delocalised  bond = 3e
 Lower electron density, polarises electrons less
 Need a halogen carrier
Nitration of benzene:
Halogenation of benzene:
Carbonyl Test
Test for Carbonyl Group
 2,4,DNPH (Brady’s Reagent)
 If present, orange precipitate formed
 FILTER, RECRYSTALISE, FILTER, MELTING POINT DETERMINATIO0N / COMPARE TO KNOW DATA
Test to distinguish between Aldehyde and Ketone
 Warm with Tollens Reagent (silver nitrate dissolved in ammonia)
 If aldehyde present, silver mirror forms as the aldehyde is oxidised
 If ketone present no change as ketone cannot be oxidised
Reduction of Aldehydes / ketonesMechanism of reducing an Aldehyde
Azo Dyes
The Azo dye is now stable as there is extensive delocalisation over both arenas via the azo group, -N=N- 
This also gives rise to the colours
The Azo dye is now stable as there is extensive delocalisation over both arenas via the azo group, -N=N-
This also gives rise to the colours
Amines
 A weak base because of lone pair of electrons on N accept protons
 proton acceptors
 lone pair electrons are donated forming a dative covalent bond
Inductive Effect
 Alkyl groups- positive inductive effect – stronger base
 The alkyl group gives a small push of electrons towards LP on the N
 This makes it form a dative covalent bond more readily
 Ammonia - no inductive effect as nothing attached to functional group
 Benzene Ring – Negative inductive effect
 Benzene ring has small pull of electrons away from Nitrogen atom
 The LP electrons are delocalised into the benzene ring
 Makes them less readily available to form a dative covalent bond
 Weaker base
Fatty acid - shorthand:
Trans fats cholesterol:

High Density Lipoproteins
 Carry cholesterol out of the blood and out of the body
 Good
Low Density Lipoproteins
 Carry about 65% of cholesterol around the body and deposit lipids onto artery walls
 This restricts blood flow
 Bad
Making Biodiesel - Transesterification:
 The waste oil is filtered then reacted with methanol and sodium hydroxide (catalyst) to form 
biodiesel. 
 This also increases the atom economy of fats.
 The waste oil is filtered then reacted with methanol and sodium hydroxide (catalyst) to form
biodiesel.
 This also increases the atom economy of fats.
Preparation of Alphatic Amines
 Warm halogenoalkens with excess ammonia
 CH3CH2Cl + NH3 >>> CH3CH2NH2 + HCl
 NH3 + HCl >>> NH4Cl
Preparation of Primary/Secondary aliphatic amines
 CH3CH2NH2 + CH3CH2Cl >>> (CH3CH2)2NH
 (CH3CH2)2NH + CH3CH2Cl >>> (CH3CH2)3N
Isoelectric Point
 Usually PH6 as COOH is slightly more acidic that NH2 is basic
 Depends on side groups, hence the different points
Acid Hydrolysis
 Heat under reflux with 6mHCl for 24 hours
 Always gives COOH and NH3+
Alkali Hydrolysis
 Solution of NaOH, reflux
 Always gives COO-Na+
and NH2
Hydrolysis of Polyesters/Polyamides
 Hot aq Acid/ aq Alkali
 As above for acid / alkali hydrolysis products
Photodegradable polymers
 Blended with light sensitive catalysts so become weak, brittle when exposed to light
 Can also have C=O which absorb UV light and break
 Photodegradable plastics break to form shorter waxy hydrocarbon molecules before bacteria
breaks them further into CO2 and H2O
Chromatography
Chromatography
Stationary phase
 is in a fixed place (paper in paper chromatography)
 molecules interact with stationary phase slowing down their movement – ADSORPTION
Mobile phase
 moved in a definite direction (water rises up in paper chromatography)
 molecules interact with mobile phase speeding up their movement – SOLUBILITY
Thin Layer Chromatography – TLC
 Dissolve sample.
 Draw a pencil line and spot sample using a capillary tube, allow to dry.
 Place plate in a tank of solvent - solvent must be below line, seal the tank.
 Separation is by adsorption - allow solvent to almost reach the top, draw a line here - solvent front.
Limitations of TLC
 Similar compounds often have too similar Rfvalues.
 Unknown compounds have no Rf value for comparison.
 It is hard to find a solvent that will have the correct amount of solubility - Goldilocks!!
Rf Values
Gas Chromatography - GC
Gas Chromatography - GC
 Is used to separate volatile compounds (gases) in a mixture with low boiling points
The stationary phase:
GC
 Depends what is separated whether you use a liquid or solid lining of the chromatography column
 e.g liquid long chain alkane (high boiling point)
 e.g solid silicone polymer
The mobile phase:
GC
 Inert carrier gas e.g helium or nitrogen.
Separation
GC
 Different components slowed by different amounts- separation – retention times
 Each component leaves the column at a different time and is detected as it leaves the column.
 Each peak represents a component
 Area under each peak is proportional to the abundance of each component
Limitations of gas chromatography:
 Similar retention times + peak shapes most compounds cannot be positively identified.
 Not all substances can be separated.
 Unknown compounds have no reference retention times.
Due to the limitations, gas chromatography is usually used in conjunction with spectroscopy.
Uses for GC-MS
1) Forensics - scenes of crime
2) Environmental analysis - air pollutants, waste water, pesticides in food.
3) Airport security - explosives in luggage / airport security
4) Space probes - planetary atmospheres
Chiral Compound
 Optical isomers are one type of Stereo isomers (cis / trans is the other).
 They are non-superimposable
 Chiral carbon has 4 different groups attached
 Always draw in 3D
Properties of optical isomers:
 They rotate plane polarised light.
 One isomer rotates it in one direction and the other in the opposite direction
Problems with Chiral drugs
 One optical isomer may have serious side effects
 Expensive/ difficult to separate isomers
 One optical isomer may have serious side effects
 Reduces the effectiveness
 Dose size
Overcoming Chiral drug synthesis problems
 Use and enzyme catalyst
 Chiral Synthesis
 Chiral Catalyst
 Chiral Pool Synthesis
1) Using enzymes as biological catalysts:
 Nature is steroespecific, if this can be used only one isomer will be produced.
 If a biocatalyst is used it will only catalyse the production of one isomer.
2) Chiral pool synthesis:
 This starts the synthesis pathway with a stereospecific enantiomer
 All of the following synthesis steps should lead to a pure optical isomeric drug
3) Use of transition metal complexes:
 Some act as catalysts that will produce only one optical isomer
Cause of Stereo Isomerism
a) Optical isomerism
C with 4 different groups attatched
Mirror images of each other
b) Cis trans isomerism
 C=C has restricted rotation
 Both C in C=C attached to two different groups
NMR:
Interpretation: always gives you 2 pieces of information
1) splitting pattern – number of adjacent H’s
2) Chemical shift – adjacent functional groups
 If the numbers of H’s are given above the peak, make sure you use these too
D2O
 D replaces H in OH and NH protons
 Peak for OH / NH protons disappears
 This is due to D having 2 nucleons – no signal
TMS
 Reference Signal at 0
Draw the structure of an optically active carboxylic acid with molecular formular of (C6H12O2). with five peaks in its13C n.m.r. spectrum.
(CH3)2CHCH(CH3)COOH