This refres to a reaction in which there is not enough O2 in order to react with atom C in buthane to change into CO2 therefore they will change to carbon monoxide. The oxygen reacts with H to produce H2O these can be defined by incompelete combustion.
Use Markovnikov's Rule to explain why Propan-2-ol is formed during the reaction between propene and steam. (A.C. 2.3)
According to his role if a HX compound was added to an unsymmetrical alkene the H will bond to the compound. As propane is an unsymmetrical alkene and water has Hydrogen OH-H,therefore the H will join the carbon that has more H. This process will lead to production of propan-2-ol.
Describe the cold reaction of but-2-ene with cold KMnO4 (A.C. 2.3)
The potassium manganate(VII) …show more content…
The Ch3 groups can be replaced with the atoms of Cl due to the way Cl atoms have been joined together in the chain (at randon)and their huge size it will not be easy for the chain to lie closely. The polychloroethen has small space of crystallinity and is amorphous.
How can you account for the fact that poly(chloroethene) is much stiffer than poly(ethene)? (2.4)
It believed that the main difference is the Cl molecule that has caused the stiffness in the chloroethane. This is due to bond between carbon and chlorine which is more polar bonds than the carbon and haydron bonds.Therefore there are more polar attractiopn between strands of monomers.
The carbonyl group, C=O, occurs in two homologous series, namely aldehydes and ketones. What is thestructural difference between an aldehyde and a ketone? (A.C. 3.1)
Aldehydes are known as the organic molecules that has a carbonyl group which is bonded to one hydrogen atom(at least) whereas in ketone is known as an organic compound that hold a carbonyl group that are attached and bonded to 2atoms of carbon. Their main difference is the location of the carbonyl
Use Markovnikov's Rule to explain why Propan-2-ol is formed during the reaction between propene and steam. (A.C. 2.3)
According to his role if a HX compound was added to an unsymmetrical alkene the H will bond to the compound. As propane is an unsymmetrical alkene and water has Hydrogen OH-H,therefore the H will join the carbon that has more H. This process will lead to production of propan-2-ol.
Describe the cold reaction of but-2-ene with cold KMnO4 (A.C. 2.3)
The potassium manganate(VII) …show more content…
The Ch3 groups can be replaced with the atoms of Cl due to the way Cl atoms have been joined together in the chain (at randon)and their huge size it will not be easy for the chain to lie closely. The polychloroethen has small space of crystallinity and is amorphous.
How can you account for the fact that poly(chloroethene) is much stiffer than poly(ethene)? (2.4)
It believed that the main difference is the Cl molecule that has caused the stiffness in the chloroethane. This is due to bond between carbon and chlorine which is more polar bonds than the carbon and haydron bonds.Therefore there are more polar attractiopn between strands of monomers.
The carbonyl group, C=O, occurs in two homologous series, namely aldehydes and ketones. What is thestructural difference between an aldehyde and a ketone? (A.C. 3.1)
Aldehydes are known as the organic molecules that has a carbonyl group which is bonded to one hydrogen atom(at least) whereas in ketone is known as an organic compound that hold a carbonyl group that are attached and bonded to 2atoms of carbon. Their main difference is the location of the carbonyl