Answer the following questions. You may use the periodic table in the Chemistry: Problems and Solutions book for this test. When you have finished, submit this assignment to your teacher by the due date for full credit.
(5 points)
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1. Pentane gas (C5H12) combusts with oxygen gas (O2) to form water (H2O) and carbon dioxide (CO2). Write a balanced chemical equation for this reaction and explain the scientific principle (statement) that requires the balancing of an equation to make it conform to reality.
Answer: C5H12 + O2 → H2O + CO2
Balanced – C5H12 + 8 O2 = 6 H2O + 5 CO2
(5 points)
Score
2. Methane (CH4), ammonia (NH3), and oxygen (O2) can react to form hydrogen cyanide (HCN) and water according to this equation:
CH4 + NH3 + O2 HCN + H2O …show more content…
Answer the following questions:
1 What is the balanced equation for this reaction?
2 Which reagent is limiting? Explain why.
3 How many grams of hydrogen cyanide will be formed? Show your work.
Answer:
1) 2 CH4 + 2 NH3 + 3 O2 = 2 HCN + 6 H2O
2) The reagent that is limiting is CH4.
To get the moles of 10g of NH3, you divide 10 by 17 and that equals 0.58. To get the moles of 8g of CH4 you divide 8 by 16 and that equals 0.5. Because you have some more oxygen left over you have to find the limiting reagent. You divide the coefficient by the number of moles, whichever is the smallest number you get is your limiting reagant. Now, you have to divide 0.58 by 2 which equals 0.29, and 0.5 by 2 and that equals 0.25.
3) You multiply 0.5 by 27 and that leaves you with 13.5 grams of hydrogen cyanide that will be formed.
(5
(5 points)
Score
1. Pentane gas (C5H12) combusts with oxygen gas (O2) to form water (H2O) and carbon dioxide (CO2). Write a balanced chemical equation for this reaction and explain the scientific principle (statement) that requires the balancing of an equation to make it conform to reality.
Answer: C5H12 + O2 → H2O + CO2
Balanced – C5H12 + 8 O2 = 6 H2O + 5 CO2
(5 points)
Score
2. Methane (CH4), ammonia (NH3), and oxygen (O2) can react to form hydrogen cyanide (HCN) and water according to this equation:
CH4 + NH3 + O2 HCN + H2O …show more content…
Answer the following questions:
1 What is the balanced equation for this reaction?
2 Which reagent is limiting? Explain why.
3 How many grams of hydrogen cyanide will be formed? Show your work.
Answer:
1) 2 CH4 + 2 NH3 + 3 O2 = 2 HCN + 6 H2O
2) The reagent that is limiting is CH4.
To get the moles of 10g of NH3, you divide 10 by 17 and that equals 0.58. To get the moles of 8g of CH4 you divide 8 by 16 and that equals 0.5. Because you have some more oxygen left over you have to find the limiting reagent. You divide the coefficient by the number of moles, whichever is the smallest number you get is your limiting reagant. Now, you have to divide 0.58 by 2 which equals 0.29, and 0.5 by 2 and that equals 0.25.
3) You multiply 0.5 by 27 and that leaves you with 13.5 grams of hydrogen cyanide that will be formed.
(5