Compare The Molarity Of Ammonia And Vinegar Lab Report

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In this experiment the molarity of ammonia is calculated using the process of titration. A chemical reaction occurs when two or more substances change to form different molecules. In each reaction there are ratios between each reactants. Certain amounts of each reactant are needed to fully complete the chemical reaction. Stoichiometry is the relationship between the quantities of the reactants. An acid is a substance that reacts and donates H+ ions. A base is a substance that accepts H+ ions. An acid that donates more that two H+ ions is polyprotic. In a reaction where an acid and a base react with each other in water till no hydroxide ions remain. Molarity is the concentration of a solution. Molarity is calculable by the following formula …show more content…
In this lab, we conducted a titration of ammonia and vinegar. We gradually added vinegar to a solution of water, ammonia, and our indicator (red cabbage water). The cabbage water is a visible sign of a solution ph level. ph is a measurement of how acidic or alkaline a solution is. A substance with a ph than 7 is a acid, and a substance with ph greater than 7 is a base. The red cabbage will change colors as the acid neutralizes the base. Our cabbage water was initially a magenta, because cabbage water is inherently slightly acidic. After the cabbage water was poured into the ammonia-water mixture the solution rapidly changed to a bottle green. With a red cabbage indicator the stronger the alkali the color the color, and the stronger the acid the warmer the color. A true neutral solution is a shade of violet. As we added vinegar pockets of bright pink flared up in the green solution. When stirred the solution’s color would be distributed. In this manner of gradually adding vinegar and stirring we conducted our

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