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73 Cards in this Set
- Front
- Back
–pinned connections at all joints
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In general, a truss should have:
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–external forces acting only on the joints
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In general, a truss should have:
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–zero moment at each joint
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In general, a truss should have:
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–members subjected only to axial forces
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In general, a truss should have:
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trusses are usually constructed in
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wood or steel. Concrete is possible but generally not practical.
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A rule of thumb in determining truss depth is a depth to span ratio of
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1/10 –1/15
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a 50’span would have a depth of approximately
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3.3’–5’depending on the load
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Trusses can be looked at in several categories:
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planar truss:
two-way truss system: space truss: space frame: |
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two dimensional
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planar truss:
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planar trusses connected perpendicular to each other, forming a truss grid.
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two-way truss system
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three dimensional truss
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space truss:
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space trusses connected to form a three dimensional grid
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space frame:
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two-dimensional in their section and connected with pin joints.
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planar trusses
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framed beam structures having vertical web members rigidly connected to parallel top and bottom chords
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Verendeel Trusses
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Are not true trusses because their members are subject to nonaxial bending forces
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verendeel trusses
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connected with rigid joints
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VierendeelTruss
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resist bendingmomentlike the flanges in a steel beam.
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top and bottom chord of the truss
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top chord is in compression while the bottom chord is in tension.
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like the flanges of a steel beam in a simple span condition, the truss
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The web members in the truss resist
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shear,the same as the web of the steel beam.
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Loads on a truss should be applied at
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the panel points.
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By placing loads at the panel points, forces act
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axially. in all the members of the truss so that members are all in tension or compression.
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Loads applied to the member rather than at the panel point introduces
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bending in the member making it behave like a beam.
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Now the members must resist both bending and axial forces--not very efficient.
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Loads applied to the member
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Uniform loads applied directly to the truss members also introduce
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bending moment into the members.
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secondary members that span between trusses,
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Purlins,
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can be used to transfer uniform loads to the panel points.
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Purlins,
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ideally, forces are distributed axially in tension or compression
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Truss Force Distribution
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forces increase towards the centerwhere bending moment increases in beams.
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top and bottom chord:
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forces increase towards the supportswhere shear increases in beams.
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web members:
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b=
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number of members
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n =
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number of joints
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is stable, generally
(equation) |
b = 2n-3
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is stable but indeterminate
(equation) |
b > 2n-3
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is unstable
(equation) |
b < 2n-3
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In order for the truss assembly to be stable,
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the truss or any part of the truss must be in equilibrium.
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A joint, shown in a free-body, must also be in
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equilibrium
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ΣFV= 0 ΣFH= 0 ΣM = 0
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laws of static equilibrium:
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all joints are pinned with zero moment, in the case of
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trusses,
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Diagonal members have
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both vertical and horizontal components.
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AEach member of the truss has
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axial, tensile or compressive,internal forces.
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the relationship of the
rise to run on the diagonal member determines the relationship between the |
vertical and horizontal
components. |
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find the resulting diagonal force by using the
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Pythagorean Theorem.
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All forces moving to the joint are
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compressive
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All forces moving away from the joint are
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tensile
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A cable with a constant cross section carrying its own
deadweight will form a |
catenary curve
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A cable carrying a uniform load projected horizontally along its length will form a
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parabolic curve.
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Cables can be looked at in several categories:
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–single cable
–double curved cables –cable-stayed |
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Only_____ ______are developed in cable structures
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tension forces
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they offer no resistance to compression or bending.
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cable structures
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the shallower the cable slope,
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the larger the force in the cable
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____ load generates an upward load on the cable (suction).
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wind load
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(wind loads on cable systems)
The shape of the roof changes in response to _______,resulting in ________ Pressure caused by the effect of the wind on the new shape. |
suction,
downward |
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The alternating effects of the wind on the changing shape of the roof cause
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fluttering
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a dynamic and cyclical process.
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fluttering
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-increase dead load
(1 of 4) |
Stabilizing wind loadson simple cable structures to prevent fluttering.:
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-use a stiffened tension element to resist the deformation
(1 of 4) |
Stabilizing wind loadson simple cable structures to prevent fluttering.:
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-use anchor cables to tie the system to the ground
(1 of 4) |
Stabilizing wind loadson simple cable structures to prevent fluttering.:
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-use double-curved cable systems
(1 of 4) |
Stabilizing wind loadson simple cable structures to prevent fluttering.:
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are connected by secondary members.(cables)
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double concave cables, pretensioned cables
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are separated by compression struts. (cables)
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double convex cables,
pretensioned cables |
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Similar to the analysis we looked at in trusses, we can also analyze cables using a series of
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free-body diagrams.
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Each free-body must also be in equilibrium satisfying the laws of
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static equilibrium:
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In the case of cables, all supports are pinned with
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zero moment.
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Unlike truss analysis, cables generally have
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pinned
connections, meaning there are a total of 4 unknown reactions, not 3. |
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A free-body diagram is necessary in determining
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the external reactions.
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Determine the vertical reactions either by ________ or by ____________.
(cable problem 1) |
symmetry
the ΣM at the reaction. |
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The relationship between the vertical and horizontal force components is the same as the
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relationship between the rise and run for the slope of the line.
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general stress formula,
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f = P/A,
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A = P/Ft
what is Ft |
Ft is the allowable tensile stressfor steel cable.
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For a given shape, cable structures only develop _______________________ and no ___________________
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axial tensile forces
no interior bending moment. |
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result in corners
(cable summary) |
pointloads
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horizontally projected, result in parabolic curves
(cable summary) |
uniform loads,
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results in catenary curves
(cable summary) |
self-weight
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