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23 Cards in this Set
- Front
- Back
When implementing an Internal Risk Model, firms often underestimate what three things? |
• Resource Commitment - Staff, Systems, Software • Timelines • Organization impact |
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When implementing an Internal Risk Model - Staff Considerations (6) |
• Reporting Lines should be clear • Leader should have a reputation for Fairness • Functions Represented: U/W, Planning, Finance,Actuarial, Risk • Full Time Staff vs. Part Time Staff (also have day to day job) • Permanent Staff vs. Temporary Staff (for implementation) • think of IRM as a new compentency - need to staff |
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Implementing IRM - Scope considerations? (4) |
• Underwriting Year • Reserves • Assets • Low Detail on Company OR High Detail on pilot segment |
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Parameter Estimation is difficult because: (4) |
• Low Data Quality • Low Data Volume • Unique Characteristics of Firm • Differing Risk Attitudes |
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Correlation Assessment in an IRM is difficult because: (4) |
• Lack of Data • High Political Sensitivity • spans Multiple Business Units • Significant impact on Company Risk Profile and Capital AllocationIRM team recommends correlation assumptionsOwned by CRO/CEO/CUO |
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Why is Validation of an Internal Risk Model difficult?How can we Validate? |
• No current model to compare to • Review a series of complementary variables over an extended period |
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How should a Pilot Test be done for the implementation of an Internal Risk Model? (4) |
• Provide output in parallel to current decision metrics(allows user to get comfortable with new metrics) • High Level of the Company OR Detail of a Pilot Segment • Provide Education on New Metrics • Each Quarter increase Weight that is given to new metrics |
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Recommendations for Integration and Maintentance of an Internal Risk Model (4) |
• Integrate into the Corporate Calendar that already exists • Major Updates - no more than twice a year • Minor Updates - via scaling • Input/Output - Ownership and Control must be very clear |
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Formula for Coefficient of Variation (CV) of Losses |
CV^2 (S) = CV^2(N) + CV^2(X) / µN |
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What is Superimposed Inflation |
Severity Trend less General Inflation [Claim Severity Trend] =[General Inflation] + [Superimposed Inflation] |
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For Projecting Annual Loss Trend, the author recommends an AR(1) processwith what parameters? |
rt+1 = m + α1 · (rt − m) + et+1 α1 = 80% et+1 ∼ Normal(0, 2.5%) |
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What is the preferred method to estimate parameters for Frequency andSeverity Distributions? |
Maximum Likelihood Estimator (MLE) Among Unbiased estimators, it has the lowest Estimation Error (for large data sets) |
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How do the authors recommend we model parameter estimates and theirdependencies |
Model the parameter estimates as Joint LogNormalwith correlations from the Information Matrix |
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When Estimating Parameters how we can estimate correlations |
LL = Log Likelihood of the data set, Given a set ofparameters α I = −∂ ^2 (LL) / ∂^2 α Σ = I−1is the Covariance Matrix |
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What is Model Risk |
Risk that the selected model is not the correct one |
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Why do we prefer to use Joint LogNormal to model estimates of parameters |
• Removes Negative Values from possiblesimulated values • Parameter Estimates have a heavy tail -LogNormal captures this |
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A method to account for Model Risk |
When comparing different models use the HQIC tocompare them • Hannan-Quinn Information Criterion (HQIC) is acompromise on the # of parameters penalty • Multiple models can be chosen for a pool of possiblemodels • For each simulation, draw one of these models, and thenparameters from that model |
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When estimating parameters - we can calculate the Likelihood of the datagiven the selected parameters. What does the slope of the Negative Log Likelihood tell us about ourestimate of the parameters? |
A steep slope tells us we are quite certain of our estimate ofthe parameters A shallow slope tells us we are not certain of our estimate ofthe parameters |
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Formula for Copula Density |
c(u, v) = ∂ ^C(u, v) / ∂u∂v |
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Gumbel τ |
Gumbel τ = 1 −1/a |
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HRT τ |
HRTτ =1/ ( 2a + 1) |
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Frank τ |
FrankComplicated formula with an integral |
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Normal τ |
Normalτ =2 · arcsin(a) / π |