The Midpoint Formula

Front 1

The Midpont Formula

Back 1

If the two coordinates given are (5,2) and (4, 2) than you must apply the formula;
X1 + X2 = 9 → [9/2 = 4.5]
Y1 + Y2 = 4 → [ 4/2 = 2 ]

The midpoint of the coordinates (5,2) and
(4,2) is (4.5, 2).

Front 2

The Distance Formula

Back 2

The distance between two coordinates;
Imagine the coordinates are (2,2) and (5,6)
2-5 = -3 → -3 squared is 9.
2-6 = -4 → -4 squared is 16.
9 + 16 = 25.
the square root of 25 is 5.

Distance = 5

Front 3

The length of a circle sector

Back 3

he length of a circle sector;
sector angle divided by 360.
let's say it is 34 and the radius is 45.2. So, 34/360 = 0.094.
next, you must multiply this by 2(pi)R.
0.094 (283.85) = 26.682
to find the outer sector, you must take 34 away from 360. Then do 326/360 and repeat the process above.

Front 4

Circumference of a circle

Back 4

If the radius of the given circle is 11.25, than the following is applied;
2 (3.14) = 6.28
So, 6.28 multiplied by 11.25 is equal to 70.65.

Circumference = 70.65

Front 5

Area of a circle sector

Back 5

The area of a circle sector;
sector angle divided by 360.
let's say it is 41 and the radius is 22.9. So, 41/360 = 0.113.
next, you must multiply this by
pi(radius squared).
0.113(1,646.64) = 186.07
to find the outer sector, you must take 41 away from 360. Then do 319/360 and repeat the process above.