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239 Cards in this Set

  • Front
  • Back
HYDROGEN
H
HELIUM
He
LITHIUM
Li
BERYLLIUM
Be
BORON
B
CARBON
C
OXYGEN
O
NITROGEN
N
FLUORINE
F
NEON
Ne
SODIUM
NA
MAGNESIUM
Mg
ALUMINIUM
AL
SILICON
Si
PHOSPHOROUS
P
CHLORINE
Cl
SULFUR
S
ARGON
Ar
POTASSIUM
K
CALCIUM
Ca
CHROMIUM
Cr
MANGANESE
Mn
IRON
Fe
NICKEL
Ni
COPPER
Cu
ZINC
Zn
BROMINE
Br
RUBIDIUM
Rb
STRONTIUM
Sr
SILVER
Ag
TIN
Sn
IODINE
I
MERCURY
Hg
BARIUM
Ba
LEAD
Pb
COVALENT BONDS
SHARING ELECTRONS. IT MAKES A MOLECULE.

NONMETAL AND NONMETAL
IONIC BONDS
COMPLETE TRANSFER OF ELECTRON
METAL TO NON METAL
TABLE SALT
ATOMIC NUMBER
NUMBER OF PROTONS
BOTTOM NUMBER-IT NEVER CHANGES
IN A NEUTRAL ATOM THE
PROTONS AND ELECTRONS HAVE EQUAL OPPOSITE CHARGES.
ISOTOPES HAVE SAME____AND MORE OR LESS_______
SAME PROTONS AND ELECTRONS THE NEUTRONS CHANGE IN AN ISOTOPE.
MASS_______ATOMIC NUMBER IS NEUTRONS
MINUS
LAW OF MULTIPLE
PROPORTIONS
TWO OR MORE ELEMENTS MUST BE SAME ELEMENTS IN DIFF PROPORTIONS
LAW OF MULTIPLE PROPORTIONS
NH4 AND NH4CL
ZNO2 AND ZN CL2
NO AND NO2 *******
CH4 AND CO 2
LAW OF MULTIPLE PROPORTIONS
SO AND SO2 *******
H2O AND C12H2O11
H2SO4 AND H2S
KCL AND PCLO2
DALTON'S THEORY
KNOW BY HEART
EACH ELEMENT MADE UP OF TINY PARTICLES
THE ATOMS OF A GIVEN PARTICLE ARE IDENTICAL
DALTONS THEORY CONT.
CHEMICAL COMPOUNDS ARE FORMED WHEN ATOMS COMBINE WITH EACHOTHER
DALTONS THEORY C
CHEMCIAL REACTION INVOLVE REORGANIZATION OF THE ATOMS.
Which one of the following is not one of the postulates of Dalton’s atomic theory?
Each element is composed of tiny, indivisible particles called atoms
All atoms of a given element are identical to each other and different from those of other elements
During a chemical reaction, atoms are changed into atoms of different elements
Compounds are formed when atoms of different elements combine
Atoms of an element are not changed into different types of atoms by chemical reactions
DURING A CHEMICAL REACTION ATOMS ARE CHANGED INTO ATOMS OF DIFFERENT ELEMENTS
Which one of the following is not one of the postulates of Dalton’s atomic theory?
Atoms are composed of protons, neutrons and electrons
All atoms of a given element are identical; the atoms of different elements are different and have different properties
Atoms of an elements are not changed into different types of atoms by chemical reactions: atoms are neither created nor destroyed in chemical reactions
Compounds are formed when atoms of more than one element combine; a given compound always has the same relative number and kind of atoms
Each element is composed of extremely small particles called atoms
ATOMS ARE COMPOSED OF PROTONS,NEUTRONS, AND ELECTRONS
WHAT DID JJ THOMSON DO
POSTULATED THE EXSISTENCE OF ELECRONS(USING THE CATHODE RAY TUBE) AND SAID THEY WERE - CHARGED AND HE DETERMINED CHARGE TO MASS RATIO.
JJ THOMSON
KNEW ELECTRONS WERE NEGATIVELY CHARGED AND THAT THERE WAS A CHARGE TO MASS RATIO
ROBERT MILLIKEN DETERMINED
THE ACTUAL CHARGE TO MASS RATION AND THE MASS OF AN ELECTRON
RUTHERFORD WANTED PROVE THE PLUM PUDDING THEORY
PROVED INSTEAD IT WASN'T RIGHT BECAUSE THE BEAM DIDN'T GO DIRECTLY THROUGH, AND SO DISCOVERED THE NUCLEUS
RUTHERFORD IS RESPONSIBLE FOR THE
MODERN VIEW OF THE ATOM
. The first scientist to show that atoms emit any negative particles was
a) J. J. Thomson.
b) Lord Kelvin.
c) Ernest Rutherford.
d) William Thomson.
e) John Dalton
J J THOMSON
The scientist whose alpha-particle scattering experiment led him to conclude that the nucleus of an atom contains a dense center of positive charge is
a) J. J. Thomson.
b) Lord Kelvin.
c) Ernest Rutherford.
d) William Thomson.
e) John Dalton
RUTHERFORD
. Rutherford’s experiment was important because it showed that:
a) radioactive elements give off alpha particles.
b) gold foil can be made to be only a few atoms thick.
c) a zinc sulfide screen scintillates when struck by a charged particle.
d) the mass of the atom is uniformly distributed throughout the atom.
e) an atom is mostly empty space
THE ATOM IS MOSTLY EMPTY SPACE
PERIODIC TABLE TO THE LEFT OF THE STAIR STEP IS _____ AND THE RIGHT IS
TO THE LEFT IS METALS AND THE RIGHT IS NON-METALS
THE RIGHT OF THE STAIR STEP HAD _______BONDING
COVALENT IS METAL TO METAL WHICH IS ALSO MOLECULES
THE LEFT OF THE STAIR STEP HAS _______BONDING
IONIC BONDING IS NONMETAL TO METAL
IN THE PERIODIC TABLE WHICH COLUMNS ARE THE MAIN GROUP ELEMENTS
1ST TWO AND LAST 6
THE MIDDLE BLUE PORTIONS OF THE TABLE IS CALLED WHAT
TRANSITION METALS
WHAT ARE THE BOTTOM TWO ROWS OF THE PERIODIC TABLE CALLED
RARE EARTH MINERALS
CATION
POSITIVE ION
ANION
NEGATIVE ION
IONIC BONDING
FORCE OF ATTRACTION BETWEEN OPPOSITLY CHARGED IONS.
ELEMENTS ARE CLASSIFIED BY
PROPERTIES AND ATOMIC NUMBER
GROUPS ARE VERTICAL OR HORIZONTAL
VERTICAL
1A
ALKALI METALS
2A
ALKALI EARTH METALS
7A
HALOGENS
8A
NOBLE GASSES
PERIODS ARE HORIZONTAL OR VERITCAL
HORIZONTAL
THE NUCLEUS IS VERY SMALL AND CONTAINS
ALMOST ALL OF THE MASS OF THE ATOM
THECHEMISTRY FROM THE ATOM RESULTS FROM ITS
ELECTRONS
ELECTRON MAKE UP MOST OF THE ____________ OF AN ATOM
VOLUME
THE ______AND __________ OF THE ELECTRON IS WHAT GIVES VARIATION TO AN ATOM
NUMBER AND ARRANGEMENT
HALOGENS NEED TO GAIN OR LOSE AN ELECTRON TO BE LIKE A NOBEL GASS
HALOGENS NEED TO GAIN, THAT MEANS LOSE 1 ELECTRON
THE CHARGE FOR THE ENTIRE HALOGEN COLUMN IS
-1 THAT MEANS THAT GAIN 1 ELECTRON
THE OXYGEN COLUMN NEEDS TO GAIN OR LOSE
OXYGEN NEEDS TO GAIN 2 ELECTRONS SO THEY ARE
-2
NITROGEN NEEDS TO GAIN OR LOSE HOW MANY ELECTRONS TO BE PURE
NITROGEN NEEDS TO GAIN 3, WHICH IS -3
CARBON NEEDS TO GAIN OR LOSE HOW MANY ELECTRONS
CARBON NEEDS TO GAIN 4
WHICH IS -4
DO THE METALS NEED TO GAIN OR LOSE ELECTRONS TO BE MORE LIKE THE NOBLE GASSES?
THE METALS NEED TO LOSE ELECTRONS WHICH MEANS +1,+2,+3
BINARY COMPOUNDS
USE ELEMENTAL NAME FOR THE 1ST ELEMENT AND 2ND ELEMENT END "IDE"
COMPOSED OF ATOMS OF 2 DIFFERENT ELEMENTS-TWO METALS FAR RIGHT OF TABLE
1, 2, 3, 4, 5, 6, 7
MONO,DI,TRI,TETRA,PENTA,HEXA,HEPTA
BINARY COMPOUND METAL AND A NONMETAL
NAMED METAL FIRST AND THEN NONMETAL "IDE" ON THE END OF NONMETAL
NH4+

POLYATOMIC IONS
AMMONIUM
CN-

POLYATOMIC IONS
CYANIDE
OH-

POLYATOMIC IONS
HYDROXIDE
H*

CATIONS
HYDROGEN
Li+


CATIONS
LITHIUM
NA+

CATIONS
SODIUM
K+


CATIONS
POTASSIUM
Rb*


CATIONS
RUBIDIUM
Mg2+


CATIONS
MAGNESIUM
Ca2+

CATIONS
CALCIUM
Sr2+


CATIONS
STRONTIUM
Ba2+

CATIONS
BARIUM
Al3+

CATIONS
ALUMINUM
Ni2+

CATIONS
NICKEL
ZN2+


CATIONS
ZINC
FE3+

CATIONS
IRON III OR FERRIC
FE2+
IRON II OR FERROUS
Cu2+


CATIONS
COPPER II OR CUPRIC
Cu1+


CATIONS
COPPER I OR CUPROUS
Pb4+


CATIONS
LEAD (IV) OR PLUMBIC
Pb2+


CATIONS
LEAD II OR PLUMBOUS
Sn4+

CATIONS
TIN IV OR STANNIC
Sn2+

CATIONS
TIN II OR STANNOUS
Hg2+


CATIONS
MERCURY II OR MERCURIC
ZN2+


CATIONS
ZINC
FE3+

CATIONS
IRON III OR FERRIC
FE2+
IRON II OR FERROUS
Cu2+


CATIONS
COPPER II OR CUPRIC
Cu1+


CATIONS
COPPER I OR CUPROUS
Pb4+


CATIONS
LEAD (IV) OR PLUMBIC
Pb2+


CATIONS
LEAD II OR PLUMBOUS
Sn4+

CATIONS
TIN IV OR STANNIC
Sn2+

CATIONS
TIN II OR STANNOUS
Hg2+


CATIONS
MERCURY II OR MERCURIC
F-


ANIONS
FLUORIDE
Cl-

ANIONS
CHLORIDE
Br-


ANIONS
BROMIDE
I-

ANIONS
IODIDE
H-



ANIONS
HYDRIDE
O2-

ANIONS
OXIDE
S2-
ANIONS
SULFIDE
N3-

ANIONS
NITRIDE
P3-


ANIONS
PHOSPHIDE
C4-

ANIONS
CARBIDE
TERNARY COMPOUNDS
COMPOSED OF 3 OR MORE COMPOUNDS-USUALLY NEGATIVE IONS CALLED POLYATOMIC IONS
MnO4-

POLYATOMIC IONS
PERMANGANATE
C2H3O2-

POLYATOMIC IONS
ACETATE
NO3-

POLYATOMIC IONS
NITRATE
NO2-

POLYATOMIC IONS
NITRITE
2-
CO3

POLYATOMIC IONS
CARBONATE
2-
SO4

POLYATOMIC IONS
SULFATE
2-
SO3

POLYATOMIC IONS
SULFITE
2-
S2O3

POLYATOMIC IONS
THIOSULFATE
3-
PO4

POLYATOMIC IONS
PHOSPHATE
3-
CrO4

POLYATOMIC IONS
PHOSPHATE
2-
CrO4

POLYATOMIC IONS
CHROMATE
2-
Cr2O7

POLYATOMIC IONS
DICHROMATE
ClO-

POLYATOMIC IONS
HYPOCHLORITE
ClO2-

POLYATOMIC IONS
CHLORITE
ClO3-


POLYATOMIC IONS
CHLORATE
ClO4-

POLYATOMIC IONS
PERCHLORATE
BrO-

POLYATOMIC IONS
HYPOBROMITE
BrO2-

POLYATOMIC IONS
BROMITE
BrO3-

POLYATOMIC IONS
BROMATE
BrO4-

POLYATOMIC IONS
PERBROMATE
IO-


POLYATOMIC IONS
HYPOIODITE
IO2-

POLYATOMIC IONS
IODITE
IO3-

POLYATOMIC IONS
IODATE
IO4-

POLYATOMIC IONS
PERIODATE
BINARY ACIDS-WATER SOULUTIONS OF COMPOUNDS COMPOSED OF _______ AND _____
WATER SOULUTIONS OF COMPOUNDS COMPOSED OF HYDROGEN AND A NONMETAL
HF

BINARY ACIDS
HYDROFLUORIC ACID
HCl

BINARY ACIDS
HYDROCHLORIC ACID
HBr

BINARY ACIDS
HYDROBROMIC ACID
HI

BINARY ACIDS
HYDROIODIC ACID
H2S

BINARY ACIDS
HYDROSULFURIC ACID
2.54 cm
1 inch
453.6 g
1 pound
1 L
1.06 qt
A digit that must be estimated is called ------. A measurement always has some degree of uncertainty
A digit that must be estimated is called UNCERTAIN. A measurement always has some degree of uncertainty
Accuracy refers to
Accuracy refers to the agreement of a particular value with the true value
A measurement always has some degree of
uncertainty
Precision refersto the.
degree of agreement among several elements of the same quantity.
5. A titration was performed to find the concentration of hydrchloric acid with the following results:
Trial Molarity
1 1.25 +/- 0.01
2 1.24 +/- 0.01
3 1.26 +/- 0.01
The actual concentration of HCl was determined to be 1.000 M; the results of the titration are :
Both accurate and precise
Accurate but imprecise
Precise but inaccurate
Both inaccurate and imprecise
Accuracy and precision are impossible to determine with the available information
Precise but inaccurate. All are in the same area but not in the right area
Accurate
To the true value
Precise
able to reproduce.

IF you can reproduce it you have precision.
Rules for Counting Significant Figures - Overview
1. Nonzero integers
2. Zeros
leading zeros (0.0025)
captive zeros (1.008)
trailing zeros
(100 has one sig fig while
1.00 x 102 has three sig figs or
100. has three sig figs)
3. Exact numbers
Nonzero integers always count as significant figures.
3456 has
4 SIG FIGS
Leading zeros do not count as
significant figures.
0.0486 has
3 SIG FIGS
Captive zeros always count as
significant figures.
16.07 has
4 SIG FIGS
Trailing zeros are significant only
if the number contains a decimal point.
9.300 has
4 SIG FIGS
Exact numbers have an infinite number of significant figures.
1 inch =
2.54 cm EXACTLY
Express 0.000543 in exponential notation
5.43 x 10-4********
5.43 x 10-6
54.3 x 10-5
54.3 x 10-3
543 x 10-3
Express 784000000 in exponential notation
7.84 x 106
7.84 x 108********
78.4 x 107
784 x 106
784 x 107
Multiplication and Division: # sig figs in the result equals the number in the least precise measurement used in the calculation.
6.38  2.0
12.76  13 (2 sig figs)
Addition and Subtraction: # sig figs in the result equals the number of decimal places in the least precise measurement.
6.8 + 11.934 =
here it is one place passed the deciam
18.734=18.7
3.SIG FIGS
For addition, answer is one past the decimal like equation
Using the rules of significant figures, calculate the following:
6.167 + 83/
5.10
so add 6.167+83=89.167 so no places past zero because 83 has none past zero so it is 89/5.10=17.450 89 has 2 and 5.10 has three, so 2 is less than 3 so answer is expressed in 2 so answer is 17
Using the rules of significant figures, calculate the following:
4.0021 – 0.004
3.998*** same number past the decimal
4
3.9981
4.00
4.0
1 kilo
is 1000 liter
1 gram
is 1000 miligram or kilogram
1 meter
1000mm or 100 cm
MIXTURES HAVE
VARIABLE COMPOSITION
homogeneous mixture
IS A SOLUTION LIKE VINEGAR
heterogeneous mixture
NOT UNIFORM TO THE NAKED EYE LIKE RANCH DRESSING
COMPOUND
A substance with a constant composition that can be broken down into elements by chemical processes.
ELEMENT
: A substance that cannot be decomposed into simpler substances by chemical means
PURE SUBSTANCES
CAN BE BROKEN DOWN INTO OR ELEMENTS BYCHEMICAL METHODS.
1 m
1 meter
1.094 yards
2.54 centimeters

2.54 cm
1 inch
1 kg
1 kilogram
2.205 pounds

2.205 lbs.
453.6 g

453.6 grams
1 pound
1 L

1 liter
1.06 quarts
3
1 ft
one foot cubed
28.32 liters
miles to centimeters
160934.4 cm
1 mile
1 mile
160934.4 cm-centimeters
one meter
1 m
3.2808399 ft
one mL
equals 1cm cubed
one mile
1.61 km
Total kelvins
Tk=total Celsius + 273.15
Total Farenheit
TF=Total celsius times 9/5+32
Total Celsius
TC= Total Farenheit -32 times 5/9
mega M 1,000,000
mega is a million 10 to the 6th
kilo is k 1000
kilo is 1000, 10 to the 3
hecto is h it is 100
hecto is 100 10 to the 2nd
deka is da 10
deka is 10 to the 1st, da
one is 1
ten to zero
deci is d it is 0.1
deci is 0.1 or 10-1
centi is c it is0.01
centi 0.01 or 10-2
mili is m it is 0.001
mili is 0.001 or 10-3
micro is u it is 0.000001
micro is 10-6
nano is n it is 0.000000001
nano is 10-9
How many yards in 1 meter?
1.094 yards = 1 meter
How many feet in 1 meter?
3.2808399 feet = 1 meter
1 meter=100 centimeters=1000 milliters
1000 mililiters=1 meter
100 centimeters =1 meter
how many cm in an inch?
2.54 cm in an inch
WHat does 1 ft cubed equal in liters
1 foot cubed = 28.32 L
What does one quart = in mililiters?
one quart = .946 mililiters
1 mile in kilometers?
1.61 km = 1 mile
1 mile in in centimeters?
160934.4 centimeters in a mile
1 mile in yards?
1760 yards in a mile
how many kilograms in a pound
2.205 kilograms in a pound
how many grams in a pound
453.6 grams in a pound
how many yards in a meter
1.094 yards in a meter
how many yards in a mile
1760 yards in a mile
density is mass over volume
D=m/v
grams per liter is density
Carbon atomic mass = 12.01 amu
1 mole of anything = 6.022  10 to the 23 units of
substance
Avogadro’s number equals 6.022  10 top the 23 units
A substance’s molar mass (molecular weight) is the mass in grams of one mole of the compound
Percent Composition
Mass percent of an element:
mass % = mass of element in compound over mass of compound times 100%
molecular formula = (empirical formula)n
[n = integer]
molecular formula = C6H6 = (CH)6
empirical formula = CH
molecular formula = (empirical formula)n
[n = integer]
molecular formula = C6H6 = (CH)6
empirical formula = CH
Empirical Formula Determination
1. Base calculation on 100 grams of compound.
2. Determine moles of each element in 100 grams of compound.
3. Divide each value of moles by the smallest of the values.
4. Multiply each number by an integer to obtain all whole numbers.
A representation of a chemical reaction:
C2H5OH + 3O2  2CO2 + 3H2O
reactants products
A representation of a chemical reaction:
C2H5OH + 3O2  2CO2 + 3H2O
reactants products
C2H5OH + 3O2  2CO2 + 3H2O
The equation is balanced.
1 mole of ethanol reacts with 3 moles of oxygen
to produce
2 moles of carbon dioxide and 3 moles of water
C2H5OH + 3O2  2CO2 + 3H2O
The equation is balanced.
1 mole of ethanol reacts with 3 moles of oxygen
to produce
2 moles of carbon dioxide and 3 moles of water
Calculating Masses of Reactants and Products
1. Balance the equation.
2. Convert mass to moles.
3. Set up mole ratios.
4. Use mole ratios to calculate moles of desired substituent.
5. Convert moles to grams, if necessary.
Solving a Stoichiometry Problem
1. Balance the equation.
2. Convert masses to moles.
3. Determine which reactant is limiting.
4. Use moles of limiting reactant and mole ratios to find moles of desired product.
5. Convert from moles to grams