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10 Cards in this Set

  • Front
  • Back

Oxidising agents

1. Get reduced


2. Types:


- KMnO4


- K2Cr2O7


- H2O2


- Cl2(Halogens tend to gain electrons due to high electronegativity)





KMnO4

1. Observation: Purple→colourless


2. Ionic equation:


MnO4-(aq) + 8H+(aq) + 5e-→ Mn2+(aq) +4H2O(l)


3. Use: Test for reducing agents

K2Cr2O7

1. Observation: Orange→Green


2. Ionic equation:


K2Cr2O7 2-(aq) + 14H+(aq) +6e-= 2Cr3+ +7H2O(l)3. Use: Test for reducing agents

H2O2

1. Observation: Orange→Green


2. Ionic equation:


H2O2(l) + 2H(aq) + 2e-(aq) → 2H2O(l)


3. both oxidising and reducing

Chlorine

1. Observation: Solution turns darker in color when reacted with bromide or iodide


2. Ionic equation: Cl2(g) + 2e-(aq) → 2Cl-(aq)


3. Use: Oxidises 3Br- to Br2 and 2I- to I2

Reducing agents

1. Get oxidised


2. Types:


- Potassium Iodide(aq)


- Reactive metals


- Hydrogen



KI

1. Observation: Solution turns brown


2. Ionic equation:


2I-(aq) → I2 + 2e- (reacts with Cl2)


3. Use: Test for oxidising agents



Reactive Metals, e.g. Al, Zn

1. Observation: Less reactive metals are produced


2. Use: Displacement of less reactive metals

Hydrogen

1. Observation (Reacts with CuO): Reddish-brown solid(Cu) is formed


2. Use: Reduces copper(II) oxide to copper

Disproportionation Reaction (spelling!)

1. Examples


- 2H2O2(l) → 2H2O(l) +O2(g)


(H2O2, O)


- Cu2O(s) + H2SO4(aq) → Cu(s) +CuSO4(aq) + H2O(l)


(Cu2O, Cu)


2. Definition: A disproportionation reaction occurs when a substance is both oxidised and reduced simultaneously to form two different products.