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### 13 Cards in this Set

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 Give Eqn for Snell's Law Snell's law Give Eqn for total internal refraction What must be true for total internal refraction? total internal refraction n1 > n2, there is no TIR when n1 is smaller like when light goes from air to water Give 2 eqns for photon energy E=hf=hc/λ Give Mirror eqn. Define variables and what values correspond to what location relative to the mirror do= distance of object from mirror. di= distance of image from mirror += in front (concave) -= behind (convex) df= focal distance from mirror += concave mirror=in front -= convex mirror=behind What type of image is +i for mirrors? Negative? + i values indicate a real, inverted image in a mirror - values indicate a virtual, upright image Give lens power eqn. Define variable location relative to lens, describe how it is related to a mirror P=1/f +f= behind lens of lens (convex) ie your eye's convex lens puts Focal point at retina opposite side as object -F= in front of lens (diverging) For a mirror +F is in front of mirror, same side as object -F is behind the mirror, opposite of object What is another name for a converging lens? Where is the focal point and what value does it have? Where and what type is the image? Is the object + or - distance? Convex Lens F= is behind the lens and is + Image= real and inverted on the opposite side of the lens The object is always positive on, regardless of F What is another name for a diverging lens? Where is the focal point and what value does it have? Where and what type is the image? Concave Lens F= is in front of the lens and is - Image= is real and on the opposite side of the lens as the object What is a rule of thumb for lens? Treat the mirror eqn the same except the values of i and F are flipped as if the backside of the lens is a mirror. What is lens power measured in? D, diopters Give magnification eqn and what the value indicate. M=-i/o +m=upright image -m=inverted image What does a decrease in power indicate about a focal distance? increase in focal Inverse relationship If a object is very far away, where does the image appear? Using mirror eqn. 1/f = 1/o + 1/i so if o is far: 1/f = 1/i thus i = f so the image appears on the retina