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13 Cards in this Set

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  • Back
Give Eqn for Snell's Law
Snell's law
Give Eqn for total internal refraction

What must be true for total internal refraction?
total internal refraction

n1 > n2, there is no TIR when n1 is smaller like when light goes from air to water
Give 2 eqns for photon energy
Give Mirror eqn.

Define variables and what values correspond to what location relative to the mirror
do= distance of object from mirror.

di= distance of image from mirror
+= in front (concave)
-= behind (convex)

df= focal distance from mirror
+= concave mirror=in front
-= convex mirror=behind
What type of image is +i for mirrors?

+ i values indicate a real, inverted image in a mirror

- values indicate a virtual, upright image
Give lens power eqn.

Define variable location relative to lens, describe how it is related to a mirror

+f= behind lens of lens (convex)
ie your eye's convex lens puts Focal point at retina opposite side as object
-F= in front of lens (diverging)

For a mirror
+F is in front of mirror, same side as object

-F is behind the mirror, opposite of object
What is another name for a converging lens?

Where is the focal point and what value does it have?

Where and what type is the image?

Is the object + or - distance?
Convex Lens

F= is behind the lens and is +

Image= real and inverted on the opposite side of the lens

The object is always positive on, regardless of F
What is another name for a diverging lens?

Where is the focal point and what value does it have?

Where and what type is the image?
Concave Lens

F= is in front of the lens and is -

Image= is real and on the opposite side of the lens as the object
What is a rule of thumb for lens?
Treat the mirror eqn the same except the values of i and F are flipped as if the backside of the lens is a mirror.
What is lens power measured in?
D, diopters
Give magnification eqn and what the value indicate.

+m=upright image
-m=inverted image
What does a decrease in power indicate about a focal distance?
increase in focal

Inverse relationship
If a object is very far away, where does the image appear?
Using mirror eqn.
1/f = 1/o + 1/i
so if o is far:
1/f = 1/i thus i = f
so the image appears on the retina