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13 Cards in this Set
- Front
- Back
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Give Eqn for Snell's Law
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Snell's law
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Give Eqn for total internal refraction
What must be true for total internal refraction? |
total internal refraction
n1 > n2, there is no TIR when n1 is smaller like when light goes from air to water |
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Give 2 eqns for photon energy
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E=hf=hc/λ
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Give Mirror eqn.
Define variables and what values correspond to what location relative to the mirror |
do= distance of object from mirror.
di= distance of image from mirror += in front (concave) -= behind (convex) df= focal distance from mirror += concave mirror=in front -= convex mirror=behind |
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What type of image is +i for mirrors?
Negative? |
+ i values indicate a real, inverted image in a mirror
- values indicate a virtual, upright image |
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Give lens power eqn.
Define variable location relative to lens, describe how it is related to a mirror |
P=1/f
+f= behind lens of lens (convex) ie your eye's convex lens puts Focal point at retina opposite side as object -F= in front of lens (diverging) For a mirror +F is in front of mirror, same side as object -F is behind the mirror, opposite of object |
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What is another name for a converging lens?
Where is the focal point and what value does it have? Where and what type is the image? Is the object + or - distance? |
Convex Lens
F= is behind the lens and is + Image= real and inverted on the opposite side of the lens The object is always positive on, regardless of F |
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What is another name for a diverging lens?
Where is the focal point and what value does it have? Where and what type is the image? |
Concave Lens
F= is in front of the lens and is - Image= is real and on the opposite side of the lens as the object |
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What is a rule of thumb for lens?
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Treat the mirror eqn the same except the values of i and F are flipped as if the backside of the lens is a mirror.
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What is lens power measured in?
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D, diopters
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Give magnification eqn and what the value indicate.
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M=-i/o
+m=upright image -m=inverted image |
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What does a decrease in power indicate about a focal distance?
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increase in focal
Inverse relationship |
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If a object is very far away, where does the image appear?
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Using mirror eqn.
1/f = 1/o + 1/i so if o is far: 1/f = 1/i thus i = f so the image appears on the retina |
