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78 Cards in this Set

  • Front
  • Back

Ideal Gas Law

PV= nRT=NkT

v_rms (root-mean-squared velocity)

sqrt[3kT/m]

U_thermal

N*f*kT/2 where f is degrees of freedom

First Law of Themodynamics

▲U = Q + W

"quasistatic"

a volume change process slow enough that the gas is continually in equilibrium during the process

Quasistatic Work

W= – P▲V for constant pressure, or
W= – ∫P(V) dV from V_i to V_f if P(V) known

isothermal

▲T=0 —>▲U = 0 . Often this process is slow enough to treat quasistatically for calculating work.

Adiabatic

Q=0, no Heat —>▲U = W

PV^(gamma) = constant ( use to solve work by treating as quasistatic)

Adiabatic exponent (\gamma)

\gamma = (f+2)/f where f is the degrees of freedom

heat capacity

heat per degree temperature increase,
C ≡ Q/▲T =(▲U-W)/▲T

Heat capacity at constant volume

constant volume implies zero work thus,

C_V = (▲U/▲T)_v = (∂U/ ∂T)_v for infinitesimal

change where _v indicates constant volume

Heat capacity at constant pressure

C_p = ([▲U - (-P▲V)] /▲T)_p
= (∂U/∂T)_p+P(∂V/∂T)_p

For ideal gas, (∂U/∂T)_p= (∂U/∂T)_v thus
C_p = C_v+Nk

Microstate

One possible state

Macrostate

the number of unique states, not counting degeneracies

Multiplicity

the number of degenerate Microstates corresponding to a given Macrostate

Paramagnet

a material which is magnetically active and aligns parallel to any external B-field

Einstein Solid

a model of solids in which each atom is 3 seperate yet identical oscillators with quantized energy

Fundamental assumption of Stat Mech

In an isolated system in thermal equilibrium, all accessible microstates are equally probable.

Stirling's Approximation (including the pi, his only contribution)

ln(N!)= NlnN - N + ½ln(πN) or

N!= N^N*e^(–N)*sqrt (πN)

Second Law of Thermodynamics

"Multiplicity tends to increase."
"Entropy tends to increase."
"You can't win."

Irreversible and Reversible

Irreversible processes create new Entropy. Isentropic (▲S = 0) implies a Reversible process because no entropy was created, so reversing the process doesn't violate 2nd Law

Entropy

S ≡ k ln Ω

S= -(∂F/∂T)_V,N


S= -(∂G/∂T)_P,N

Temperature

1/T ≡ (∂S/∂U)_N,V

Temperature is the quantity that's the same in thermal equilibrium.

Pressure

P ≡= T (∂S/∂V)_U,N



Pressure is the quantity that is the same for systems in mechanical equilibrium.

Chemical Potential ( µ )

µ ≡ – T (∂S/∂N)_U,V


Quantity that's the same for systems in diffusive equilibrium (particles being shared)

change in Entropy

dS = dU/T = Q/T for a quasistatic process (or when W=0)

Often written ▲S = Q/T when finite change is considered under constant temperature. Otherwise
dS = C_v*dT/T if temperature is varying, and you integrate to get ▲S

Third Law of Thermodynamics

C_v –> 0 as T –> 0
As T –> 0, S –> S(0), residual entropy

A more conceptual formulation is given as follows: The rate change in entropy goes to 0 as T goes to 0, thus S=0 is unattainable in finite time intervals (read reality), thus T=0 K is impossible.

Magnetization

M = - U/B where B is the magnitude of the B-field

Quasistatic Heat

Q = Tds for a quasistatic process

Thermodynamic Identity (IMPORTANT)

dU = TdS - PdV + µdN

Setting various things to 0 (dt= 0 etc) also you to rederive the formulas for these three important quantities, T, P, and µ.

Efficiency of an Engine ( e )

e = W/ Q_h where Q_h is the heat absorbed.


More useful though, using W = Q_h - Q_c,

e = 1 - Q_c/Q_h where Q_c is the heat expelled to the cold reservoir. Entropy considerations give the inequality

e ≤ 1 – T_c/T_h


Work in an Engine

Q_h=W+Q_c with both Q's taken to be positive

Carnot Cycle

A cycle of two adiabats and two isotherms that achieves maximum theoretical value of efficiency, e = 1 – T_c/T_h

Coefficient of Performance (COP)

COP = Q_c/W = 1/(Q_h/Q_c – 1) . Used to rate Refrigeration processes.

Curie's Law

M 1/T which holds at high T limits for all paramagnets.

Rankine Cycle

Standard cycle utilized in Steam Engines

Otto Cycle

4 and 2 Strokes Engines use this cycle where a gas is adiabatically compressed, ignited by a spark(plug) pushing the piston during expansion, waste is expelled and new fuel injected. Rinse repeat

Diesel Cycle

Compress air to temperatures hot enough such that upon injection of fuel, it immediately ignites pushing the piston. Generally tuned to maintain near constant pressure throughout the cycle.

Throttling

A process where a gas is forced through a porous plug or a very small valve . Enthalpy remains constant during this process.

The attractive potential (-U_potential) generally dominates the repulsive (see exceptions). It's negative , but becomes less negative as pressure drops and the distance between molecules increases. Energy conservation requires the kinetic energy thus drop to compensate, which cools the gas strongly.

Exceptions to Throttling

Throttling processes (Hampson-Linde Cycle) liquefies most gases except Hydrogen and Helium, which will only liquefy if drastically cooled before the throttling process. Intermolecular attraction for these two gases is much too small, collisions dominate INCREASING temperature in this process unless molecules are moving sufficiently slow (read cold).

Laser Cooling

Absolutely badass.

Basically a low density cloud of atoms is shot at by a laser of frequency slightly below the threshold within which the atoms will absorb the photons. Atoms moving toward the laser see doppler shifted light and absorb a photon, then spontaneously emit it. In this process momentum is gained. Shine Laser from every direction, and you oppose motion in every direction, causing cooling.

Enthalpy, H

H= U+ PV



Total Energy needed to create a system, and displace the environment to create the space it occupies.

Helmholtz free Energy

F= U- TS

F= -kTlnZ as well



Total work needed to create a system out of nothing (environment provides some energy for free)

Gibbs Free Energy

G= U-TS+PV

Total work you need to do to create a system out of nothing

Thermodynamic Potentials (little memory trick)

Remember, you can derive all the relevant partial derivative relations from the Thermo Identities by setting stuff to 0!

Remember, you can derive all the relevant partial derivative relations from the Thermo Identities by setting stuff to 0!

"Free Energy is a Force toward Equilibrium"

If no particles can enter or leave a system


*At constant energy and volume, S tends to increase (maximized by system)


*At constant temperature and volume, F tends to decrease (minimized by system)
*At constant temperature and pressure, G tends to decrease (minimized by system)

Extensive Quantity

V, N, S, U, H, F, G, mass

If you double the amount of "stuff" these double. If you multiple Extensive quantity with intensive, you get an extensive quantity. Ex/Ex = Intensive Quantity. Ex*Ex = nonsense your doing it wrong. Adding changes nothing but adding Ex+In is again nonsense

Intensive

T, P, µ, density



These things don't double when the amount of "stuff" is doubled.

Interpretation of µ (Chemical Potential)

G = Nµ , chemical potential is just the Gibbs free energy per particle!

Van Der Waals Equation of state
(description not formula)

a qualitative model for understanding real gases. The first correction, a, accounts for short range attractive forces ("stickiness") while the second correction accounts for for the strong short range repulsive forces (molecules have "finite volume" and gas isn't infinitely compressible)

Boltzmann factor

exp[-ßE] (that's a shitty Beta)



ß= 1/kT

Probability in Boltzmann Stats

P(s) = 1/Z exp[-ßE(s)]

where Z is the partition function, the sum of all Boltzmann factors

Average Energy( E-bar)

-1/Z ∂Z/∂ß = -∂/∂ßlnZ



U= NE-bar, so depending on Z, this formula can also yield total energy U (this is up to whether you put the N in the power of Z, or multiply it in later)

Standard Deviation

where E^2-bar is given by taking another derivative with respect to beta (given by Johnson)

where E^2-bar is given by taking another derivative with respect to beta (given by Johnson)

Partition Function for noninteracting, indistinguishable particles

Resolution to Gibb's Paradox, truly indistinguishable particles

Resolution to Gibb's Paradox, truly indistinguishable particles

Gibbs Factor

Like Boltzmann, but allows for particle exchange with reservoir.

Like Boltzmann, but allows for particle exchange with reservoir.

Bosons

Photons, pions, etc. Integer-spin particles that can occupy the same state. Generally all the boson try to get into the lowest available energy state

Fermions

Electrons, Protons, Neutrons, Neutrinos etc. Half-integer spin particles. These can never occupy the same state due to Pauli Exclusion (well that's what its called at least, which is hardly telling of the physics involved).

Fermi-Dirac Distribution

Bose-Einstein Distribution

Fermi Energy

At T=0, n_FD becomes a step function with the cutoff at µ(T=0), which we call the fermi energy. A gas like this is said to be Degenerate
 
 
 

At T=0, n_FD becomes a step function with the cutoff at µ(T=0), which we call the fermi energy. A gas like this is said to be Degenerate




Bulk Modulus

A useful quantity that's easily measured, goes at the change in pressure when the material in compressed, divided by the change in volume:
 

A useful quantity that's easily measured, goes at the change in pressure when the material in compressed, divided by the change in volume:


Density of States

dn/dε : find surface area of 1/8 sphere in momentum space, multiply by dp, divide by the volume of a single momentum state (pi*h/2L)^3. This essentially tells you how many states there are if you go from p to p+dp

Ultraviolet Catastrophe

Basically before well developed QM, because the number of possible wavelengths in an electromagnetic wave is infinite, shouldn't the total thermal energy produced by all these waves be infinite? Of course not, QM tells us that energy of a harmonic oscillator is quantized, and thus higher energy (shorter wavelengths) get exponentially suppressed.

Planck distribution

Essentially the Bose-Einstein Distribution with µ=0 and ε=hf. This makes sense because photons are Bosons, and they can be created and destroyed, thus µ must be 0

Essentially the Bose-Einstein Distribution with µ=0 and ε=hf. This makes sense because photons are Bosons, and they can be created and destroyed, thus µ must be 0

Photons

Spin 1 Bosons. The particles of light. Essentially each photon is a quantum harmonic oscillator that moves through space. Photons have 2 polarizations, so make sure to slip in that factor of 2 when you find U or N from the distribution

Wien's Law

Higher temperatures yield higher energy photons.

Higher temperatures yield higher energy photons.

Stefans' Law

P/A = σT^4

where σ is Stefan-Boltzmann constant "5-6-7-8" 5.67x 10^-8

Blackbody Radiation

Radiation emmited by a non-reflective object. Completely equivalent to the emission of radiation from a hole in a box of radiation. (Essentially Stefan's Law)

Emissivity (e)

A measure of how reflective a surface is. 1 is a perfect blackbody, 0 is a perfectly reflective surface. Modifies Stefan's Law:



P/A =σeT^4

Phonons

Spin 0 Bosons (unless Transverse). "Particles" of oscillation in a solid. Essentially these are embodiments of the modes of oscillation of coupled oscillators. Waves in solid analogous to waves of light, phonons analogous to photons.

Debye Approximation

Peter Debye basically said that summing over arbitrary shapes of the crystal lattice (which determines the shape of "n-space") is too hard, so let's pretend its a sphere, convert the sum to an integral in spherical cords and bam, its solvable. Magically, this approximation is exact in both low and high temperature limits.

Bose-Einstein Condensation (BEC)

The tendency for bosons below a certain temperature (called the condensation temperature T_c) to aburtly accumulate in the ground-state (lowest energy state). At low temperatures, µ is very small, and ε_0 is very small, so the distribution favors ground state (ridiculously favors).

Superfluid

The superfluid component is an example of a BEC. The superfluid atoms are constantly moving to the lowest available state, and so behave in mind-blowing ways.

Curie Temperature

Temperature at which a ferromagnet's net magnetization becomes zero.

Ising Model

Model of a ferromagnet in which long-range magnetic interaction between dipoles is ignored, and the assumptions that there is a preferred axis of magnetization and that each dipole can only point parallel or antiparallel to it are made.

Mean Field Approximation

The Approximation here is that at every moment, the alignments of all dipoles is "typical" - no major fluctuations that cause M to be less or more than average

The Approximation here is that at every moment, the alignments of all dipoles is "typical" - no major fluctuations that cause M to be less or more than average

Monte-Carlo Simulation

A computer simulations where a Metropolis algorithm(give each dipole a ton of opportunities to flip) is used in combination with importance sampling (probability to flip weighted on exp(-ΔU/kT) to try and model the behavior of a ferromagnet. Quite successful if done in enough complication.