• Shuffle
    Toggle On
    Toggle Off
  • Alphabetize
    Toggle On
    Toggle Off
  • Front First
    Toggle On
    Toggle Off
  • Both Sides
    Toggle On
    Toggle Off
  • Read
    Toggle On
    Toggle Off
Reading...
Front

Card Range To Study

through

image

Play button

image

Play button

image

Progress

1/29

Click to flip

Use LEFT and RIGHT arrow keys to navigate between flashcards;

Use UP and DOWN arrow keys to flip the card;

H to show hint;

A reads text to speech;

29 Cards in this Set

  • Front
  • Back
E
Energy

physical quantity that provides a measure of the state of a system
E (unit of measure)
J, joule

J = Nm

J = kg * m/2² * m
K definition
Kinetic Energy

describes motion of a system
K formula (straight line)
K = 1/2 * m * v²
K formula (rotational)
K = 1/2 ω²

where ω² is measured in rad / s
Relationship of velocity to K
K increases as the square of v

as v doubles, K quadruples
F_g
force exerted by gravity

F_g = G * (m₁ * m₂ ₂/ r²)

Force of gravity = gravitational acceleration * product of masses / square of radius
U_g
gravitational potential energy

9.8 m / s² OR 9.8 N / kg

form of energy describing interaction between an object and the earth (or a reference level)

PE stored due to relation of object to reference level
U_g formula
U_g = m g y

gravitational PE = mass * gravitational acceleration * height above reference level
U_e
elastic potential energy

energy stored in a system as a result of its deformation

ideal model is a spring
U_e formula
U_e = 1/2 k x²

where k = spring constant
Hooke's Law
F = k x

Force exerted by a spring = spring constant * length between equilibrium point and stretch/compress point
E_th
thermal energy, released as heat

energy associated with molecular motion
Heat
arises due to difference between the vibratory motion of a system's molecules relative to the molecules in the environment

occurs when T_sys != T_env
E_chem
chemical energy stored in fuel
∑E for class
∑E = K + U_g + U_e + E_th + E_chem

a system may have all or only some of these
How can E be changed?
system must interact with environment
W
work

physical quantity describing how a system interacts with its environment to produce a ∆ in ∑E_sys

written script style to differentiate between W for weight
W (algebraic formula)
W = F d cos θ

work = force applied * displacement * cos of angle between force & displacement
Work-Energy Theorem
W = ∆E

W = ∆K + ∆U_g + ∆U_e + ∆E_th + ∆E_chem
Work between system & its environment
Work done BY system
increases E of environment, decreases E of system

work done ON system
increases E of system, decreases E of environment
Law of Conservation of Total Energy
In absence of work done on/by system, ∑E remains constant
Work's relation to motion
inhibit motion < W = 0 < enhance motion
K = 1/2 m v² manipulations
v = √(2K / m)
m = 2K / v²
F_n or n
normal force

The component of a contact force exerted on an object that is perpendicular to the surface

the pressure a table exerts on a book
the pressure a ramp exerts on a wheelchair
W
weight (can also mean work, written script style in class to denote work)

W = mg

Weight = mass * gravitational acceleration
ME
mechanical energy

ME = K + U_g + U_e
Student standing on roof throws ball of m=0.5 kg vertically upward at 20 m/s at h=100 m above the ground. Neglect air resistance. Find
a. speed of impact of ball on ground (point B)
b. maximum elevation (point C)
c. total flight time
Define system to include everything

a
W=0=∆E
∆E = ∆K+∆U_g
=[(1/2 m v_B²) - (1/2 m v_A²)] + [(m g y_B) - (m g y_A)]
disregard m since it is in every term, reduce & simplify
0=(1/2 v_B²) - (1/2 (20 m/s)²) + 9.8*0 - 9.8*100

b
same equation, use points A & C, solve for y_C

c
needs kinematics
v_yf = v_yi + a_y * ∆t
solve for ∆t
∆t = (v_yf - v_yi) / a_y
If W = 0 J, and only ME exists, then
0 J = ∆K + ∆U_g + ∆U_e

since energy is never created or destroyed, only converted, ∑E_final = ∑E_initial

K_final + U_g_final + U_e_final = K_initial + U_g_initial + U_e_initial