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5 Cards in this Set

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- In order to solve this problem, simply notice that the tension in the middle rope is the only force supporting the 30lb and 40lb weights.
- The total force being supported by this middle rope is then 70lbs, which means that the tension in the rope is 70 lbs.
see above.
If something is in static equilibrium, this implies that the net force and the net torque on the beam are zero.

So would get your force equation: 60 = F1 + F2 ;
and your torque equation: 2(60)-F1-F2*4=0 (no need for denom since it'll end up canceling out with zero).
How would you go about solving this problem.
- if it's slowing down, that means its experiencing an acceleration in the opposite direction to its velocity. B/c the car is moving in a circular path, its velocity at any point will be tangential to the circle at that point.
- Take the difference between the new acceleration and the present acceleration and that would be your net acceleration.
Which vector?
- Regardless of their masses, m1 slides down faster b/c of the larger angle of inclination.
- Net force here is: mgsin(theta) - umg*cos(theta) = ma
- The time to slide down the plane only depends on this acceleration and the length of the plane.
- Recall that sin increases with increase angle while cos decreases with increased angle.
See above.
- First you want to determine the KE of the parachute and man.
- Then set this equal to the final KE of the block at the ground (since h=0 here; this will be the final speed).
- Then use equation vf^2=vi^2+2ad to solve for the distance.
How would you go about solving this problem?