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5 Cards in this Set
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**** IMPORTANT
- In order to solve this problem, simply notice that the tension in the middle rope is the only force supporting the 30lb and 40lb weights. - The total force being supported by this middle rope is then 70lbs, which means that the tension in the rope is 70 lbs. |
see above.
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If something is in static equilibrium, this implies that the net force and the net torque on the beam are zero.
So would get your force equation: 60 = F1 + F2 ; and your torque equation: 2(60)-F1-F2*4=0 (no need for denom since it'll end up canceling out with zero). |
How would you go about solving this problem.
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5;
- if it's slowing down, that means its experiencing an acceleration in the opposite direction to its velocity. B/c the car is moving in a circular path, its velocity at any point will be tangential to the circle at that point. - Take the difference between the new acceleration and the present acceleration and that would be your net acceleration. |
Which vector?
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- Regardless of their masses, m1 slides down faster b/c of the larger angle of inclination.
- Net force here is: mgsin(theta) - umg*cos(theta) = ma - The time to slide down the plane only depends on this acceleration and the length of the plane. - Recall that sin increases with increase angle while cos decreases with increased angle. |
See above.
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- First you want to determine the KE of the parachute and man.
- Then set this equal to the final KE of the block at the ground (since h=0 here; this will be the final speed). - Then use equation vf^2=vi^2+2ad to solve for the distance. |
How would you go about solving this problem?
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