Use LEFT and RIGHT arrow keys to navigate between flashcards;
Use UP and DOWN arrow keys to flip the card;
H to show hint;
A reads text to speech;
27 Cards in this Set
- Front
- Back
First-Order Processes
|
Non-saturating
Glomerular filtration, diffusion and ion trapping, active renal secretion, metabolic processes at small substrate concentrations [drug] << Km hyperbolic curve of elimination first-order region of metabolism occurs very much to left of plot, where drug conc. is low |
|
First-order Rate
|
-Kel [drug]
the higher the drug conc, the higher the rate of elimination exponential decay plot log of drug conc. vs time for a straight line analysis |
|
First order half-life
|
the fraction of the dose eliminated ina given time is independent of the dose
|
|
Rate constant of decay, 1st order
|
= .693 / t1/2
|
|
Apparent volume of distribution
|
Vd = dose / plasma conc.
|
|
Zero-order elimination
|
saturating
metabolic processes at large substrate conc. Rate of metabolism does NOT depend on amount of drug present Rate = -Kel drug conc. is decreasing As the drug conc. continues to get smaller, eventually the elimination will pass into first-order region |
|
Zero-order Graph
|
plot of drug conc. vs time is linear
No logarithms involved |
|
Generally no half-time for zero order...
|
constant amount of drug is eliminated per hour, no a constant fraction
|
|
First-order examples
|
Metoclopramide, Vancomycin
|
|
Zero-order example
|
Ethanol, Phenytoin, Salicylate
|
|
Zero-order elimination
|
the time it takes for blood level of drug to drop below an arbitrary level is directly proportional to amount ingested
processes show a conc. increase that is steep and unpredictable, does not reach a plateau |
|
Plateau Principle
|
for 1st order, the time to reach the plateau level (steady state) is determined solely by Kel
Time to reach 50% of plateau = t1/2 75% = 2t1/2 87.5% = 3t1/2 96.9% = 5t1/2 |
|
Maintenance Dose
|
dose needed to maintain steady state
|
|
Repeated Dosage
|
plateau principle holds roughly, absorption is rapid relative to elimination
|
|
Clearance
|
Cl = Kel x Vd
Inulin: Cl = 130 ml/min, measures glomerular filtration rate p-aminohippurate and penicillin: Cl = 650 ml/min, measure maximal active renal secretion |
|
Rate of Infusion
|
= Kel x Vd x [drug]ss
= Cl x [drug]ss |
|
Loading Dose
|
Vd x [drug]ss
|
|
Rate of drug eliminated
|
= Cl x [drug]ss
|
|
Maintenance Dose
|
= Cl x [drug]ss x Tm
(Tm = dose interval) |
|
Multi-compartment System
|
Thiopental
used to induce anesthesia given by IV anesthetic action of thiopental is terminated by redistribution to other tissues such as muscle, skin, fat |
|
Elimination Rate Constant
|
Kel = .693 / t1/2
|
|
[drug]ss
|
therapeutic concentration desired at steady state
|
|
Loading Dose
|
= Vd x [drug]ss
|
|
Clearance
|
Cl = Kel x Vd
|
|
Rate of Infusion = Rate of Elimination
|
= Cl x [drug]ss
= Kel x Vd x [drug]ss |
|
Dose Interval
|
= Tm
|
|
Maintenance Dose
|
= Cl x [drug]ss x Tm
|