Use LEFT and RIGHT arrow keys to navigate between flashcards;
Use UP and DOWN arrow keys to flip the card;
H to show hint;
A reads text to speech;
3 Cards in this Set
- Front
- Back
|
For molecular structure C6H12O6, calculate the unsaturation number
|
The unsaturation number is the number of unsaturated bonds (double or triple bonds) in a chemical structure. The equation is UN = {[2(carbons)+2]-[(hydrogen-nitrogen+halide]}/2 For C6H12O6, UN ={[(2x6)+2]-(12) }/2= {14-12}/2 = 2/2= 1 Therefore, there are no unsaturated bonds (double or triple bonds) in this structure |
|
|
For phenol, C6H6O, calculate the unsaturation number
|
The unsaturation number is the number of unsaturated bonds (double or triple bonds) in a chemical structure. The equation is UN = {[2(carbons)+2]-[(hydrogen-nitrogen+halide]}/2 For phenol, UN= [(2x6+2)-6]/2 =(12+2-6)/2 =8/2 = 4 Benzene rings have only 3 double bonds, but the electrons distribute a fourth double bond across the 6 carbons. ANY unsaturation number over 3 is indicative of an aromatic ring |
|
|
Which of the follow statements is not true for unsaturation number 1) any unsaturation number over 3 is indicative of an aromatic ring system 2) oxygen can neither be saturated or unsaturated as a divalent atom and is not part of the unsaturation number calculation 3) A simplified unsaturation number can be found with just carbon and nitrogen |
3) Any unsaturation number over 3 is indicative of an aromatic ring system. Oxygen can be neither saturated nor unsaturated, nor can Sulfur for that matter. For Halides, these values are equivalent to a hydrogen atom while nitrogen represents the loss of a hydrogen atom. Therefore unsaturation number can be simplified as Carbons - Hydrogen/2 +1
|
