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20 Cards in this Set
- Front
- Back
meso compound
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-a compound with two chirality centers w.the same set of four groups at each chirality center
-and when the four groups are mirror images of each other, there is a plane of symmetry. |
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enantiomers
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non-superimposable mirrored images
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configurational diastereomers
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one chirality center has the same configuration and one has a different configuration when mirrored.
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cis/trans diastereomers
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have two groups that are the same and are non-superimposable non-mirrored images
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what direction does the priority increase in R using the Cahn-Ingold-Prelog rules?
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right! rectus!
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What direction does an S stereocenter go using the Cahn-Ingold-Prelog sequence rules?
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LEFT > Sinister
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Z means....
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same!
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E means
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opposite!
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smartest thing to look for when trying to identify if meso or not...
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line of symmetry
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If told to "deduce the structure of the unknown compound" you want to find the unsaturation number...to do so you need the formula...
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2C+2-H+X-N)/2
to sex add two, take heat add X factor and take now divide |
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+HX
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breaks double bond and gives marki H and X on carbons
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+Cl2 and +Br2
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breaks double bond and gives anti addition on carbons. get X on one carbon and X on the other
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X2 with H2O present
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breaks double bond and adds marki and anti to carbons
get X on one, OH on the other, and HX is chilling on its own |
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HgOAc)2 H2O.THF
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this is oxymercuration. gives OH on one C, H on the other in Marki form
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BH3, THF
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this is hydroboration/ Oxidation. gives nonmarki Z product. H on one and OH on the other Carbon
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add CHCl3 with KOH
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breaks double bond and gives triangle of C's with two Chlorines at the top one
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add CH2I2 with Zinc and Copper
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this is a simmons, smith rxn. breaks double bond and gives triangle of C's with 2H's at the top.
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H2 with catalyst such as Pd/C or PtO2
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breaks double bond and adds to H's with syn (Z) addition
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epoxidation
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breaks double bond to give triangle where the top is an oxygen.
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when you use H3O+ in a reaction to hydroxylize by acid-catalyzed epoxide hydrolysis...
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you take the triangle with the O at the top and break it apart. you end up with two OH's on either end with anti stereochemistry
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