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20 Cards in this Set

  • Front
  • Back
meso compound
-a compound with two chirality centers w.the same set of four groups at each chirality center
-and when the four groups are mirror images of each other, there is a plane of symmetry.
enantiomers
non-superimposable mirrored images
configurational diastereomers
one chirality center has the same configuration and one has a different configuration when mirrored.
cis/trans diastereomers
have two groups that are the same and are non-superimposable non-mirrored images
what direction does the priority increase in R using the Cahn-Ingold-Prelog rules?
right! rectus!
What direction does an S stereocenter go using the Cahn-Ingold-Prelog sequence rules?
LEFT > Sinister
Z means....
same!
E means
opposite!
smartest thing to look for when trying to identify if meso or not...
line of symmetry
If told to "deduce the structure of the unknown compound" you want to find the unsaturation number...to do so you need the formula...
2C+2-H+X-N)/2

to sex add two, take heat add X factor and take now

divide
+HX
breaks double bond and gives marki H and X on carbons
+Cl2 and +Br2
breaks double bond and gives anti addition on carbons. get X on one carbon and X on the other
X2 with H2O present
breaks double bond and adds marki and anti to carbons

get X on one, OH on the other, and HX is chilling on its own
HgOAc)2 H2O.THF
this is oxymercuration. gives OH on one C, H on the other in Marki form
BH3, THF
this is hydroboration/ Oxidation. gives nonmarki Z product. H on one and OH on the other Carbon
add CHCl3 with KOH
breaks double bond and gives triangle of C's with two Chlorines at the top one
add CH2I2 with Zinc and Copper
this is a simmons, smith rxn. breaks double bond and gives triangle of C's with 2H's at the top.
H2 with catalyst such as Pd/C or PtO2
breaks double bond and adds to H's with syn (Z) addition
epoxidation
breaks double bond to give triangle where the top is an oxygen.
when you use H3O+ in a reaction to hydroxylize by acid-catalyzed epoxide hydrolysis...
you take the triangle with the O at the top and break it apart. you end up with two OH's on either end with anti stereochemistry