Use LEFT and RIGHT arrow keys to navigate between flashcards;
Use UP and DOWN arrow keys to flip the card;
H to show hint;
A reads text to speech;
18 Cards in this Set
- Front
- Back
Electrochemical Driving Force |
(Vm - EK) |
|
Ohm's Law |
IK = gK * Vm |
|
Modified Ohm's Law |
At steady state: IK = gK( Vm - EK) Because at steady state we know current is 0 and we also know the net electrochemical driving force is balanced at 0. |
|
At steady state, what is the net current of all ions? What is the net electrochemical driving force? |
They are both zero. There is no net flux of ions at a steady state |
|
gK : gNa: gCl relative conductances |
8:1:2 |
|
How do you estimate Vm with the driving force of each ion? |
|
|
Conductance (g) |
the reciprocal of resistance (R) |
|
Outward current (positive or negative?) |
= positive current |
|
Inward current is positive of negative? |
negative current |
|
Membrane potential Vm |
is the potential inside the cell measured with respect to the outside. The potential outside is defined as zero. |
|
Current (I) |
Simply defined as electrical flow. By convention, positive current is considered to flow in the direction of positive charge carriers.
|
|
Voltage |
is the electrical force of pressure that makes charge carriers move. Voltage (V or sometimes E) is also referred to as "potential". Voltage is always measured as a difference between two places |
|
Voltage (pressure) can produce current (flow) only when |
there is a conductive pathway, like an ion channel. |
|
Current is proportional to the |
voltage difference and the conductance of the pathway. This is what is stated in Ohm's law
|
|
leakage conductance |
The aggregate conductance of all channels at rest. The potassium selectivity of the leakage conductance accounts for the transmembrane voltage of the cell at rest (resting Vm) |
|
Voltage-activated _____ channels produce positive feedback and the all-or-none action potential |
Sodium |
|
When sodium channels open during an action potential, what happens to gNa? |
gNa goes up. It's the conductance, so the more open channels, the greater gNa becomes. |
|
What makes action potentials all-or-none? |
They either fire when the cell is depolarized beyond the threshold, or they do not fire if the cell is depolarized but is below threshold. For instance, if threshold is -45mV, depolarizing to -44mV will cause the voltage-gated Na channels to open, further depolarizing the cell towards Na's reversal potential. If the cell is depolarized to -46mV, the cell will not fire an action potential and will simply return to the resting Vm. |