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18 Cards in this Set

  • Front
  • Back

Electrochemical Driving Force

(Vm - EK)

Ohm's Law

IK = gK * Vm

Modified Ohm's Law

At steady state:




IK = gK( Vm - EK)




Because at steady state we know current is 0 and we also know the net electrochemical driving force is balanced at 0.

At steady state, what is the net current of all ions? What is the net electrochemical driving force?

They are both zero. There is no net flux of ions at a steady state

gK : gNa: gCl relative conductances

8:1:2

How do you estimate Vm with the driving force of each ion?

Conductance (g)

the reciprocal of resistance (R)

Outward current (positive or negative?)

= positive current

Inward current is positive of negative?

negative current

Membrane potential Vm

is the potential inside the cell measured with respect to the outside. The potential outside is defined as zero.

Current (I)

Simply defined as electrical flow. By convention, positive current is considered to flow in the direction of positive charge carriers.

Voltage

is the electrical force of pressure that makes charge carriers move. Voltage (V or sometimes E) is also referred to as "potential". Voltage is always measured as a difference between two places

Voltage (pressure) can produce current (flow) only when

there is a conductive pathway, like an ion channel.

Current is proportional to the

voltage difference and the conductance of the pathway. This is what is stated in Ohm's law



I= g*V

leakage conductance

The aggregate conductance of all channels at rest. The potassium selectivity of the leakage conductance accounts for the transmembrane voltage of the cell at rest (resting Vm)

Voltage-activated _____ channels produce positive feedback and the all-or-none action potential

Sodium

When sodium channels open during an action potential, what happens to gNa?

gNa goes up. It's the conductance, so the more open channels, the greater gNa becomes.

What makes action potentials all-or-none?

They either fire when the cell is depolarized beyond the threshold, or they do not fire if the cell is depolarized but is below threshold. For instance, if threshold is -45mV, depolarizing to -44mV will cause the voltage-gated Na channels to open, further depolarizing the cell towards Na's reversal potential. If the cell is depolarized to -46mV, the cell will not fire an action potential and will simply return to the resting Vm.