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20 Cards in this Set
- Front
- Back
Work |
W = Fd Work given in joules Or: W = Fd cosθ Angle at which the force is applied. WORK is NOT A VECTOR. Scalar. Has no direction. Work can also be found by taking the area under the curve of a force by displacement graph. |
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Kilowatt Hour |
The kilowatt-hour (symbolized kWh) is a unit of energy equivalent to one kilowatt (1 kW) of power expended for one hour. One watt is equal to 1 J/s. One kilowatt-hour is 3.6 megajoules kW x hours |
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Gravitational Potential Energy |
U = mgh Conservative force. The work done by gravity depends only on the initial and final heights, not the path the object follows. Friction is NOT a conservative force. The path taken determines the amount of work. |
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Conservation of total mechanical energy |
KEi + PEi = KEf + PEf WITH FRICTION: KEi + PEi + Work done by friction = KEf + PEf |
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Mechanical Advantage |
Gives the factor by which a mechanism multiplies the input or effort force. MA = Resistance Force / Effort Force Resistant force is the force that would be required if no machine was being used (say, you lifted a block straight up) Effort force is the force required when using a machine (lifting this same box with a pulley or on an inclined plane) |
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Efficiency |
Measures the degree to which friction and other factors reduce the actual work output of a machine from it's theoretical maximum. Say, heat is lost or friction is present. Efficiency % = Work Output / Energy Input |
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Momentum |
Is a vector quantity p = mv Can also be found by taking the area under the curve of force vs. time. |
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Impulse |
J (Do not confuse with Joules) J = N x s J = Δp = FΔt So average force applied is: F = J/Δt Units for impulse and momentum are interchangeable. N x s = Kg x m / s |
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Elastic Collision |
Total momentum and kinetic energy are conserved. m1v1 + m2v2 = m1V1 + m2V2 Only elastic unless stated or dealing with subatomic particles. |
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Inelastic Collision |
Total momentum is conserved but kinetic energy is NOT Energy is converted to heat and sound. Can also be deformed. |
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Perfectly inelastic Collision |
Objects stick together afterwards. Momentum IS convserved. Loss of kinetic energy is as great as it could possibly be. m1v1 + m2v2 = (m1 + m2)V |
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Determining whether a collision was elastic or inelastic. |
Take the initial masses and velocities and plug them into kinetic energy equations. Both before and after the collision. 1/2m1v1^2 + 1/2m2v2^2 If the same amount of energy is present in both, then kinetic energy is conserved and the collision is elastic. |
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Angular Momentum and Torque |
Angular Momentum (L) L = lmv l = length of lever arm (shortest distance between reference point and velocity. Forms a right angle) For a circle, lever arm is always equal to the radius. Remember torque: t = lF |
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Rotational Accelerations |
t = Ia a = rotational acceleration. (acceleration) I = moment of inertia. (mass) |
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Force, impulse and momentum relations |
Force equals impulse over time. F = ΔP/Δt |
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Torque, and angular momentum relations |
t = ΔL/Δt Change in angular momentum over change in time. |
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Relationship between power and force |
P = Fv
Force times velocity |
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Two object of different masses sit atop a incline. How do their potential energies and inertias compare. |
Different inertias and different potential energy. (If an object has a greater mass, it will always also have a greater inertia) |
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Normal Force of a Centripetal Accelerating Object (Like a roller coaster through a loop) |
At the top of a loop, there are two forces acting on a train. The normal force (N) and the force of gravity (mg) They both point downward, so F = N + mg Thus, N + mg =mv2 / r |
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Acceleration of a projectile considering air friction. |
The projectile experiences constant, opposing air friction the entire way. On the way up: Friction is in the same direction as gravity On the way down: Friction is in the opposite direction of gravity. Because acceleration (downward) is greater on the way up, it reaches the top of it's projectile quicker than it goes from top to bottom. (Because on the way down, there is a slight force acting upward) |