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### 39 Cards in this Set

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 nano (n) 10x -9 micro (u) 10x -6 milli (m) 10x -3 centi (c) 10x -2 kilo (k) 10x 3 mega (M) 10x 6 kinematics description of motion in terms of an object's position, velocity, and acceleration displacement 1. change in position 2. displacement = final position - initial position 3. vector: points from initial position to final 4. disregards path taken 5. magnitude is net distance traveled 4. velocity 1. tell us how fast an object's position changes 2. velocity = average velocity @ constant v 3. vector 4. magnitude is speed 5. velocity = speed + direction average velocity displacement (delta s) / time (delta t) speed 1. scalar 2. no direction average speed 1. NOT the magnitude of average velocity = (delta s / delta t) 2. total distance / time acceleration 1. tells us how fast an object's velocity changes 2. acceleration changes when EITHER speed or direction changes True or False: Object's can accelerate if speed is constant True; as long as direction is changing average acceleration 1. change in velocity/ time Scenario: ball thrown, and at the peak, v = 0. Does it accelerate at that point? Yes; v is changing direction (from positive to negative direction) so the object is accelerating when v = 0 vector a in the same direction as vector v 1. speed is increasing vector a perpendicular to vector v 1. object speed constant 2. direction of vector v changing vector a in opposite direction from vector v 1. object's speed decreasing vector a at angle between 0 and 90 degrees to vector v 1. objects speed increasing 2. direction of vector v is changing vector a at angle between 90 and 1800 degrees to vector v 1. object's speed is decreasing 2. direction of vector v is changing uniformly accelerated motion 1. a is constant 2. use "Big Five" equations The Big Five (must be uniformly accelerated ie a is constant) 1. d = 0.5(v0 + v)t 2. v = v0 + at 3. d = v0t + 0.5at^2 4. d = vt - 0.5at^2 5. v^2 = v0^2 + 2ad missing d, a constant v = v0 + at missing a, (a constant) d = 0.5(v0 + v)t missing v, a constant d = v0t + 0.5at^2 missing v0, a constant d = vt - 0.5at^2 missing t v^2 = v0^2 + 2ad position vs. time graph slope = velocity velocity vs. time graph 1. slope = acceleration 2. area under = displacement free fall 1. object moving ONLY under influence of gravity 2. g = 10 m/s2 (if thrown UP, g= -10m/s2) 3. downward acceleration projectile motion 1. experiences both horizontal and vertical (gravity) motion initial velocity of projectile motion 1. horizontal: v0x = v0 cos(u) 2. vertical: v0y = v0 sin(u) once projectile launched 1. no longer experiences horizontal acceleration (vx = v0x) 2. constant gravitational acceleration projectile motion: displacement 1. horizontal motion x = v0xt 2. vertical motion y = v0yt + 0.5gt^2 projectile motion: velocity 1. horizontal motion vx = v0x (constant!) ax = 0 2. vertical motion vy = v0y + gt ay = g (negative number) projectile motion: acceleration 1. horizontal motion v0x = v0 cos(u) 2. vertical motion v0y = v0 sin(u) range total horizontal displacement t in projectile motion time it take to get to TOP (not total time) ; must multiply t by 2 to get total time of motion