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114 Cards in this Set

  • Front
  • Back
Final Velocity
Vƒ = Vo + at
Final Velocity Squared
v^2 = V0^2 +2ad
Delta X
Vot + 1/2at^2
Newton's second Law
F = ma
Force of Gravity
Fg = Gm1m2/r^2
Centripetal Acceleration
Ac = v^2/r
Static Friction
0 <= Fs <= µsFn
Kinetic Friction
Fk = µkFn
Torque
t = rfsinΘ
Center of mass
(m1x1 + m2x2) / m1 + m2
Momentum
mv
Conservation of momentum
m1v1i +m2v2i = m1v1f + m2v2f
Potential Energy
mgh
Kinetic energy
1/2mv^2
Work
FdcosΘ
Young's Modulus
Stress/Strain

(F/A)(△L/L)
Shear Modulus
Stress over strain

(F/A)/(△x/h)
Bulk Modulus
Stress over strain

(F/A)/(△V/V)
Impulse
I = Ft = △p
Power
P = Work/Time in watts

or

IV
Hook's Law
F = -Kx
Potential energy of a spring
U = 1/2kx^2
Frequency of a spring
f = (1/2π) squareroot (k/m)
Period of spring
T = 2π squareroot(m/k)
Frequency of Pendulum
f = (1/2π)squareroot(g/l)
Period of Pendulum
2π squareroot(l/g)
Density
p = m/v
Buoyant Force
Fb = pgv

p is density of fluid, v is volume displaced
Continuity equation
A1V1 = A2V2
Bernoulli's equation
P + 1/2pv^2 +pgh = a constant

P is pressure
p is density
v is velocity
Intensity
I = P/A
Decibel System
B = 10log(I/Io)

I0 = 1 x 10^-12
Beat frequency
|f1 - f2|
Wave velocity
f X wavelength
Wave period
1/f
Frequency on string, open pipe
f = nv/2L n=1,2,3,4...
frequency on pipe that is closed
f = nv/4L n=1, 3, 5
Wavelength on string, open pipe
λ = 2L/n n=1,2,3
Wavelength on closed pipe
λ = 4L/n n=1,3,5
Doppler effect
F = f'(V +- Vd)/(V +- Vs)

V is velocity of sound, 340 m/d
Coulomb's Law
F = Kq1q2/r^2 = qE
Electric Field
E = F/q = Kq1/r^2 = V/d
Electric Potential Energy
U = Fr = Kq1q2/r = qV = qEd
Electric Potential (Voltage)
V = U/q = Kq1/r = Ed
Electric Field in between two plates
E = V/d

d = distance between two plates
Ohm's Law
V = IR
Resistance of wire
R = pL/A
Force on charge in magnetic field
F = qvbsinΘ
Force on wire in magnetic field
F = iLbsinΘ
Magnetic Field In a loop of wire
B = µoI/2r
Magnetic Field on straight .wire
B = µoI/2πr
Resistance of resistors in series
Req = R1 + R2 + R3
Resistance of resistors in parallel
1/Req = 1/R1 + 1/R2 + 1/R3
Capacitance of capacitors in series
1/C = 1/C1 + 1/C2 + 1/C3
Capacitance of capacitors in parallel
C = C1 + C2 + C3
Capacitance
C = Q/V

or, by purely physical dimensions:

C = EoA/L
AC voltage
Vmax / squareroot of 2
AC current
Imax / squareroot of 2
Binding Energy
E = mc^2
Snell's Law
n1sinΘ1 = n2sinΘ2
Index of refraction
n = c/v
Magnification
M = -i/0
total internal reflection
n1sinΘ1 = n2sin90
Image, Object, Focal Length
1/i + 1/o = 1/f = 2/r
Power of lens
P = 1/f
Energy of a photon, with work function
E = hf - w
Energy of principal quantum level for hydrogen
E = -13.6 eV/n^2

n = principle quantum number
Ideal Gas Law
PV = nRT
Dalton's Law of partial pressure
P = Pa + Pb + Pc
P = XaP + XbP + XcP
Pa = XaP
Raoults law
Pa = Xa VPa

VPa = vapor pressure of pure a
Pa = partial pressure of A in solution
Graham's Law of effusion
Va/Vb = squareroot(Mb/Ma)
Boiling Point elevation
ΔTb = Kbm

m = molality
Freezing Point Depression
ΔTf = Kfm

m = molality, but be sure to check the K for SI values
Osmotic Pressure
π = iMRT

M is molarity
pH
-log[H+]
pOH
-log[OH]
Kw
=10^-14 = [H+][OH-]
Ka
[A-][H+] / [HA]
Kb
[HB+][OH-]/B
pKa + pKb

KbKa
14

10^-14
Henderson Hassalbalch equation
pH = pka + log [conj base]/[acid]
1st law of thermo
U = Q - W
Gibbs free energy
ΔG = H - TΔS
Standard Gibbs free energy as a function of Keq
ΔG° = -RTlnKeq
Gibbs free energy in a reaction already going (no longer standard conditions)
ΔG = RTln(Q/Keq) (simplified)

ΔG = ΔG° + RTlnQ

if Q < Keq, then Q\Keq ratio is less than one, ln of decimal is negative, free energy is negative, thus spontaneous, and the reaction will proceed forward until equilibrium is reached

if Q > Keq, then ratio is more than one, and ln is positive, meaning free energy change is positive, meaning reaction will proceed in the reverse direction spontaneously (?) until the reaction is at equilibrium

If Q/Keq = 1, reaction is at equilibrium. ln of 1 is zero
Standard GFE in a cell
ΔG° = -nFE°cell
Combination of equations concerning ΔG°
ΔG° = -nFE = -RTlnKeq

nFE = RTlnKeq
Relationship between E°cell and Keq
E°cell = (RT/nF)lnKeq
E°cell
E°ox + E°red
Ecell as a function of concentrations

(Nernst equation)
Ecell = E°cell - (RT/nF)lnQ
Faraday's constant
The number of coulomb's in one mole of electrons
10^5 C per mole of electrons
eV
electron volt
the amount of energy acquired when one electron moves through one volt
A unit of energy
1 eV = 1.6 X 10-19 J
Max number of stereoisomers with n chiral centers
2^n
Hardy weinberg equations
P + q = 1
p^2 + 2pq + q^2 = 1
Number of different gamete types
2^n

n is number of heterozygous genes
STP
standard temperature and pressure
T = 273 K
P = 1 atm = 760 torr = 760 mmHg = 101 kPa
Standard state conditions
298 K
1 atm (1 barr)
1M solutions
Isolated system
Not mass nor energy can be transferred
Closed system
Mass cannot be transferred, but energy can
Open system
Both mass and energy can be transferred
standard heat of reaction
ΔH°rxn = ΔH°f products - ΔH°f reactants
Ksp for
AgCl <--> Ag+ + Cl-
[An+]^m[Bm-]^n
Ksp for MX
x^2
Ksp for MX2
4x^3
Ksp for MX3
27x^4
Ksp for M2X3
108x^5
Rate Law for

aA + bB --> cC + dD
rate = k[A]^x[B]^y

x and y are determined EXPERIMENTALLY

rate law regards the concentrations of the REACTANTS
how is k from rate law and Keq related?
Keq = kf/kr
Law of mass action

for aA + bB --> cC + dD
No matter how many steps,

Keq = [C]^c[D]^d/[A]^a[B]^b

pure solids and liquids are not included in the equilibrium expression.
Progress towards equilibrium:
1. Qc < Keq
2. Qc = Keq
3. Qc > Keq
1. Reaction has not yet reached equilibrium
2. Reaction has reached equilibrium
3. Reaction has exceeded equilibrium
Oxidation Number rules (the weird ones)
1. The oxidation number of halogens in a compound is -1, except when paired with...
2. The oxidation of hydrogen is -1 in compounds that are...
3. Oxygen has an oxidation number of -2, except when...
1. something that has a higher electronegativity. Ex: HOCl, ox number of cl is +1
2. less electronegative than hydrogen. Ex: NaH, CaH2
3. paired with F, because it is more electronegative, or in peroxides like BaO2 in which the O has a -1 oxidation state
Steps of Balancing Redox Reaction
1. Separate two half reactions
2. Balance the atoms that are NOT H and O
3. Acidic solution --> Add H2O to balance the O atoms, add H+ to balance the H atoms
Basic Solution --> Add H2O and OH-
4. Balance charges of each half reaction with electrons.
5. Multiply each reaction by some integer so that electrons for both reactions are equal
6. Add the half reactions
7. Ensure Mass and Charge is Balanced
Standard EMF
E°red + E°ox

or

E°cath - E°anode
Pascal's principle
P1 = P2

F1/A1 = F2/A2