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34 Cards in this Set

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Antiderivative
function F is antiderivative of f on an interval I if F'(x)=f(x) for all x in I
Antiderivative
F'(x) = f(x) for all x in I
Indefinite integral
All antiderivatives of f w/ respect to x
Indefinite integral
|f(x) or |F'(x)
First "n" squares
(n(n+1)(2n+1))/6

......

(Think Summation k^2)
First "n" cubes
((n(n+1))/2)^2


(Think Summation k^3)
Definite Integral
Given e>0 there exists a # d>0 such that for every partition
P= {x0, x1,... , xn} of [a,b] w/ ||P||<d and any choice ck in
[x(k-1), xk] we have
|Summation f(ck) /\xk -J|<e
Definite Integral (summed up)
J as lim-->infinity, summation:
f(ck)((b-a)/n)
/\xk
(b-a)/n
Interchangable continuous function
if a function is continuous over [a,b] then an definite integral exists and is integrable over [a,b]
Average Value
av(f)= 1/(b-a)* a|b(f(x)dx)
Mean Value Theorem
If f is continuous on [a,b], then at some point c in [a,b]:

f(c) = (1/b-a)* a|b(f(x)dx)
Fundamental Theorem of Calculus Part 1 (FTC PT1)
If f is continuous on [a,b], then F(x)=(a|x)(f(t)dt) is cont on [a,b] and differentiable on (a,b) and its derivative f(x) is
F'(x)=(d/dx)(a|x)(f(t)dt)= f(x)
FTC Part 1
F'(x)= (d/dx)(a|x)(f(t)dt)=f(x)
Fundamental Theorem of Calculus Part 2 (FTC PT2)
If f is cont on [a,b] and F is the antiderivative of f on [a,b] then

(a|b)f(x)dx = F(b)-F(a)
FTC Part2
(a|b)f(x)dx = F(b)-F(a)
Net Change
Net of a function F(x) over [a,b] is integral of its Rate of Change

F(b)-F(a) =(a|b)F'(x)dx
Rate of Change
F(b)-F(a) =(a|b)F'(x)dx
Substitution Method
If u=g(x) is a differentiable function whose range is interval I and f is cont on I then:

|(f(g(x))g'(x)dx = |f(u)du
Substitution of Definite Integral
Remember to Plug a and b values into u for new values corresponding to u!!
In the context of Riemann sums, a partition (P) of [a,b] is a set:
P = {x0, x1, x2,......,x(n-1), x(n)}
the k-th subinterval is denoted as:
[x(k-1), x(k)]
Its norm ||P|| is defined as
the largest of all subinterval widths
MVT Eqn
f(c)=(1/b-a)(a|b)(f(x)dx)
Closed Formula
summation (f(a+((b-a)/n)(i-1))/\x)
lnx =
(1|x)(1/t)dt x>0
Exponential growth and decay
y =y(o)e^(kt)
Integration by parts
|(f(x)g'(x)dx) = f(x)g(x) - |f'(x)g(x)dx
Integration by parts (short)
|u dv = uv- |vdu
sin^2(x) =
(1-cos(2x))/2
cos^2(x)=
(1+cos2x)/2
Partial Fractions method 1
factor the denominator and :

(A/(denom factor))+(B/(denom factor)
Partial Fractions method 2
If denominator is to the power of:

(A1/(x-r))+ (A2/(x-r)^2)+ .... (Am/(x-r)^m)
Partial Fractions method 3
((B1x+C)/(x^2+px+q))+....((Bnx + Cn)/(x^2+px+q)^n)