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10 Cards in this Set

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Magnitude of an impulse, in the same direction

I = mv - mu

End - start

Tension

T1 cosX = T2 cosY

Vertical tension

Mg = T1cosA + T2cosB

Force down a slope

MgsinX - Fr

Normal reaction

Mgcos X

Friction

Fr = uR

Resolving vertically

Upwards force = downwards force

Moment

Force x perp distance

Magnitude of vectors

(3i -2j) would be √3² + 2² = √13

Magnitude of an impulse, in opposite directions

mv +mu