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35 Cards in this Set

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Hat One contains 6 yellow marbles and 4 red marbles. Hat Two contains 3 yellow marbles and 3 red marbles and 4 green marbles. If I draw one marble from Hat One and one marble from Hat Two, what is the probability that I have drawn two yellow marbles? Which rule do I use?
Goal: Y and Y.
Neither draw affects the other.
Restricted conjunction rule.
6/10 x 3/10
What is the probability of getting a heads on either (or both) of two tosses of a coin? What rule do I use?
Goal: H on coin 1 or on coin 2 (or both).
Not mutually exclusive (since obviously getting a H on one coin does not mean one cannot get H on the other.)
General disjunction rule.
1/2 + 1/2 - (1/2 x 1/2) = 3/4
If the probability that a person is female is .51 and the probability that a person is red-headed is .14, what is the probability that the next person you randomly encounter will be a red-headed female? What rule do I use?
(a red-headed female is both a red-head and female)
Goal: red-headed and female.
Restricted conjunction rule.
.51 x .14
What is the probability of getting at least one six when rolling a pair of dice? [This question not about adding the two dice together.] What rule do I use?
Goal: a 6 on one die or on the other (or both).
Not mutually exclusive.
General disjunction rule.
P(6 on 1st die) + P(6 on 2nd die) - [P(6 on 1st) x P(6 on 2nd)]
= 1/6 + 1/6 - [1/6 x 1/6]
What is the probability of getting two aces from a deck of cards on two draws without replacement? What rule do I use?
Goal: Ace on first draw and ace on second draw.
The first draw affects the second draw.
General conjunction rule.
P(A1 and A2) = 4/52 x 3/51
What is the probability of drawing either a nine or a King from a deck on a single draw? What rule do I use?
Goal: either a 9 or a K.
Only one draw so the events are mutually exclusive (getting 9 precludes getting K and vice versa.
Restricted disjunction rule.
P(9 or K) = 4/52 + 4/52 = 8/52
A concert hall has ten rows of ten seats. In a random drawing for seats you are the first to draw two tickets. What is the probability of drawing two front row seats? What rule do I use?
Goal: Front row seat on 1st draw and front row on 2nd draw.
First draw affects the second.
General conjunction rule.
Pr(F1 and (F2 given F1))
= 10/100 x 9/99 = 1/110
What is the probability of getting either a three or an even number when rolling a die? What rule do I use?
Goal: 3 or even number.
It's only one roll of one die so the possibilities are mutually exclusive.
P(3 or E) = 1/6 + 3/6 = 4/6
Hat One contains 6 yellow marbles and 4 red marbles. Hat Two contains 3 yellow marbles and 3 red marbles and 4 green marbles. What if I draw one marble from Hat One and put it in my pocket, and then draw another marble from the same hat (Hat One) and put it in my pocket, and then draw a third marble from the same hat (Hat One). What is the probability that I have three yellow marbles in my pocket? Which rule do I use?
Goal: Yellow and yellow and yellow
Each draw affects the next draw.
General conjunction rule.
6/10 x 5/9 x 4/ 8
A 10-sided die (numbered 1-10) is rolled. What is the probability of getting 4 or 8? What rule do I use?
Goal: 4 or 8.
One roll so events are mutually exclusive (can't both happen).
Restricted disjunction rule.
1/10 + 1/10
What is the probability of drawing a Jack or a king from a standard deck (with one draw)? What rule do I use?
Goal: J or K.
Mutually exclusive since it is only one draw.
Restricted disjunction rule.
4/52 + 4/52 = 8/52 = 2/13
Hat One contains 6 yellow marbles and 4 red marbles. Hat Two contains 3 yellow marbles and 3 red marbles and 4 green marbles. What if I draw one marble from Hat Two and put it in my pocket, and then draw another marble from the same hat (Hat Two) and put it in my pocket. What is the probability that I have two green marbles in my pocket? Which rule do I use?
Goal: G and G.
Same hat, so the first draw affects the second.
General conjunction rule.
4/10 x 3/9
Hat One contains 6 yellow marbles and 4 red marbles. Hat Two contains 3 yellow marbles and 3 red marbles and 4 green marbles. What is the probability of drawing either a yellow marble or a red marble on a single draw from Hat One? Which rule?
Goal: Y or R.
Single draw, so if one gets Y he cannot get R and vice versa. (Mutually exclusive)
Restricted disjunction rule.
6/10 + 4/10
What's the probability of drawing a jack or a spade? What rule do I use?
Goal: J or spade.
Not mutually since there is a jack of spades in the deck.
General disjunction rule.
So, it is the P of a jack plus the P of a spade minus the P of the jack of spades (1/52).
4/52 + 13/ 52 - 1/52 = 16/52
If five of 50 tires in a tire store are in some way defective, what is the probability that four tires put on your car will all be defective? What rule do I use?
"Goal": D and D and D and D.
Not independent since each tire selected reduces the inventory.
General conjunction rule.
5/50 x 4/49 x 3/48 x 2/47
= 1/46060
In Clarajean's closet are four pairs of pants (black, white, grey, and brown), and five different shirts (blue, white, red, yellow, and purple). If she was to blindly pick a pair of pants and a shirt, what is the probability that the pants and shirt will be the same color?
Goal: same color pants and shirt = White and White.
Independent events since which pants are chosen does not affect which shirt is chosen and vice versa.
Restricted conjunction rule.
1/4 x 1/5 = 1/20 = 0.05 = 5%
Hat One contains 6 yellow marbles and 4 red marbles. Hat Two contains 3 yellow marbles and 3 red marbles and 4 green marbles. What if I draw one marble from Hat One and put it in my pocket, and then draw another marble from the same hat (Hat One) and put it in my pocket. What is the probability that I have two red marbles in my pocket? Which rule do I use?
Goal: R and R.
The first draw affects the second.
General conjunction rule.
4/10 x 3/9
A 10-sided die (numbered 1-10) is rolled. What is the probability of getting 9 or a number less than three? What rule do I use?
Goal: 9 or (1 or 2).
One roll, so events are mutually exclusive (if a 1 is rolled, the other possibilities cannot occur).
Restricted disjunction rule.
1/10 + 1/10 + 1/10 = 3/10
Hat One contains 6 yellow marbles and 4 red marbles. Hat Two contains 3 yellow marbles and 3 red marbles and 4 green marbles. What is the probability of drawing either a yellow marble or a red marble on a single draw from Hat Two? What rule do I use?
Goal: R or Y
Mutually exclusive: A single draw so if one gets R they cannot get Y and vice versa.
Restricted disjunction rule.
3/10 + 3/10
Hat One contains 6 yellow marbles and 4 red marbles. Hat Two contains 3 yellow marbles and 3 red marbles and 4 green marbles. What is the probability of drawing either a green marble or a red marble on a single draw from Hat Two? Which rule do I use?
Goal: G or R
Single draw, so if one gets G she cannot get Y and vice versa. (Mutually exclusive)
Restricted disjunction rule.
4/10 + 3/10
A 10-sided die (numbered 1-10) is rolled. What is the probability of getting 5 or an odd number? What rule do I use?
Goal: 5 or (1 or 3 or 5 or 7 or 9).
Not mutually exclusive since 5 is both a 5 and odd (notice it is listed twice).
General disjunction rule.
1/10 + 5/10 - 1/10 = 5/10
= 1/2 = 0.5 = 50%
Roll a regular 6-sided die. Find the probability of rolling a 2 or an even number. What rule do I use?
Goal: 2 or (2 or 4 or 6).
These events are inclusive (not mutually exclusive) because a 2 and an even number can happen at the same time. A 2 is an even number, so this would satisfy both.
General disjunction rule.
P(A or B) = P(A) + P(B) - P(A and B)
1/6 + 3/6 - 1/6 = 3/6 = 1/2
What is the probability of getting heads on each of three successive tosses of one coin? What rule do I use?
Goal: H and H and H.
Restricted conjunction rule.
1/2 x 1/2 x 1/2 = 1/8
What is the probability of getting at least one six on three rolls of a die?
How would I set this up to use the negation rule?
Negation rule: 1 - (prob. of NOT getting at least one 6.
1 - (prob. of getting non-6 and non-6 and non-6).
1 - (5/6 x 5/6 x 5/6)
What is the probability of getting at least one tail on three tosses of a coin? How would I set this up to use the negation rule?
Negation rule: 1 - (prob. of NOT getting at least one Tail).
1 - (getting all heads) = 1 - (H and H and H)
1 - (1/2 x 1/2 x 1/2) = 1 - 1/8 = 7/8
Assume that a person can have only one of four possible hair colors and that the probabilities of each are: black (.31); brown (.30); blond (.25); or red (deliberately unspecified). Assume that no one is bald. Assume that every person is either male or female, that sex and hair color are independent of one another, and that the probability of being female is .51. What is the probability of a red-haired male? What rule would I use?
Goal: red-haired male (a person both red-haired and male).
Restricted conjunction rule. (And using the negation rule to get the probabilities that one is red-haired and that one is male).
[ 1 - (.31 + .30 + .25)] x (1 - .51)
= .14 x .49
Hat One contains 6 yellow marbles and 4 red marbles. Hat Two contains 3 yellow marbles and 3 red marbles and 4 green marbles. What if I draw one marble from Hat Two and put it in my pocket, and then draw another marble from the same hat (Hat Two) and put it in my pocket, and then draw a third marble from the same hat (Hat Two). What is the probability that I have three red marbles in my pocket? What rule do I use?
Goal: R and R and R.
Each draw affects the next.
General conjunction rule.
3/10 x 2/9 x 1/8
Captain Omar and his ship, the H.M.S. Khan, are two furlongs from the dread pirate Ishaan and his merciless band of scallawags. The Captain has probability 1/2 of hitting the pirate ship. The pirate only has one good eye, so he hits the Captain's ship with probability 2/5.
If both fire their cannons at the same time, what is the probability that the pirate hits the Captain's ship, but the Captain misses? What rule do I use?
Goal: pirate hits and the Captain misses.
Independent events. Use negation rule to figure out chance of Captain missing if he has a 1/2 chance of hitting.
2/5 x (1 - 1/2) = 2/5 x 1/2 = 2/10 = 0.2 = 20%
If a pair of dice are rolled, what is the probability that the total points (pips, dots) add up to five? What rule do I use?
Goal: (1 and 4) or (2 and 3) or (3 and 2) or (4 and 1).
Use conjunction to figure each way of getting a five; use restricted disjunction to calculate the total probability.
(1/6x1/6) + (1/6x1/6) + (1/6x1/6) + (1/6x1/6) = 4/36
Hat One contains 6 yellow marbles and 4 red marbles. Hat Two contains 3 yellow marbles and 3 red marbles and 4 green marbles. What is the probability that drawing one marble from each hat will yield two red marbles? Which rule do I use?
Goal: Red and Red
Neither draw affects the other (independent events).
Restricted conjunction rule.
4/10 x 3/10
LeBron Asks: What are the chances of making 10 free throws in a row? Assume the probability of making each individual shot is 75%. What rule do I use?
Goal: Make the first shot and make the second and ....
Restricted conjunction rule.
See the Kahn acadamy video: https://www.khanacademy.org/math/probability/independent-dependent-probability/independent_events/v/lebron-asks-about-the-chances-of-making-10-free-throws
Assume that a person can have only one of four possible hair colors and that the probabilities of each are: black (.31); brown (.30); blond (.25); or red (deliberately unspecified). Assume that no one is bald. Assume that every person is either male or female, that sex and hair color are independent of one another, and that the probability of being female is .51. What is the probability of a person with either red or blond hair? What rule do I use?
Goal: red hair or blond.
Restricted disjunction rule, but figure red hair by negation rule.
[1 - (.31 + .30 + .25)] + .25
= .14 + .25
Tim Duncan is shooting free throws. Making or missing free throws doesn't change the probability that he will make his next one, and he makes his free throws 72% of the time.
What is the probability of Tim Duncan making ALL of his next 8 free throw attempts? What rule do I use?
Goal: Make the basket and Make and Make and ....
Restricted conjunction rule.
.72 x .72 x .72 x .72 x .72 x .72 x .72 x .72
If you flip a coin and roll a 6-sided die, what is the probability that you will flip a tails and roll less than a 6? What rule do I use?
Goal: Tails and (either a 5 or 4 or 3 or 2 or 1).
Independent events so use restricted conjunction rule, but use the disjunction rule to add up the probabilities of tossing less than a 6.
1/2 X (1/6 + 1/6 + 1/6 + 1/6 +16) = 1/2 x 5/6 = 5/12
Captain Emily and her ship, the H.M.S. Khan, are two furlongs from the dread pirate William and his merciless band of scallawags. The Captain has probability 3/8 of hitting the pirate ship. The pirate only has one good eye, so he hits the Captain's ship with probability 1/4.
If both fire their cannons at the same time, what is the probability that the Captain hits the pirate ship, but the pirate misses?
Goal: Captain Emily hits and the pirate misses.
Restricted conjunction rule, but figure the probability that the pirate misses with the negation rule.
3/8 x (1 - 1/4) = 3/8 x 3/4 = 9/32