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13 Cards in this Set
- Front
- Back
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w=
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2pi/T
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f=
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w/2pi
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y=
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Acos(w)
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v=
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-wAsin(wt)
wA = max velocity at equilibrium y = 0 0 = min velocity at y = +/- A |
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a=
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-w^2Acos(wt)
w^2A = max acceleration at y = +/-A 0 = min acceleration at equilibrium y = 0 |
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a = as a functino of displacement
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-w^2 * y
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Solve for w in terms of k
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f = a = -mw^2y
-ky = -mw^2y **w = (k/m)^1/2** |
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solve for T in terms of w
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w = (k/m)^1/2 = 2pi/T
T = 2pi (m/k)^1/2 |
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Et=
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1/2kA^2 = 1/2mv^2 + 1/2kx^2
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at equilibrium, F=
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KA - mg = 0
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if you pull the system down, F=
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K(A + y) -mg = k*(delta)y
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for a pendulum with a degree less than 15, F= and solve for k
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-mg*sintheta
-mg*theta -mg(s/L) = -ks mg/L = k |
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T (spring) =
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2pi (L/g)^1/2
comes from 2pi (m/k)^1/2, so |
