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93 Cards in this Set

  • Front
  • Back
allele
an alternative form of a gene (one member of a pair) that is located at a specific position (Locus) on a specific chromosome.
Example: Hgb A vs. Hgb S
Organisms have _____ alleles for each trait.
two
Locus
Position of a gene along a chromosome
Polymorphism
Locus that has two or more alleles that occur with appreciable frequency
Homozygous
Loci on a pair of chromosomes have identical genes
Example
O blood type (OO)‏
heterozygous
Loci on a pair of chromosomes have different genes
Example
AB blood type (A and B genes on pair of loci)‏
Phenotype
An organism's expressed traits (green or yellow). In Mendel's experiment, the F2 generation had a 3:1 phenotypic ratio of plants with green pods to plants with yellow pods
Genotype
An organism's genetic makeup (GG, Gg or gg). The genotypic ratio of the F2 generation was 1:2:1 (1GG:2Gg:1gg).
Because some alleles are dominant over others, the phenotype of an organism does not always reflect its genotype.
True or False
True
recessive phenotype
(yellow) is only expressed with the organism is homozygous recessive (gg).
A pea plant with green pods may be either ....
homozygous dominant (GG) or heterozygous (Gg).
Testcross
The breeding of an organism of unknown genotype with a homozygous recessive.
If all the progeny of the testcross have green pods...
then the green pod parent was probably homozygous dominant since a GG x gg cross produces Gg progeny.
If the progeny of the testcross contains both green and yellow phenotypes...
then the green pod parent was heterozygous since a Gg x gg cross produces Gg and gg progeny in a 1:1 ratio.
Hemophilia
is a sex-linked trait where XH gives normal blood clotting and is dominant to the hemophilia allele Xh.
Give the genotypes of:
1) a woman with normal blood clotting whose father had hemophilia
1) the woman has normal clotting so she has one XH but she got Xh from her father
Give the genotypes of:
2) a normal man whose father had hemophilia.
the man is XHY since he got the Y from his father and he is normal so must be XH
XH Xh * XH Y
each child has a 1/2 chance of being male and males have a 1/2 chance of being affected; so 1/4 chance of a child with hemophilia
If this couple has a daughter, what is the probability that the daughter will be a carrier of the hemophilia trait?
1/2 chance of being a carrier
What is the probability a daughter would have hemophilia?
0 chance that a daughter would have hemophilia
If this couple has a son, what is the probability he will have hemophilia?
1/2 chance
Who decides what proteins must be made?
Who determines the sequence of Amino Acids?
Ribosome
T-RNA
M-RNA
Pyrimidines nitrogen bases
cytosine and thymine
Purines nitrogen bases
adenine and guanine
Transcription
DNA → RNA
Translation
RNA → protein
Transcription
RNA is synthesized from the DNA template

Results in the formation of messenger RNA (mRNA)‏

mRNA moves out of the nucleus and into the cytoplasm
RNA Polymerase
An enzyme binds to the complex of transcription factors.
The RNA polymerase proceeds down one strand moving in the 3′ → 5′ direction.
Transcription
Some 50 different protein transcription factors bind to promoter sites, usually on the 5′ side of the gene to be transcribed.
Working together, they open the DNA double helix...
RNA polymerase & protien transcription factor
There is no ____ on RNA, instead you have _____
T, U pyrimidine
Purpose of RNA Polymerase
travels along the DNA strand, it assembles ribonucleotides into a strand of RNA. Each ribonucleotide is inserted into the growing RNA strand following the rules of base pairings.
What needs to be removed before the RNA polymerase does its job?
nucleosomes
Synthesis of the RNA proceeds in the
5---> 3 direction
Translation
Process by which RNA directs the synthesis of a polypeptide...Site of protein synthesis is the ribosome
The ribosome moves along the _____sequence to translate the ______________ sequence
mRNA...amino acid
tRNA contains a sequence of nucleotides ________ complementary to the triad of nucleotides on the ______ strand _______.‏
anticodon
mRNA
codon
Translation Story
The ribosome binds to mRNA at a specific area.
The ribosome starts matching tRNA anticodon sequences to the mRNA codon sequence.
Each time a new tRNA comes into the ribosome, the amino acid that it was carrying gets added to the elongating polypeptide chain.
The ribosome continues until it hits a stop sequence, then it releases the polypeptide and the mRNA.
The polypeptide forms into its native shape and starts acting as a functional protein in the cell.
DNA Replication
Untwisting and unzipping of the DNA strand
Single strand acts as a template
Complementary base pairing by DNA polymerase
Adenine-thymine; cytosine-guanine
The first major step for the DNA Replication
to take place is the breaking of hydrogen bonds between bases of the two antiparallel strands. The unwounding of the two strands is the starting point. The splitting happens in places of the chains which are rich in A-T. That is because there are only two bonds between Adenine and Thymine (there are three hydrogen bonds between Cytosine and Guanine).
Helicase
is the enzyme that splits the two strands.
origin of replication for DNA replication
The initiation point where the splitting starts is called "origin of replication".The structure that is created is known as "Replication Fork".
One of the most important steps of DNA replication is...
is the binding of RNA Primase in the initiation point of the 3'-5' parent chain.
RNA Primase
can attract RNA nucleotides which bind to the DNA nucleotides of the 3'-5' strand due to the hydrogen bonds between the bases.
RNA nucleotides are the primers (starters) for the binding of DNA nucleotides.
elongation process of DNA replication
5'-3' Template: The 3'-5' proceeding daughter strand -that uses a 5'-3' template- is called leading strand because:
DNA Polymerase can "read" the template and continuously adds nucleotides (complementary to the nucleotides of the template, for example Adenine opposite to Thymine etc).
the lagging strand
the DNA Pol I -exonuclease- reads the fragments and removes the RNA Primers.
The gaps are closed with the action of DNA Polymerase (adds complementary nucleotides to the gaps) and DNA Ligase (adds phosphate in the remaining gaps of the phosphate - sugar backbone).
semiconservative replication
Each new double helix is consisted of one old and one new chain.
Leading Strand contains
RNA Primase
DNA Polymerase III
DNA Polymerase I
Lagging Stands
RNA Primase
DNA Polymerase III
DNA Polymerase I
Ligase
Termination
Last step of DNA replication
Termination happens when...
DNA Polymerase reaches to an end of the strands.
These ends of linear (chromosomal) DNA consists of noncoding DNA that contains repeat sequences and are called telomeres.
semiconservative replication
Each new double helix is consisted of one old and one new chain.
Leading Strand contains
RNA Primase
DNA Polymerase III
DNA Polymerase I
Lagging Stands
RNA Primase
DNA Polymerase III
DNA Polymerase I
Ligase
Termination
Last step of DNA replication
Termination happens when...
DNA Polymerase reaches to an end of the strands.
These ends of linear (chromosomal) DNA consists of noncoding DNA that contains repeat sequences and are called telomeres.
Somatic cells
Contain 46 chromosomes (23 pairs)‏
Diploid cells
Gametes
Contain 23 chromosomes
Haploid cells
One member of each chromosome pair
Meiosis
Formation of haploid cells from diploid cells
Autosomes
The first 22 of the 23 pairs of chromosomes in males and females
The two members are virtually identical and thus said to be homologous
Sex chromosomes
Remaining pair of chromosomes
In females, it is a homologous pair (XX)‏
In males, it is a nonhomologous pair (XY)‏
Euploid cells
Cells that have a multiple of the normal number of chromosomes
Haploid and diploid cells are euploid forms
polyploid cell
When a euploid cell has more than the diploid number
Triploidy: a zygote having three copies of each chromosome (69)‏
Tetraploidy: four copies of each (92 total)‏
Both triploid and tetraploid fetuses don’t survive
tetraploidy
four copies of each (92 total)
Triploidy
a zygote having three copies of each chromosome (69)‏
Aneuploidy
A somatic cell that does not contain a multiple of 23 chromosomes
trisomy
A cell containing three copies of one chromosome is trisomic
Monosomy
is the presence of only one copy of any chromosome.Monosomy is often lethal, but infants can survive with trisomy of certain chromosomes
“It is better to have extra than less”
disjunction versus nondisjunction
disjunction is normal versus
Usually the cause of aneuploidy
Failure of homologous chromosomes or sister chromatids to separate normally during meiosis or mitosis
Partial trisomy
Only an extra portion of a chromosome is present in each cell
Chromosome mosaics
Trisomies occurring only in some cells of the body
Down syndrome
Best-known example of aneuploidy
Trisomy 21
1:800 live births
Mentally retarded, low nasal bridge, epicanthal folds, protruding tongue, poor muscle tone
Risk increases with maternal age
trisomy X.
This is a female that has three X chromosomes.
Termed “metafemales”
Symptoms are variable: sterility, menstrual irregularity, and/or mental retardation
Symptoms worsen with each additional X
Turner syndrome
Females with only one X chromosome
Characteristics
Absence of ovaries (sterile)‏
Short stature (~ 4'7")‏
Webbing of the neck
Edema
Underdeveloped breasts; wide nipples
High number of aborted fetuses
X is usually inherited from mother
Klinefelter syndrome
Individuals with at least two Xs and one Y chromosome
Characteristics
Male appearance
Develop female-like breasts
Small testes
Sparse body hair
Long limbs
Some individuals can be XXXY and XXXXY. The abnormalities will increase with each X.
Chromosome breakage
If a chromosome break does occur, physiological mechanisms will usually repair the break, but the breaks often heal in a way that alters the structure of the chromosome
Agents of chromosome breakage
Ionizing radiation, chemicals, and viruses
Types of Mutations
UV light
Spontaneous Mutations: Transversions
Inversions
Deletion
Duplication
Silent Mutations
Nonsense Mutations
Frameshift Mutation
Translocation
Insertion
Cri du chat syndrome
Cry of the cat”
Deletion of short arm of chromosome 5
Low birth weight, metal retardation, and microcephaly
Duplication
Presence of a repeated gene or gene sequence
Rare occurrence
Less serious consequences because better to have more genetic material than less (deletion)‏
Duplication in the same region as cri du chat causes mental retardation but no physical abnormalities
Inversions
Two breaks on a chromosome
Reversal of the gene order
Usually occurs from a breakage that gets reversed during reattachment
ABCDEFG may become ABEDCFG
Translocations
The interchanging of material between nonhomologous chromosomes
Translocation occurs when two chromosomes break and the segments are rejoined in an abnormal arrangement
Fragile sites
Fragile sites are areas on chromosomes that develop distinctive breaks or gaps when cells are cultured
No apparent relationship to disease
Fragile X syndrome
Site on the long arm of the X chromosome
Associated with mental retardation; second in occurrence to Down syndrome
Higher incidence in males because they have only one X chromosome
Single-Gene Disorders
Recurrence risk
The probability that parents of a child with a genetic disease will have yet another child with the same disease
Recurrence risk of an autosomal dominant trait
When one parent is affected by an autosomal dominant disease and the other is normal, the occurrence and recurrence risks for each child are one half
Single-Gene Disorders
Autosomal dominant disorder
Abnormal allele is dominant, normal allele is recessive, and the genes exist on a pair of autosomes
Penetrance
The percentage of individuals with a specific genotype who also express the expected phenotype
imcomplete penetrance
Individual who has the gene for a disease but does not express the disease
Retinoblastoma (eye tumor in children) demonstrates incomplete penetrance (90%)‏
Expressivity
the variation in a phenotype associated with a particular genotype
This can be caused by modifier genes
Examples of Expressivity
von Recklinghausen disease
Autosomal dominant
Long arm of chromosome #17
Disease varies from dark spots on the skin to malignant neurofibromas, scoliosis, gliomas, neuromas, etc.
Single gene disorder
Autosomal recessive disorder
Abnormal allele is recessive and a person must be homozygous for the abnormal trait to express the disease
The trait usually appears in the children, not the parents, and it affects the genders equally because it is present on a pair of autosomes
Autosomal recessive disorder recurrence risk
Single gene disorder
Recurrence risk of an autosomal dominant trait
When two parents are carriers of an autosomal recessive disease, the occurrence and recurrence risks for each child are 25%
Consanguinity
Mating of two related individuals
Dramatically increases the recurrence risk of recessive disorders
Sex-Linked Disorders
The Y chromosome contains only a few dozen genes, so most sex-linked traits are located on the X chromosome and are said to be X-linked
Sex-Linked Disorders
Sex-linked (X-linked) disorders are usually expressed by males because females have another X chromosome to mask the abnormal gene
X-linked recessive
Most X-linked disorders are recessive
Affected males cannot transmit the genes to sons, but they can to all daughters
Sons of female carriers have a 50% risk of being affected