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43 Cards in this Set

  • Front
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to find tau from plot sensor failure (saturating exponential)

dystep/dt = yss/tau



where dystep/dt = initial slope


yss = steady state y-value

to find tau from poor sensor failure (decaying exponential)

dyic/dt = -y0/tau



where dyic/dt = initial slope


y0 = initial y value

initial state of capacitor

wire

initial state of inductor

gap

final state of capacitor

gap

final state of inductor

wire

voltage divider equation -->

Vout(s) = z2 / (z1+z2) * Vin(s)

z2 =

elements after node (in impedances)

z1 =

elements before node (in impedances)

impedance of R

R

impedance of C

1/Cs

impedance of L

Ls

when t-->0, s

approaches infinity

when t-->infinity, s

approaches zero

for parallel elements in voltage divider, z =

1/((impedance a)^-1 + (impedance b)^-1))

%OS =

100 * e^ (zeta*pi/sqrt(1-zeta^2))

wnTp =

pi/(sqrt(1-zeta^2))

wn in terms of mechanical units

sqrt K/M

zeta in terms of mechanical units

1/2 * B/(sqrt K/M)

to find %OS from a plot

(y-value of peak - yss)/yss

to find Tp from a plot

time value of highest y-value

find zeta from reference curves

find corresponding zeta from %OS value

find frequency of oscillation from reference curves

given %OS or zeta, find corresponding wnTp value and solve for wn

settle time is ...

the time at which the curve settles completely within the 5% envelope

system poles:

sigma = -zeta * wn


w = wn * sqrt(1-zeta^2)

transfer function =

H(s) = X(s)/F(s)

when e^-1

=0.37


after 1 time constant, dropped 37% of initial value and is within 63% of steady state value

when e^-3

=0.05


within 5% of steady state after 3 time constants

when e^5

= 0.006


within 1% of steady state value after 5 time constants

t' =

t/tau

zeta is the..

damping coefficient


tells how much %OS there is


controls how high the resonance peak is

wn is the ...

undamped natural frequency

peak time is ...

how long it takes to get to the steady state

Tp goes to infinity as ...

zeta approaces 1

as zeta approaches 1 ....

Tp goes to infinity and %OS vanishes

small zeta values gives %OS

that approaches 100%

5% settle time criteria

wnTs = 3/zeta

phase leads come from...

high frequency

the phase of a product is

the sum of the phases

the phase of a quotient is

the difference of the phases

the phase of any complex function is

the imaginary part

if zeta is small, resonance frequency...

approaches wn

phase =

tan^-1(imaginary/real)